A sewer is laid from a manhole A to a manhole B, 250 m away along a gradient of 1 in 125. If the reduced level of the invert at A is 205.75 m and the height of the boning rod is 3 m, the reduced level of the sight rail at B, is
  • a)
    208.75 m
  • b)
    202.75 m
  • c)
    206.75 m
  • d)
    211.75 m
Correct answer is option 'C'. Can you explain this answer?
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Civil Engineering (CE) Question

Pushkar Malik
Jun 11, 2018
205.75 - 1 * 205/125 = 203.75,
203.75 + 3 = 206.75.

Pankaj Gupta
Jul 30, 2018
(205.75-1*250/125)+3=206.75

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