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Equation of circles touching x-axis at the origin and the line 4x – 3y + 24 = 0 are

- a)x
^{2}+ y^{2}-6y = 0,x^{2}+ y^{2}+ 24y = 0 - b)x
^{2}+ y^{2}+ 2y = 0,x^{2}+ y^{2}-18y = 0 - c)x
^{2}+ y^{2}+18x = 0, x^{2}+ y^{2}- 8x = 0 - d)x
^{2}+ y^{2}+ 4x = 0, x^{2}+ y^{2}-16x = 0

Correct answer is option 'A'. Can you explain this answer?

Gaurav Bansal
Sep 04, 2018 |

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Equation of circles touching x-axis at the origin and the line 4x – 3y + 24 = 0 area)x2 + y2 -6y = 0,x2 + y2 + 24y = 0b)x2 + y2 + 2y = 0,x2 + y2 -18y = 0c)x2 + y2 +18x = 0, x2 + y2 - 8x = 0d)x2 + y2 + 4x = 0, x2 + y2 -16x = 0Correct answer is option 'A'. Can you explain this answer?

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Equation of circles touching x-axis at the origin and the line 4x – 3y + 24 = 0 area)x2 + y2 -6y = 0,x2 + y2 + 24y = 0b)x2 + y2 + 2y = 0,x2 + y2 -18y = 0c)x2 + y2 +18x = 0, x2 + y2 - 8x = 0d)x2 + y2 + 4x = 0, x2 + y2 -16x = 0Correct answer is option 'A'. Can you explain this answer? for JEE 2022 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Equation of circles touching x-axis at the origin and the line 4x – 3y + 24 = 0 area)x2 + y2 -6y = 0,x2 + y2 + 24y = 0b)x2 + y2 + 2y = 0,x2 + y2 -18y = 0c)x2 + y2 +18x = 0, x2 + y2 - 8x = 0d)x2 + y2 + 4x = 0, x2 + y2 -16x = 0Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2022 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equation of circles touching x-axis at the origin and the line 4x – 3y + 24 = 0 area)x2 + y2 -6y = 0,x2 + y2 + 24y = 0b)x2 + y2 + 2y = 0,x2 + y2 -18y = 0c)x2 + y2 +18x = 0, x2 + y2 - 8x = 0d)x2 + y2 + 4x = 0, x2 + y2 -16x = 0Correct answer is option 'A'. Can you explain this answer?.

Equation of circles touching x-axis at the origin and the line 4x – 3y + 24 = 0 area)x2 + y2 -6y = 0,x2 + y2 + 24y = 0b)x2 + y2 + 2y = 0,x2 + y2 -18y = 0c)x2 + y2 +18x = 0, x2 + y2 - 8x = 0d)x2 + y2 + 4x = 0, x2 + y2 -16x = 0Correct answer is option 'A'. Can you explain this answer? for JEE 2022 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Equation of circles touching x-axis at the origin and the line 4x – 3y + 24 = 0 area)x2 + y2 -6y = 0,x2 + y2 + 24y = 0b)x2 + y2 + 2y = 0,x2 + y2 -18y = 0c)x2 + y2 +18x = 0, x2 + y2 - 8x = 0d)x2 + y2 + 4x = 0, x2 + y2 -16x = 0Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2022 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equation of circles touching x-axis at the origin and the line 4x – 3y + 24 = 0 area)x2 + y2 -6y = 0,x2 + y2 + 24y = 0b)x2 + y2 + 2y = 0,x2 + y2 -18y = 0c)x2 + y2 +18x = 0, x2 + y2 - 8x = 0d)x2 + y2 + 4x = 0, x2 + y2 -16x = 0Correct answer is option 'A'. Can you explain this answer?.

Solutions for Equation of circles touching x-axis at the origin and the line 4x – 3y + 24 = 0 area)x2 + y2 -6y = 0,x2 + y2 + 24y = 0b)x2 + y2 + 2y = 0,x2 + y2 -18y = 0c)x2 + y2 +18x = 0, x2 + y2 - 8x = 0d)x2 + y2 + 4x = 0, x2 + y2 -16x = 0Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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