The displacement of the body in 5 seconds from the beginning of the mo...
Displacement = Area under the velocity- time graph the slope till 5 cm
the slope is a straight line and thus its area will be equal to the area of the triangle with height = 20 and base = 5
Area of triangle = 1/2 x base x height
Area = 1/2 x 5 x 20 = 50 m.
The displacement of the body in 5 seconds from the beginning of the mo...
To find the displacement of the body in the first 5 seconds, we need to calculate the area under the velocity-time graph. In this case, the area forms a triangle.
The formula for the area of a triangle is:
Area = \frac{1}{2} \times \text{base} \times \text{height}
From the graph:
* The base of the triangle (time) is 5 seconds.
* The height of the triangle (velocity) is 20 m/s.
Plugging these values into the formula:
Area = \frac{1}{2} \times 5 \, \text{s} \times 20 \, \text{m/s}
Area = \frac{1}{2} \times 100 \, \text{m}
Area = 50 \, \text{m}
Therefore, the displacement of the body in the first 5 seconds is 50 meters.