T_{50} (Half-life period) of first-order reaction is 10 minute. Starting with 10 mol L^{–1}. Rate after 20 minute is:

- a)0.0693 mol L
^{–1}min^{–1} - b)0.0693 x 2.5 mol L
^{–1}min^{–1} - c)0.0693 x 5 mol L
^{–1}min^{–1} - d)0.0693 x 10 mol L
^{–1}min^{–1}

Correct answer is option 'B'. Can you explain this answer?

Related Test: Test: Chemical Kinetics - 3

This discussion on T50 (Half-life period) of first-order reaction is 10 minute. Starting with 10 mol L1. Rate after 20 minute is:a)0.0693 mol L1 min1b)0.0693 x2.5 mol L1 min1c)0.0693 x5 mol L1 min1d)0.0693 x10 mol L1 min1Correct answer is option 'B'. Can you explain this answer? is done on EduRev Study Group by Chemistry Students. The Questions and
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T50 (Half-life period) of first-order reaction is 10 minute. Starting with 10 mol L1. Rate after 20 minute is:a)0.0693 mol L1 min1b)0.0693 x2.5 mol L1 min1c)0.0693 x5 mol L1 min1d)0.0693 x10 mol L1 min1Correct answer is option 'B'. Can you explain this answer? over here on EduRev! Apart from being the largest Chemistry community, EduRev has the largest solved
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