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Acetaldehyde cannot exhibit
- a)Iodoform test
- b)Luca's test
- c)Benedict's test
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Acetaldehyde cannot exhibita)Iodoform testb)Lucas testc)Benedicts test...
Explanation:
Lucas Test:
- Acetaldehyde can exhibit Lucas test.
- Lucas reagent is a mixture of anhydrous ZnCl2 and HCl, which is used to distinguish between primary, secondary, and tertiary alcohols based on their reactivity.
- Acetaldehyde, being a primary alcohol, reacts with Lucas reagent to form a cloudy solution within a few minutes, indicating a positive result.
Iodoform Test:
- Acetaldehyde cannot exhibit the iodoform test.
- The iodoform test is used to detect the presence of methyl ketones or alcohols containing the CH3CO- group.
- Acetaldehyde does not have the necessary functional group to react with iodine and hydroxide to form a yellow precipitate of iodoform.
Benedict's Test:
- Acetaldehyde can exhibit Benedict's test.
- Benedict's reagent is used to test for the presence of reducing sugars like aldehydes and some ketones.
- Acetaldehyde, being an aldehyde, can reduce the copper (II) ions in Benedict's reagent to form a red precipitate of copper (I) oxide.
Therefore, the correct answer is option B. Lucas test because acetaldehyde can exhibit both Lucas test and Benedict's test, but not the iodoform test.
Lucas Test:
- Acetaldehyde can exhibit Lucas test.
- Lucas reagent is a mixture of anhydrous ZnCl2 and HCl, which is used to distinguish between primary, secondary, and tertiary alcohols based on their reactivity.
- Acetaldehyde, being a primary alcohol, reacts with Lucas reagent to form a cloudy solution within a few minutes, indicating a positive result.
Iodoform Test:
- Acetaldehyde cannot exhibit the iodoform test.
- The iodoform test is used to detect the presence of methyl ketones or alcohols containing the CH3CO- group.
- Acetaldehyde does not have the necessary functional group to react with iodine and hydroxide to form a yellow precipitate of iodoform.
Benedict's Test:
- Acetaldehyde can exhibit Benedict's test.
- Benedict's reagent is used to test for the presence of reducing sugars like aldehydes and some ketones.
- Acetaldehyde, being an aldehyde, can reduce the copper (II) ions in Benedict's reagent to form a red precipitate of copper (I) oxide.
Therefore, the correct answer is option B. Lucas test because acetaldehyde can exhibit both Lucas test and Benedict's test, but not the iodoform test.
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Acetaldehyde cannot exhibita)Iodoform testb)Lucas testc)Benedicts testd)None of theseCorrect answer is option 'B'. Can you explain this answer?
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