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# A straight wire of length l and electric dipole moment p is bent to form a semicircle. The new dipole moment would bea)p/2b)2p/πc)p/2πd)2pCorrect answer is option 'B'. Can you explain this answer? Related Test: Sample JEE Main Full Mock Test

## JEE Question

By Prince Kumar · Jan 08, 2019 ·JEE
4 Answers
Syed Mehmood answered Nov 20, 2018

Sanjeevini Angadi answered Jan 08, 2019

Aniket Das answered Aug 13, 2018
L=piÃ—r , r=L/pi , new dipole moment =qÃ—2r(2r=diameter) p'=qÃ—2L/pi , p'=2p/pi(as given, p=qr)

Pradeep Singh answered 2 weeks ago
Electric dipole moment = qÃ—2l
according to question it will form semicircle,

so applying that formula you will get your answer

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