The most acidic species is:
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?
Related Test: Test: Heterocyclic- 1

Chemistry Question

By Esra Joy · Oct 24, 2018 ·Chemistry
18 Answers
Sarthak Rajendra Bande answered Oct 24, 2018
B is anti aromatic, so maximum acidic .moreover after losing Proton it will become aromatic so highly acidic

Satyabrata answered Oct 25, 2018
B is not antiaromatic .B is non aromatic bt after de protonation it will aromatic so it is most acidic

Tanuja Srivastava answered Nov 18, 2018
It is antiaromatic and on losing a proton the nitrogen will have no positive charge left on it making it more stable. So it can easily donate proton in comparison to any other compound of other options.

Tarpan Maiti answered Nov 25, 2018
Compound c &d are already aromatic..so after losing proton they will not get any extra stability,but compound b is antiaromatic so after losing proton it will get stability as it becomes aromatic..on the other hand compound a also don't get any stability after losing proton like compound b..thus compound b is most acidic

Manchanda Goyal answered Nov 17, 2018
B as acidity of a acid is directly propotional to stability of its conjugate base and in cause of b conjugate base foelrm will be aromatic

Gaurav Singh answered Nov 17, 2018
After removal of H b c d becomes aromatic ..but we know that pyrrol is aromatic than pyridine ...hence b is right ans

Sacratees P99 answered Nov 22, 2018
NH2 is electron releasing group.so resonance passibilities is high. So it is more acidic than others.

Avinash Kumar answered Nov 25, 2018
On removing proron from (b) it becomes atomatic which is most stable therefore it is most acidic.

Asmita Goswami answered Sep 22, 2019
Initially 'B' is antiaromatic due to absence of lone pair on N. On loosing the 'proton', the N takes up the bonding electrons and thus the conjugate base becomes more stable due to gaining of aromaticity by becoming a 6 pi electron system.

Avijit Mandal answered Dec 02, 2019
With releasing hydrogen,the compound is become neutral & then the lone pair of nitrogen is participate in resonance & .The compound is become aromatic and increase the stability

Gunjan Sharma answered Nov 21, 2018
The conjugate base of option b became pyrrole and it is a stable species

Md Irshad Hussain answered Sep 20, 2019
B is a non aromatic compounds because N-atoms is not a planar

Aradhana Sharma answered Apr 20, 2019
Since nitrogen has postive charge and there is resonance possible due to pie bond in the ring and there is no Me group to increase tha + I effect so this is most acidic among these

Arup Guria answered Dec 26, 2018
B after releasing one proton will get aromatic pyrrole ring where the lone pair of nitrogen involved in conjugation.for c&d no need of N lone pair for arometicity.

Sudipta Pahari answered Mar 01, 2019
In option B, after protonation the compound will be aromatic,the lone pair of 'N' atom wii praticipate in resonance,so,'B'is right answer

Ajay Ajay answered Apr 26, 2019
We have to see it's conjugate base stability so, b is correct due to conjugation of its conjugate base, becomes aromatic compound

Mangish Ghosh answered Sep 20, 2019
After deprotonation, the conjugate base will gain aromaticity i.e. it will pyrrole. So as it gain extra stability ,so it will be most acidic.

Uttra Rawat answered Jun 02, 2019
Explanation -(b)
Ring size is smaller having sp2 carbon atoms which increases the acidity.

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