• a)
    1
  • b)
    0
  • c)
    5
  • d)
    none of these
Correct answer is option 'B'. Can you explain this answer?

CA Foundation Question

By Kavya C · May 25, 2020 ·CA Foundation
5 Answers
Mini Dharsini answered May 25, 2020
(b-c)x=(b-c)(b+c-a). ,(c-a)y=(c-a)(c+a-b). ,(a-b)z=(a-b)(a+b-c)


=( b^2+ bc-ab-bc-c^2+ac) + (c ^2+ac-bc-ac-a^2+ab) +
(a^2+ab-ac-ab-b^2+bc).
= 0

Anjali Verma answered Sep 25, 2018
Can anyone solve it for me

Ayush Agarwal answered Jul 23, 2020
It's answer is 0
bcus the question is based on tricks of cyclic order

Latha Gone answered Jul 23, 2020
Let X=(b+c-a);y=(c+a-b);z=(a+b-c)

=(b-c)(b+c-a)+(c-a)(c+a-b)+(a-b)(a+b-c)

=b^2-c^2-ab+ac+c^2-a^2-bc+ab+a^2-b^2-ac+bc

=0

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