The most acidic species is:- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
Related Test: Test: Heterocyclic- 1
The most acidic species is:
a)
b)
c)
d)
Chemistry Question
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B is anti aromatic, so maximum acidic .moreover after losing Proton it will become aromatic so highly acidic
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B is not antiaromatic .B is non aromatic bt after de protonation it will aromatic so it is most acidic
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It is antiaromatic and on losing a proton the nitrogen will have no positive charge left on it making it more stable. So it can easily donate proton in comparison to any other compound of other options.
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Compound c &d are already aromatic..so after losing proton they will not get any extra stability,but compound b is antiaromatic so after losing proton it will get stability as it becomes aromatic..on the other hand compound a also don't get any stability after losing proton like compound b..thus compound b is most acidic
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B as acidity of a acid is directly propotional to stability of its conjugate base and in cause of b conjugate base foelrm will be aromatic
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After removal of H b c d becomes aromatic ..but we know that pyrrol is aromatic than pyridine ...hence b is right ans
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NH2 is electron releasing group.so resonance passibilities is high. So it is more acidic than others.
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On removing proron from (b) it becomes atomatic which is most stable therefore it is most acidic.
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Initially 'B' is antiaromatic due to absence of lone pair on N. On loosing the 'proton', the N takes up the bonding electrons and thus the conjugate base becomes more stable due to gaining of aromaticity by becoming a 6 pi electron system.
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With releasing hydrogen,the compound is become neutral & then the lone pair of nitrogen is participate in resonance & .The compound is become aromatic and increase the stability
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B after releasing one proton will get aromatic pyrrole ring where the lone pair of nitrogen involved in conjugation.for c&d no need of N lone pair for arometicity.
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Since nitrogen has postive charge and there is resonance possible due to pie bond in the ring and there is no Me group to increase tha + I effect so this is most acidic among these
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In option B, after protonation the compound will be aromatic,the lone pair of 'N' atom wii praticipate in resonance,so,'B'is right answer
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We have to see it's conjugate base stability so, b is correct due to conjugation of its conjugate base, becomes aromatic compound
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After deprotonation, the conjugate base will gain aromaticity i.e. it will pyrrole. So as it gain extra stability ,so it will be most acidic.
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Explanation -(b)
Ring size is smaller having sp2 carbon atoms which increases the acidity.
Ring size is smaller having sp2 carbon atoms which increases the acidity.
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