A straight wire of length l and electric dipole moment p is bent to form a semicircle. The new dipole moment would be
  • a)
    p/2
  • b)
    2p/π
  • c)
    p/2π
  • d)
    2p
Correct answer is option 'B'. Can you explain this answer?

JEE Question

By Prince Kumar · Jan 08, 2019 ·JEE
4 Answers
Sanjeevini Angadi answered Jan 08, 2019

Aniket Das answered Aug 13, 2018
L=pi×r , r=L/pi , new dipole moment =q×2r(2r=diameter) p'=q×2L/pi , p'=2p/pi(as given, p=qr)

Pradeep Singh answered 2 weeks ago
Electric dipole moment = q×2l
according to question it will form semicircle,

so applying that formula you will get your answer

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