Three coins are tossed. If at least two coins show head, the probability of getting one tail is:​
  • a)
    3/4
  • b)
    1/3
  • c)
    1
  • d)
    2/3
Correct answer is option 'A'. Can you explain this answer?

JEE Question

By Harika K.. · May 03, 2019 ·JEE
3 Answers
Amhe Nadi answered Aug 16, 2018
Sample space = HHH, HHT, HTH, THH, TTH, THT, HTT, TTTGetting atleast two heads(F) = HHH, HHT, HTH, THHProbability of getting atleast two heads(F) = 4/8 =1/2Getting one tail (E) = HHT, HTH, THHE intersection F = HHT, HTH, THHP(E intersection F) = 3/8Required probability = P(E intersection F) / P(F) = 3/8 ÷ 1/2 =3/4

Seblewongel Girma answered May 03, 2019
Subset={HHH , HHT,HTH,HTT,THH,THT,TTH,TTT}
P(at least two head and one tail)=6/8=3/4

Premila Gamit answered Aug 12, 2018
1 obviously

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