If x and y are positive integers and x is odd...
If x and y are positive integers and x is odd, is xy even?
(1) x3y = 6a3 + 23 where a is a positive integer
(2) x2+y = 3k + 7 where k is a positive integer
• a)
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.
• b)
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.
• c)
BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.
• d)
• e)
Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.

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 Hemalatha Valishvaran Jan 25, 2019
Because, the first statement is odd and second statement is even. So, the A option is correct answer.

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 Rishav Pandey Jul 30, 2019
If you start putting in some positive integer values in a of the 1st equation you will find that all resultant numbers are odd, which can only be if y is odd and if y is also odd than xy is odd, so choice A is right.

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