Req =  ?
  • a)
    11.86 Ω 
  • b)
    10 Ω
  • c)
    25 Ω 
  • d)
    11.18 Ω
Correct answer is option 'D'. Can you explain this answer?

Electrical Engineering (EE) Question

5 Answers
Suyash Dewangan answered Aug 18, 2018
It is wrong I saw the solution and I found that it has been solved taking 5 ohm resistor....

Balwinder Singh answered Feb 23, 2020
We infer from the given diagram that the same pattern is followed after every 10ohm resistor. The infinite pattern in parallel as a whole is considered as to be Rx.
Thus, Rx = R + (R||Rx)
Solving for Rx, we get Rx = 1.62R, where R=10ohm.
So we have Rx = (1.62ohm)*(10ohm), which gives Rx=16.2ohm
Therefore, Req = 5 + (10||16.2)
=> 5 + [(10*16.2)/(10+16.2)] => Req = 5 + (162/26.2) which gives Req=11.18 ohm.

Krishna Pal Thakur answered Jan 30, 2020
Initial register is of 5 ohm

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