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The age of a person is twice the sum of ages of his two sons and five years ago his age was thrice the sum of their ages .fing his present age?
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The age of a person is twice the sum of ages of his two sons and five ...
Problem Analysis:
The problem provides information about the relationship between a person's age and the ages of his two sons. By setting up equations based on the given conditions, we can solve for the person's present age.

Given Information:
Let the person's age be P and the ages of his two sons be S1 and S2.
According to the problem:
1. P = 2(S1 + S2)
2. P - 5 = 3(S1 + S2)

Solution:
1. Substitute the first equation into the second equation:
2(S1 + S2) - 5 = 3(S1 + S2)
2S1 + 2S2 - 5 = 3S1 + 3S2
2S1 + 2S2 - 3S1 - 3S2 = 5
-S1 - S2 = 5
2. Substitute S1 = P/2 - S2 into the above equation:
-(P/2 - S2) - S2 = 5
-P/2 + S2 - S2 = 5
-P/2 - 2S2 = 5
-P - 4S2 = 10
P = 10 + 4S2
3. Since P = 2(S1 + S2), substitute P = 10 + 4S2 into this equation:
10 + 4S2 = 2(S1 + S2)
10 + 4S2 = 2(S1) + 2(10 - S1)
10 + 4S2 = 2S1 + 20 - 2S1
4S2 = 10
S2 = 10/4 = 2.5
4. Substitute S2 = 2.5 into P = 10 + 4S2:
P = 10 + 4(2.5)
P = 10 + 10
P = 20
Therefore, the person's present age is 20 years old.
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The age of a person is twice the sum of ages of his two sons and five years ago his age was thrice the sum of their ages .fing his present age?
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