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In ∆ABC, angle A = 30°, side 'b' = 4 units, side 'c' = 6 units. Find the area of ∆ABC,

  • a)
    8 cm2

  • b)
    6 cm2

  • c)
    5 cm2

  • d)
    9 cm2

Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In ABC, angle A = 30°, side b = 4 units, side c = 6 units. Find th...
Area (∆ABC) = 1/2 × bc × sin A
= 1/2 × 4 × 6 × sin 30º
= 12 × 1/2 (since sin 30º = 1/2)
Area = 6 square units.
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Most Upvoted Answer
In ABC, angle A = 30°, side b = 4 units, side c = 6 units. Find th...
Given information:
Angle A = 30°
Side b = 4 units
Side c = 6 units

Step 1: Find side a using the Law of Cosines
Using the Law of Cosines formula:
a² = b² + c² - 2bc * cos(A)
a² = 4² + 6² - 2*4*6 * cos(30°)
a² = 16 + 36 - 48 * cos(30°)
a² = 52 - 48 * 0.866 (cos(30°) is approximately 0.866)
a² = 52 - 41.568
a² = 10.432
a ≈ √10.432
a ≈ 3.23 units

Step 2: Calculate the area of the triangle using the formula
Area of triangle ABC = 0.5 * b * c * sin(A)
Area = 0.5 * 4 * 6 * sin(30°)
Area = 0.5 * 24 * 0.5
Area = 6 cm²
Therefore, the correct answer is option b) 6 cm².
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Community Answer
In ABC, angle A = 30°, side b = 4 units, side c = 6 units. Find th...
By using pythogorean triplets, B^2= H^2 - P^2 B^2=13^2 - 12^2 B= square root of 25 i.e.5 area of triangle = 1/2 ×5×12=30
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