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A tap can fill storage in 8 hours and another tap can discharge it in 16 hours. In the event that both the taps are open, the time taken to fill the tank will be:
  • a)
    8 hours
  • b)
    10 hours
  • c)
    16 hours
  • d)
    24 hours
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A tap can fill storage in 8 hours and another tap can discharge it in ...
Net part filled in 1 hr = (1/8 ? 1/16) = 1/16
Total time taken to fill the tank = 16 hrs.
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Community Answer
A tap can fill storage in 8 hours and another tap can discharge it in ...
Understanding the Problem
In this scenario, we have two taps: one that fills a tank and another that empties it.
Details of the Taps
- Filling Tap: Fills the tank in 8 hours.
- Discharging Tap: Empties the tank in 16 hours.
Calculating Rates of Work
- Filling Rate: The filling tap can fill 1 tank in 8 hours, which means it fills 1/8 of the tank in one hour.
- Discharging Rate: The discharging tap can empty 1 tank in 16 hours, meaning it empties 1/16 of the tank in one hour.
Combined Rate of Work
To find the combined effect of both taps working together, we add their rates:
- Net Filling Rate = Filling Rate - Discharging Rate
- Net Filling Rate = 1/8 - 1/16
Finding a Common Denominator
To perform this operation, we convert the fractions:
- 1/8 = 2/16
Now we can subtract:
- Net Filling Rate = 2/16 - 1/16 = 1/16
Time Taken to Fill the Tank
To find the time taken to fill the tank when both taps are open:
- If the net filling rate is 1/16 of the tank per hour, it will take 16 hours to fill 1 full tank.
Final Conclusion
Thus, when both taps are open, the time taken to fill the tank is 16 hours, confirming that option 'C' is correct.
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