What is the number of integral solutions of the equation 2x2 – 3x – 2 = 0?
  • a)
    0
  • b)
    1
  • c)
    2
  • d)
    3
  • e)
    4
Correct answer is option 'B'. Can you explain this answer?

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Sidhanta Nayak
3 weeks ago
Make it a^2 + 2ab +b^2
1st take 2 to ri8 side and devide 2 in each side
you get x^2-3x/2=1

here 2ab is 3x/2, than b is 3/4
add (3/4)^2 in both sides

it gives x^2 - 3x/2+ (9/16)=25/16
(x-3/4)^2 =25/16

x-3/4= 5/4

x=2

Make it a^2 + 2ab +b^21st take 2 to ri8 side and devide 2 in each sideyou get x^2-3x/2=1here 2ab is 3x/2, than b is 3/4add (3/4)^2 in both sidesit gives x^2 - 3x/2+ (9/16)=25/16(x-3/4)^2 =25/16x-3/4= 5/4x=2
Make it a^2 + 2ab +b^21st take 2 to ri8 side and devide 2 in each sideyou get x^2-3x/2=1here 2ab is 3x/2, than b is 3/4add (3/4)^2 in both sidesit gives x^2 - 3x/2+ (9/16)=25/16(x-3/4)^2 =25/16x-3/4= 5/4x=2