The number of degenerate orbitals in an energy level of H-atom having E_{n}= -R_{H}/9, where R_{H }is Rydberg and 1 RH = 2.18 x 10^{–18} J is

- a)5
- b)9
- c)6
- d)3

Correct answer is option 'B'. Can you explain this answer?

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Syed Mehmood
answered
Nov 21, 2018

E=-2.18*10^-18(Z/n)^2

So energy is -Rh/9=-2.18*10^-18/9

z=1 for H

solving we get n=3

degenerate orbital means orbital having same energy.

Now subshell in shell 3 are 3s 3p 3d.

so total orbital is:

s=1

p=3

d=5

total=9

So energy is -Rh/9=-2.18*10^-18/9

z=1 for H

solving we get n=3

degenerate orbital means orbital having same energy.

Now subshell in shell 3 are 3s 3p 3d.

so total orbital is:

s=1

p=3

d=5

total=9

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