Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across a 500V line then-
a) Both bulbs will be fused
b) 200 W bulb will be fused
c) 100W bulb will be fused
d) No bulb will be fused
Correct answer is 'C'. Can you explain this answer?

Electrical Engineering (EE) Question

6 Answers
Preety Kumari answered May 23, 2018
A. The 100W bulb has a resistance =250×250/100=625 ohms The 200 W bulb resistance will be half above = 312.5ohms Total resistance in series - 937.5 ohms So total series current = V/R = 500/937.5 =0.533A Power dissipated in Bulb 1: I^2⋅R =( 0.533)^2×625=177.5W Power dissipated in Bulb 2 wil be half above: 88.5 W Bulb1 , a 100W unit, will eventually burnout

Arif Mohammad answered Aug 23, 2019
A should be the correct answer.

Electrical Department Gp answered Aug 18, 2019
A) should be the correct answer

Vivek Shrivastava answered 3 weeks ago
Bohot sahi! this is correct explanation!

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