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If P(n) : (2n + 7) < (n + 3)2 then P(3) is
  • a)
    (2 x 3 + 7 x 3) < (3 + 3)2
  • b)
    (23 + 7) < (n + 3)2
  • c)
    (2 x 3 + 7) < (3 + 3)2
  • d)
    (32 + 7) < (2 + 7)2
Correct answer is option 'C'. Can you explain this answer?

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Answers

Mukul
May 30, 2018
Related If P(n) : (2n + 7) < (n + 3)2then P(3) isa)(2 x 3 + 7 x 3) < (3 + 3)2b)(23+ 7) < (n + 3)2c)(2 x 3 + 7) < (3 + 3)2d)(32+ 7) < (2 + 7)2Correct answer is option 'C'. Can you explain this answer?
just put n=3.. solve inside brackets using difficult concept for some people here.. called bodmas!

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New Words
Feb 19, 2022
P(n) : (2n + 7) < (n + 3)2 
P(3) = [(2(3) + 7) < (3+ 3)2

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Fiza Choudhary
Jun 11, 2018
Related If P(n) : (2n + 7) < (n + 3)2then P(3) isa)(2 x 3 + 7 x 3) < (3 + 3)2b)(23+ 7) < (n + 3)2c)(2 x 3 + 7) < (3 + 3)2d)(32+ 7) < (2 + 7)2Correct answer is option 'C'. Can you explain this answer?
Put n=3 in the equation and you will get option C

Question Description
If P(n) : (2n + 7) < (n + 3)2then P(3) isa)(2 x 3 + 7 x 3) < (3 + 3)2b)(23+ 7) < (n + 3)2c)(2 x 3 + 7) < (3 + 3)2d)(32+ 7) < (2 + 7)2Correct answer is option 'C'. Can you explain this answer? for JEE 2022 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If P(n) : (2n + 7) < (n + 3)2then P(3) isa)(2 x 3 + 7 x 3) < (3 + 3)2b)(23+ 7) < (n + 3)2c)(2 x 3 + 7) < (3 + 3)2d)(32+ 7) < (2 + 7)2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2022 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If P(n) : (2n + 7) < (n + 3)2then P(3) isa)(2 x 3 + 7 x 3) < (3 + 3)2b)(23+ 7) < (n + 3)2c)(2 x 3 + 7) < (3 + 3)2d)(32+ 7) < (2 + 7)2Correct answer is option 'C'. Can you explain this answer?.
Solutions for If P(n) : (2n + 7) < (n + 3)2then P(3) isa)(2 x 3 + 7 x 3) < (3 + 3)2b)(23+ 7) < (n + 3)2c)(2 x 3 + 7) < (3 + 3)2d)(32+ 7) < (2 + 7)2Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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just put n=3.. solve inside brackets using difficult concept for some people here.. called bodmas!