A beaker contains 200g of water. The heat capacity of the beaker is equal to that of 20g water the initial temperature of water in the beaker is 20 degree celsius.if 440g of hot water at 92 degree Celsius is poured in, the final temperature (neglecting radiation loss) will be nearly.?.the answer for this is 68 degree celsius . Please solve this .?

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A beaker contains 200g of water. The heat capacity of the beaker is equal to that of 20g water the initial temperature of water in the beaker is 20 degree celsius.if 440g of hot water at 92 degree Celsius is poured in, the final temperature (neglecting radiation loss) will be nearly.?.the answer for this is 68 degree celsius . Please solve this .?

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A beaker contains 200g of water. The heat capacity of the beaker is eq...

Heat released by the hot water=Heat accepted by the cold water+Heat accepted by the beaker

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A beaker contains 200g of water. The heat capacity of the beaker is eq...

Given information:
- Initial mass of water in the beaker = 200g
- Heat capacity of the beaker = Heat capacity of 20g water
- Initial temperature of the water in the beaker = 20 degrees Celsius
- Mass of hot water poured in = 440g
- Temperature of hot water poured in = 92 degrees Celsius

Calculating the heat gained by the water in the beaker:
The heat gained by the water in the beaker can be calculated using the formula:

Q = mcΔT

Where:
Q = Heat gained
m = Mass of the substance
c = Specific heat capacity of the substance
ΔT = Change in temperature

In this case, the mass of water in the beaker is 200g, and the initial temperature is 20 degrees Celsius. The specific heat capacity of water is 4.18 J/g°C.

Q1 = 200g * 4.18 J/g°C * (Tf - 20°C)
Q1 = 836(Tf - 20) J

Calculating the heat gained by the hot water:
Similarly, we can calculate the heat gained by the hot water poured into the beaker. The mass of the hot water is 440g, and the initial temperature is 92 degrees Celsius.

Q2 = 440g * 4.18 J/g°C * (Tf - 92°C)
Q2 = 1839.2(Tf - 92) J

Since the heat gained by the water in the beaker is equal to the heat gained by the hot water, we can equate the two equations:

836(Tf - 20) = 1839.2(Tf - 92)

Simplifying the equation:

836Tf - 16720 = 1839.2Tf - 168998.4

1003.2Tf = 152278.4

Tf ≈ 152278.4 / 1003.2

Tf ≈ 151.63 degrees Celsius

Therefore, the final temperature of the water in the beaker, neglecting radiation loss, will be approximately 151.63 degrees Celsius.

Answered by Mohit Rajpoot · View profile

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A beaker contains 200g of water. The heat capacity of the beaker is equal to that of 20g water the initial temperature of water in the beaker is 20 degree celsius.if 440g of hot water at 92 degree Celsius is poured in, the final temperature (neglecting radiation loss) will be nearly.?.the answer for this is 68 degree celsius . Please solve this .? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A beaker contains 200g of water. The heat capacity of the beaker is equal to that of 20g water the initial temperature of water in the beaker is 20 degree celsius.if 440g of hot water at 92 degree Celsius is poured in, the final temperature (neglecting radiation loss) will be nearly.?.the answer for this is 68 degree celsius . Please solve this .? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A beaker contains 200g of water. The heat capacity of the beaker is equal to that of 20g water the initial temperature of water in the beaker is 20 degree celsius.if 440g of hot water at 92 degree Celsius is poured in, the final temperature (neglecting radiation loss) will be nearly.?.the answer for this is 68 degree celsius . Please solve this .?.

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