What is the least multiple of 9 which leaves a remainder

of 3 when divided by each 4, 6 and 7?a) 171

b) 74

c) 99

d) 364

Correct answer is option 'A'. Can you explain this answer?

7 Answers

Priya Tiwari
answered
2 weeks ago

First we take LCM of 4,6,7 is 84 so, no. will be

84x+3, which is multiple of 9.

now go through the option.

option a is multiple of 9 and if we divide with 84 it gives remainder as 3.

so option ' a ' is correct.

84x+3, which is multiple of 9.

now go through the option.

option a is multiple of 9 and if we divide with 84 it gives remainder as 3.

so option ' a ' is correct.

Nayana Kowshik
answered
Mar 23, 2020

Yes it is op A 171..divide 171 by 4,6, and 7.when divided by each the remainder is 3...so..

Vibhor E L U
answered
Jun 24, 2019

For least multiple, divisor must be equal to dividend such that the quotient = 1.

(9k - 3)/(4Ã—6Ã—7) = 1

9k = 168 + 3 = 171.

(9k - 3)/(4Ã—6Ã—7) = 1

9k = 168 + 3 = 171.

Prerna Shankar
answered
Oct 06, 2018

L.C.M. of 6, 9, 15 and 18 is 90.

Let required number be 90k + 4, which is multiple of 7.

Least value of k for which (90k + 4) is divisible by 7 is k = 4.

âˆ´Required number = (90 x 4) + 4 = 364.

Krati Mangal
answered
May 27, 2020

Yes..when remainder is same then the first such number will be LCM(divisiors) + remainder...so the first number will be 84.but 84 is not divisible by 9 so add the LCM again to get next number , which is 171.

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