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A wire of resistance 2 ohm is stretched to double it's length ,such that it's volume remains constant....what is resistance of such wire????
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A wire of resistance 2 ohm is stretched to double it's length ,such th...
if area of cross-section is constant then resistance=4 ohm.if area of cross-section is not constant resistance=8 ohm.
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A wire of resistance 2 ohm is stretched to double it's length ,such th...
Introduction
When a wire is stretched to double its length while maintaining constant volume, its resistance changes. Let's analyze how the resistance is affected.
Initial Parameters
- Resistance (R1): 2 ohms
- Length (L1): Original length of the wire
- Cross-Sectional Area (A1): Original area of the wire
- Volume (V): Constant during stretching
Volume Conservation
The volume of the wire is given by the formula:
V = L * A
Since the volume remains constant during stretching:
V1 = V2
=> L1 * A1 = L2 * A2
Given that the length is doubled (L2 = 2 * L1):
L1 * A1 = 2 * L1 * A2
=> A2 = A1 / 2
Effect on Resistance
Resistance is defined by the formula:
R = ρ * (L / A)
Where ρ is the resistivity of the material.
- Initial Resistance:
R1 = ρ * (L1 / A1) = 2 ohms
- New Resistance after stretching:
R2 = ρ * (L2 / A2)
=> R2 = ρ * (2 * L1 / (A1 / 2))
=> R2 = ρ * (4 * L1 / A1)
Thus, we can express R2 in terms of R1:
R2 = 4 * R1
Final Calculation
Substituting the initial resistance:
R2 = 4 * 2 ohms = 8 ohms
Conclusion
After stretching the wire to double its length while keeping the volume constant, the new resistance of the wire is 8 ohms.
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A wire of resistance 2 ohm is stretched to double it's length ,such that it's volume remains constant....what is resistance of such wire????
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