If n (P) = 5, n(Q) = 12 and n(PUQ) = 14 then n(P∩Q) =
• a)
3
• b)
4
• c)
5
• d)
7

### Related Test

 User2408930 Jul 08, 2018
Given n(P)=5 n(Q)=12 n(P union Q)=14 n((P intersection Q ) =? n(P union Q)=n(P)+n(Q)-n(P intersection Q) 14=5+12-n(P intersection Q) 14=17-n(P intersection Q) 17-14=n(P intersection Q) 3=n(P intersection Q)

 Learners Habitat Feb 18, 2022
n (P) = 5, n(Q) = 12 and n(PUQ) = 14
n(PUQ) = n(P) + n(Q) - n(P∩Q)
14 = 5 + 12 + - n(P∩Q)
n(P∩Q) = 3

 Kusum Kumari Jul 13, 2018
It is given that n(P) = 5 n(Q) = 12 n(PUQ)= 14 then n (P intersection Q) = ? Solution :- n (PU Q) = n( P) + n (Q) - n ( P intersection Q) 14 = 5 + 12 - n( P intersection Q) 14 = 17 - n ( P intersection Q) n (P intersection Q) = 17-14 = 3

 Aman Aggarwal Jul 09, 2018
N(PUQ)=14. .............. (1) n(P)=5. .............. (2) n(Q)=12. ...............(3) n(PUQ)=n(P)+n(Q) - n(P intersection Q) from (1),(2), and (3):- 14=12+5-n(P intersection Q) 14 - 17 = - n(P intersection Q) --3= -- n(P intersection Q) 3= n(P intersection Q) n(P intersection Q)= 3

Given n(P)=5 n(Q)=12 n(P union Q)=14 n((P intersection Q ) =? n(P union Q)=n(P)+n(Q)-n(P intersection Q) 14=5+12-n(P intersection Q) 14=17-n(P intersection Q) 17-14=n(P intersection Q) 3=n(P intersection Q)