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Among the compounds given in the option (a) to (d), the one that exhibits a sharp band at around 3300 cm–1 in the IR spectrum is:
  • a)
    1, 2-butadiene
  • b)
    1, 3-butadine
  • c)
    1-butyne
  • d)
    2-butyne
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Among the compounds given in the option (a) to (d), the one that exhib...

-In the IR spectrum exhibits a sharp band at around 3300 cm–1 is 1-butyne.
-1-Butyne, also known as ethylacetylene, but-1-yne, ethylethyne, and UN 2452, is an extremely flammable and reactive alkyne with chemical formula C4H6 and CAS number 107-00-6 that is used in the synthesis of organic compounds. It occurs as a colorless gas.

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Among the compounds given in the option (a) to (d), the one that exhib...
Explanation:

The compound that exhibits a sharp band at around 3300 cm^-1 in the IR spectrum is 1-butyne (option C).

IR Spectroscopy:

IR spectroscopy is a technique used to analyze the functional groups present in a compound. It measures the absorption of infrared radiation by the compound, which corresponds to the vibrational frequencies of the bonds.

IR Spectrum of Alkynes:

In the IR spectrum, alkynes typically show a strong, broad absorption band in the range of 3300-2100 cm^-1. This absorption is due to the stretching vibration of the carbon-hydrogen (C-H) bond.

Comparison of the Given Compounds:

To determine which compound exhibits a sharp band at around 3300 cm^-1, we need to compare the structures of the given compounds.

a) 1, 2-butadiene: This compound contains conjugated double bonds but does not have a triple bond. Therefore, it does not exhibit a sharp band at around 3300 cm^-1.

b) 1, 3-butadiene: Similar to 1, 2-butadiene, this compound contains conjugated double bonds but lacks a triple bond. Hence, it also does not show a sharp band at around 3300 cm^-1.

c) 1-butyne: This compound has a triple bond (C≡C) between the first and second carbon atoms. The stretching vibration of the carbon-hydrogen bond in the terminal alkyne group (-C≡CH) produces a strong, sharp absorption band at around 3300 cm^-1 in the IR spectrum. Therefore, option C is the correct answer.

d) 2-butyne: This compound also has a triple bond (C≡C), but it is present between the second and third carbon atoms. The terminal alkyne group (-C≡CH) is absent in this compound. Consequently, it does not exhibit a sharp band at around 3300 cm^-1.

Conclusion:

Among the compounds given in the options, 1-butyne (option C) is the only compound that exhibits a sharp band at around 3300 cm^-1 in the IR spectrum.
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Among the compounds given in the option (a) to (d), the one that exhibits a sharp band at around 3300 cm–1 in the IR spectrum is:a)1, 2-butadieneb)1, 3-butadinec)1-butyned)2-butyneCorrect answer is option 'C'. Can you explain this answer?
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Among the compounds given in the option (a) to (d), the one that exhibits a sharp band at around 3300 cm–1 in the IR spectrum is:a)1, 2-butadieneb)1, 3-butadinec)1-butyned)2-butyneCorrect answer is option 'C'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Among the compounds given in the option (a) to (d), the one that exhibits a sharp band at around 3300 cm–1 in the IR spectrum is:a)1, 2-butadieneb)1, 3-butadinec)1-butyned)2-butyneCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Among the compounds given in the option (a) to (d), the one that exhibits a sharp band at around 3300 cm–1 in the IR spectrum is:a)1, 2-butadieneb)1, 3-butadinec)1-butyned)2-butyneCorrect answer is option 'C'. Can you explain this answer?.
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