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The zero of the polynomial (x−2)2−(x+2)2 is
  • a)
    1
  • b)
    -2
  • c)
    2
  • d)
    0
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The zero of the polynomial(x−2)2−(x+2)2isa)1b)-2c)2d)0Corr...
use factor theorem as x+2 is factor of
x³-2ax²+16 so put x = -2 and equate the equation to 0
so putting x = -2
(-2)³-2a(-2)²+16 =0
-8-8a+16=0
-8a = -8
a = 8/8= 1
So,
a = 1
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Most Upvoted Answer
The zero of the polynomial(x−2)2−(x+2)2isa)1b)-2c)2d)0Corr...
{(x)² + (2)² - 2× x ×2} - {(x)² + (2)² + 2 × x×2} = (x² + 4 - 4x) - (x² + 4 + 4x) = x² + 4 - 4x - x²- 4 - 4x = 0.........ans
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Community Answer
The zero of the polynomial(x−2)2−(x+2)2isa)1b)-2c)2d)0Corr...
use factor theorem as x+2 is factor of
x³-2ax²+16 so put x = -2 and equate the equation to 0
so putting x = -2
(-2)³-2a(-2)²+16 =0
-8-8a+16=0
-8a = -8
a = 8/8= 1
So,
a = 1
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