T50 (Half-life period) of first-order reaction is 10 minute. Starting with 10 mol L–1. Rate after 20 minute is:
  • a)
    0.0693 mol L–1 min–1
  • b)
    0.0693 x 2.5 mol L–1 min–1
  • c)
    0.0693 x 5 mol L–1 min–1
  • d)
    0.0693 x 10 mol L–1 min–1
Correct answer is option 'B'. Can you explain this answer?

Chemistry Question

Shweta Gupta answered Aug 20, 2018

This discussion on T50 (Half-life period) of first-order reaction is 10 minute. Starting with 10 mol L1. Rate after 20 minute is:a)0.0693 mol L1 min1b)0.0693 x2.5 mol L1 min1c)0.0693 x5 mol L1 min1d)0.0693 x10 mol L1 min1Correct answer is option 'B'. Can you explain this answer? is done on EduRev Study Group by Chemistry Students. The Questions and Answers of T50 (Half-life period) of first-order reaction is 10 minute. Starting with 10 mol L1. Rate after 20 minute is:a)0.0693 mol L1 min1b)0.0693 x2.5 mol L1 min1c)0.0693 x5 mol L1 min1d)0.0693 x10 mol L1 min1Correct answer is option 'B'. Can you explain this answer? are solved by group of students and teacher of Chemistry, which is also the largest student community of Chemistry. If the answer is not available please wait for a while and a community member will probably answer this soon. You can study other questions, MCQs, videos and tests for Chemistry on EduRev and even discuss your questions like T50 (Half-life period) of first-order reaction is 10 minute. Starting with 10 mol L1. Rate after 20 minute is:a)0.0693 mol L1 min1b)0.0693 x2.5 mol L1 min1c)0.0693 x5 mol L1 min1d)0.0693 x10 mol L1 min1Correct answer is option 'B'. Can you explain this answer? over here on EduRev! Apart from being the largest Chemistry community, EduRev has the largest solved Question bank for Chemistry.
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