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A body starts to slide over a horizontal surface with an initial velocity of 0.2 m/s. Due to friction, its velocity decreases at the rate of 0.02 m/s2. How much time will it take for the body to stop?
  • a)
    10 s
  • b)
    15s
  • c)
    1s
  • d)
    5s
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A body starts to slide over a horizontal surface with an initial veloc...
Initial velocity, u = 0.2 m/s. 
Final velocity, v = 0 
Acceleration, a = 0.02 m/s^2.
v = u + at 
0 = 0.2 - 0.02 x t
0.02 x t = 0.2 
t = 0.2/0.02 = 10 sec.
Thus, the body will take 10 seconds to stop.
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Community Answer
A body starts to slide over a horizontal surface with an initial veloc...
Given data:
Initial velocity (u) = 0.2 m/s
Deceleration (a) = -0.02 m/s² (negative because it is opposite to the direction of motion)
Final velocity (v) = 0 m/s (when the body stops)

We need to find the time taken (t) for the body to stop.

Using the formula of motion:
v = u + at
0 = 0.2 - 0.02t
0.02t = 0.2
t = 10 seconds

Therefore, it will take 10 seconds for the body to stop.

HTML Answer:
Formula Used:
v = u + at

Given:
Initial velocity (u) = 0.2 m/s
Deceleration (a) = -0.02 m/s²
Final velocity (v) = 0 m/s

Solution:
0 = 0.2 - 0.02t
0.02t = 0.2
t = 10 seconds

Answer:
It will take 10 seconds for the body to stop.
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