Calculate the strength of 5 volumeH2O2solution.a)2.5%solutionb)15 g/L ...
Volume strength = 11.2 x M So M = 5/11.2 = 0.446 Strength (g/L ) = 0.446 x 34 = 15.17 g/L
View all questions of this test
Calculate the strength of 5 volumeH2O2solution.a)2.5%solutionb)15 g/L ...
5 volume of H2O2 means 1L of 5 volume of H2O2 on decomposition gives 5L of O2 at ntp.
2H2O2------>2H2O+ O2
68g. 22.4L at ntp
22.4L of O2 at ntp is produced from H2O2=68g
5L of O2 at ntp is produced from H2O2=68/22.4*5= 15.18g.
%age strength of H2O2 solution = 15.18/1000*100= 1.518%
I hope that it will be helpful to you
Calculate the strength of 5 volumeH2O2solution.a)2.5%solutionb)15 g/L ...
Calculation of the strength of hydrogen peroxide solutions:
To calculate the strength of a hydrogen peroxide solution, we need to convert the given information into a common unit which is moles per liter (mol/L) or molarity.
a) 2.5% solution:
- The given solution is 2.5% hydrogen peroxide (H2O2).
- This means that there are 2.5 grams of H2O2 in 100 mL of solution.
- To convert this to grams per liter (g/L), we can multiply by 10 because there are 10 100 mL in 1 L.
- Therefore, the solution contains 25 grams of H2O2 in 1 L.
- To calculate the molarity, we need to know the molar mass of H2O2 which is 34.02 g/mol.
- The molarity can be calculated using the formula: Molarity (M) = moles/volume (L).
- In this case, the molarity is equal to 25 g / 34.02 g/mol = 0.735 mol/L.
b) 15 g/L solution:
- The given solution is 15 g/L hydrogen peroxide (H2O2).
- This means that there are 15 grams of H2O2 in 1 L of solution.
- To calculate the molarity, we need to know the molar mass of H2O2 which is 34.02 g/mol.
- The molarity can be calculated using the formula: Molarity (M) = moles/volume (L).
- In this case, the molarity is equal to 15 g / 34.02 g/mol = 0.441 mol/L.
c) 10 g/L solution:
- The given solution is 10 g/L hydrogen peroxide (H2O2).
- This means that there are 10 grams of H2O2 in 1 L of solution.
- To calculate the molarity, we need to know the molar mass of H2O2 which is 34.02 g/mol.
- The molarity can be calculated using the formula: Molarity (M) = moles/volume (L).
- In this case, the molarity is equal to 10 g / 34.02 g/mol = 0.294 mol/L.
d) 3.5% solution:
- The given solution is 3.5% hydrogen peroxide (H2O2).
- This means that there are 3.5 grams of H2O2 in 100 mL of solution.
- To convert this to grams per liter (g/L), we can multiply by 10 because there are 10 100 mL in 1 L.
- Therefore, the solution contains 35 grams of H2O2 in 1 L.
- To calculate the molarity, we need to know the molar mass of H2O2 which is 34.02 g/mol.
- The molarity can be calculated using the formula: Molarity (M) = moles/volume (L).
- In this case, the molarity is equal to 35 g / 34.02 g/mol = 1.028 mol/L.
Conclusion:
- The strength of the hydrogen per
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.