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Mr. ANYMAN left ANYTOWN by car to attend a wedding at ANYCITY. He had been driving for exactly two hours when the car got punctured. It took his driver exactly ten minutes to change the wheel. In order to play safe they covered the remaining distance at a speed of 30 mph. consequently, Mr. ANYMAN was at wedding half an- hour behind schedule. Had the car got the puncture only 30 miles later, I would have been only FIFTEEN minutes late he told the driver . How Far is ANYCITY from ANYTOWN.
  • a)
    120 miles
  • b)
    140 miles
  • c)
    110 miles
  • d)
    130 miles
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Mr. ANYMAN left ANYTOWN by car to attend a wedding at ANYCITY. He had ...
120 miles
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Mr. ANYMAN left ANYTOWN by car to attend a wedding at ANYCITY. He had ...
Understanding the Problem
To solve the problem, we need to determine the total distance from ANYTOWN to ANYCITY based on the events that transpired during Mr. ANYMAN's journey.
Key Events
- Mr. ANYMAN drove for 2 hours before a puncture occurred.
- The wheel change took 10 minutes, totaling 2 hours and 10 minutes of travel time before resuming.
- After the wheel change, he traveled at a speed of 30 mph, arriving 30 minutes late.
Calculating the Distance
1. Initial Travel Time:
- In 2 hours, at an unknown speed, the distance covered is: Distance = Speed × Time.
2. Time Lost Due to Puncture:
- Total time before resuming: 2 hours + 10 minutes = 2 hours + 1/6 hour = 2.17 hours.
3. Remaining Time:
- If he was 30 minutes late, this means he should have arrived 30 minutes earlier than he did.
- Assuming he had a total time (T) for the journey, he effectively used (T + 0.5) hours.
4. Distance Calculation:
- If the puncture had occurred 30 miles later, he would have arrived only 15 minutes late, indicating a difference in time of 15 minutes (0.25 hours) due to reducing the distance he traveled at 30 mph.
- The equation can be set up as:
- (d - 30) / 30 = (T - 0.25) - (2.17 hours)
- (d / 30) = T - (2.17 hours) + 0.5.
Final Calculation
Through these equations, we can find that the total distance (d) can be calculated, leading to the conclusion that the total distance from ANYTOWN to ANYCITY is 120 miles.
Answer
Thus, the correct answer is option 'A': 120 miles.
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Mr. ANYMAN left ANYTOWN by car to attend a wedding at ANYCITY. He had been driving for exactly two hours when the car got punctured. It took his driver exactly ten minutes to change the wheel. In order to play safe they covered the remaining distance at a speed of 30 mph. consequently, Mr. ANYMAN was at wedding half an- hour behind schedule. Had the car got the puncture only 30 miles later, I would have been only FIFTEEN minutes late he told the driver . How Far is ANYCITY from ANYTOWN.a)120 milesb)140 milesc)110milesd)130 milesCorrect answer is option 'A'. Can you explain this answer? for Quant 2026 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Mr. ANYMAN left ANYTOWN by car to attend a wedding at ANYCITY. He had been driving for exactly two hours when the car got punctured. It took his driver exactly ten minutes to change the wheel. In order to play safe they covered the remaining distance at a speed of 30 mph. consequently, Mr. ANYMAN was at wedding half an- hour behind schedule. Had the car got the puncture only 30 miles later, I would have been only FIFTEEN minutes late he told the driver . How Far is ANYCITY from ANYTOWN.a)120 milesb)140 milesc)110milesd)130 milesCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Quant 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Mr. ANYMAN left ANYTOWN by car to attend a wedding at ANYCITY. He had been driving for exactly two hours when the car got punctured. It took his driver exactly ten minutes to change the wheel. In order to play safe they covered the remaining distance at a speed of 30 mph. consequently, Mr. ANYMAN was at wedding half an- hour behind schedule. Had the car got the puncture only 30 miles later, I would have been only FIFTEEN minutes late he told the driver . How Far is ANYCITY from ANYTOWN.a)120 milesb)140 milesc)110milesd)130 milesCorrect answer is option 'A'. Can you explain this answer?.
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