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A force F acts on a stationary body for the time t. The distance covered by the body 'S' will be proportional to:
- a)t
- b)1/t
- c)t2
- d)1/t2
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A force F acts on a stationary body for the time t. The distance cover...
S=ut+1/2at^2 Since the mass is constant, and i guess you dont mean above to be dealt in relativistic speed, and a constant force is applied then we will have constant acceleration. So distance covered will be only dependent on elapsed time t.So s ∝ t^2
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A force F acts on a stationary body for the time t. The distance cover...
We are said that a Force F acts on a stationary body for time t.
Since a constant Force is acting, the body has constant acceleration for time t. In other words, the motion of body is uniformly accelerated for time t.
If the mass of the body is m, then we have. F= ma
a=F/m
Thus, an acceleration a acts on the body for time t. Now we can find the distance s covered by the body in this time.
Also, the body was initially stationary. So initial velocity is zero.
We use the following equation of motion:
s=ut+/at^2
s=(0)t +1/2×F/M×t^2 s= F/2m×t^2. s proportinal to t^2
Since a constant Force is acting, the body has constant acceleration for time t. In other words, the motion of body is uniformly accelerated for time t.
If the mass of the body is m, then we have. F= ma
a=F/m
Thus, an acceleration a acts on the body for time t. Now we can find the distance s covered by the body in this time.
Also, the body was initially stationary. So initial velocity is zero.
We use the following equation of motion:
s=ut+/at^2
s=(0)t +1/2×F/M×t^2 s= F/2m×t^2. s proportinal to t^2
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