A real and odd periodic signal x[n] has fundamental period N = 7 and FS coefficients X [k]. Given that X [15] = j, X [16] = 2j, X [17] = 3j. The values of X [0],X [-1], X [-2], and X [ -3] will be
  • a)
    0, j,2j, 3j
  • b)
    1, -1, -2, -3
  • c)
    1, 1, 2, 3
  • d)
    0,  -j , -2 j, -3 j
Correct answer is option 'D'. Can you explain this answer?

Electronics and Communication Engineering (ECE) Question

Subhash Chand
Feb 18, 2020
Since the FS coefficient repeat every N. Thus
X[1] = X[15], X[2] = X[16], X[3] = X[17]
The signal real and odd, the FS coefficient X[k] will be purely imaginary and odd. Therefore X[0] = 0 X[-1] = -X[1], X[-2] = -X[2], X[-3]  = -X[-3]
Therefore (D) is correct option.

This discussion on A real and odd periodic signal x[n] has fundamental period N = 7 and FS coefficients X [k]. Given that X [15] = j, X [16] =2j, X [17] = 3j. The values of X [0],X [-1], X [-2], and X [-3] will bea)0, j,2j, 3jb)1, -1, -2, -3c)1,1,2,3d)0, -j , -2 j, -3 jCorrect answer is option 'D'. Can you explain this answer? is done on EduRev Study Group by Electronics and Communication Engineering (ECE) Students. The Questions and Answers of A real and odd periodic signal x[n] has fundamental period N = 7 and FS coefficients X [k]. Given that X [15] = j, X [16] =2j, X [17] = 3j. The values of X [0],X [-1], X [-2], and X [-3] will bea)0, j,2j, 3jb)1, -1, -2, -3c)1,1,2,3d)0, -j , -2 j, -3 jCorrect answer is option 'D'. Can you explain this answer? are solved by group of students and teacher of Electronics and Communication Engineering (ECE), which is also the largest student community of Electronics and Communication Engineering (ECE). If the answer is not available please wait for a while and a community member will probably answer this soon. You can study other questions, MCQs, videos and tests for Electronics and Communication Engineering (ECE) on EduRev and even discuss your questions like A real and odd periodic signal x[n] has fundamental period N = 7 and FS coefficients X [k]. Given that X [15] = j, X [16] =2j, X [17] = 3j. The values of X [0],X [-1], X [-2], and X [-3] will bea)0, j,2j, 3jb)1, -1, -2, -3c)1,1,2,3d)0, -j , -2 j, -3 jCorrect answer is option 'D'. Can you explain this answer? over here on EduRev! Apart from being the largest Electronics and Communication Engineering (ECE) community, EduRev has the largest solved Question bank for Electronics and Communication Engineering (ECE).