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Plz give 5 example of oxidation and reduction.?
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Plz give 5 example of oxidation and reduction.?
Oxidation Reaction
Oxidation reactions can be defined in terms of addition of oxygen or the removal of hydrogen. There are a number of reactions in which oxygen is added, or in which hydrogen is removed.

Examples: Addition of Oxygen:

(a). CuO(s) + H2(g) → Cu(s) + H2O(l)

CuO adds oxygen to H2;  CuO is therefore the oxidizing agent or oxidant, it oxidizes the H2 to H2O.

(b). C(s) + H2O(g) → H2(g) + CO(g)

H2O is the oxidizing agent; it gives oxygen to carbon, which is oxidized to CO.

Removal of Hydrogen:

(a). H2S(g) + Cl2(g) → 2HCl(g) + S(s)

Chlorine is the oxidant, it removes hydrogen from H2S, thereby oxidizing it to sulphur.

(b). 2H2O(l) + 2F2(g) → 4HF(aq) + O2(g)

Fluorine removes hydrogen from the water, therefore, fluorine is the oxidant. The water is oxidized to oxygen.

Reduction Reaction
Reduction reactions can be defined as reactions that involve the removal of oxygen or the addition of hydrogen.

Example, Removal of Oxygen:

(a). CuO(s) + H2(g) → Cu(s) + H2O(l)

Hydrogen removes oxygen from CuO, thereby reducing it to Cu. Hydrogen is therefore the reducing agent or reductant.

(b). H2O(g) + C(s) → H2(g) + CO(g)

Carbon is the reductant, it removes oxygen from steam, thereby reducing it to hydrogen.

Addition of Hydrogen:

(a). H2S(g) + Cl2(g) → 2HCl(g) + S(s)

H2S adds hydrogen to Cl2(g). H2S is the reducing agent. It reduces Cl2(g) to HCl(g).

(b). 2H2O(l) + 2F2(g) → 4HF(aq) + O2(g)

H2O here adds hydrogen to F2, thereby reducing it to HF. H2O is the reductant in this reaction.
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Plz give 5 example of oxidation and reduction.?
Examples of Oxidation and Reduction:

1. Oxidation of Iron:
Iron can undergo oxidation when exposed to oxygen in the presence of moisture, forming iron oxide or rust. The process can be represented as follows:
4 Fe + 3 O₂ → 2 Fe₂O₃
In this reaction, the iron atoms lose electrons, resulting in an increase in their oxidation state from 0 to +3. Hence, this is an example of oxidation.

2. Reduction of Copper Oxide:
Copper oxide can be reduced to copper metal by heating it with hydrogen gas. The reaction can be represented as follows:
CuO + H₂ → Cu + H₂O
In this reaction, the copper atoms gain electrons, resulting in a decrease in their oxidation state from +2 to 0. Therefore, this process is an example of reduction.

3. Oxidation of Hydrogen Peroxide:
Hydrogen peroxide can undergo self-oxidation in the presence of a catalyst, such as manganese dioxide. The reaction can be represented as follows:
2 H₂O₂ → 2 H₂O + O₂
In this reaction, hydrogen peroxide loses oxygen atoms, leading to an increase in its oxidation state from -1 to 0. Thus, this is an example of oxidation.

4. Reduction of Potassium Permanganate:
Potassium permanganate can be reduced by adding it to a solution containing an oxidizable substance, such as oxalic acid. The reaction can be represented as follows:
2 KMnO₄ + 5 H₂C₂O₄ + 3 H₂SO₄ → K₂SO₄ + 2 MnSO₄ + 10 CO₂ + 8 H₂O
In this reaction, the manganese atoms in the permanganate ion lose electrons, resulting in a decrease in their oxidation state from +7 to +2. Hence, this process is an example of reduction.

5. Oxidation of Methane:
Methane, a hydrocarbon, can be oxidized by reacting it with oxygen gas. The reaction can be represented as follows:
CH₄ + 2 O₂ → CO₂ + 2 H₂O
In this reaction, the carbon in methane loses electrons and gains oxygen atoms, resulting in an increase in its oxidation state from -4 to +4. Thus, this process is an example of oxidation.

Summary:
1. Oxidation of Iron: 4 Fe + 3 O₂ → 2 Fe₂O₃
2. Reduction of Copper Oxide: CuO + H₂ → Cu + H₂O
3. Oxidation of Hydrogen Peroxide: 2 H₂O₂ → 2 H₂O + O₂
4. Reduction of Potassium Permanganate: 2 KMnO₄ + 5 H₂C₂O₄ + 3 H₂SO₄ → K₂SO₄ + 2 MnSO₄ + 10 CO₂ + 8 H₂O
5. Oxidation of Methane: CH₄ + 2 O₂ → CO₂ + 2 H₂O

These examples demonstrate the concept of oxidation and reduction, where oxidation involves the loss of electrons or an increase in oxidation state, and reduction involves the gain of electrons or a decrease in oxidation state. Understanding these processes is fundamental
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