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Sania says to her daughter, “I was as old as you are now when you were born”. If Sania is 30 years old, then what was the age of her daughter four years ago?
  • a)
    15
  • b)
    11
  • c)
    12
  • d)
    10
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Sania says to her daughter, “I was as old as you are now when yo...
Let the age of Sania be X years and the age of her daughter be Y years.
Now according to the question,
Y = X - Y
Or 2Y = X Given that, X = 30 years So, Y = 15 years
Hence, present age of Sania’s daughter = 15 years
Therefore, age of Sania’s daughter 4 years ago = 15 - 4 = 11 years
Hence, option (b) is correct.
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Most Upvoted Answer
Sania says to her daughter, “I was as old as you are now when yo...
Explanation:

Given:
Sania is currently 30 years old.
Sania was as old as her daughter is now when her daughter was born.

Calculation:
Let's assume the current age of Sania's daughter is x years.
According to the given information, when Sania was x years old, her daughter was 0 years old.
This means there is an age gap of 30 - x years between Sania and her daughter.

Four years ago:
Four years ago, Sania's age would have been 30 - 4 = 26 years.
At that time, her daughter's age would have been x - 4 years.

Considering the age gap:
The age gap between Sania and her daughter remains the same, which is 30 - x years.
So, 26 (Sania's age four years ago) = (x - 4) (her daughter's age four years ago) + 30 - x
26 = x - 4 + 30 - x
26 = 26
This equation shows that the age gap remains consistent.

Calculating the daughter's age four years ago:
If Sania is currently 30 years old, the daughter's age four years ago can be found by substituting x = 14 into the equation.
Daughter's age four years ago = 14 - 4 = 10 years
Therefore, the age of Sania's daughter four years ago was 10 years old.
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