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The height in time t by a particle thrown upward with a speed u is given by h = ut - 1/2gt^2 where g = 9.8m/s^2 is a constant . find the time taken in reaching the maximum height.?
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The height in time t by a particle thrown upward with a speed u is giv...
Time taken to reach maximum height
• To find the time taken to reach the maximum height, we need to consider the particle's motion when it reaches its highest point.
• At the maximum height, the particle's velocity becomes zero, as it momentarily stops moving upward before starting to descend.
• Therefore, we can set the velocity equation to zero and solve for time to find the time taken to reach the maximum height.
Velocity equation
• The velocity of the particle at any time t can be found by taking the derivative of the height equation with respect to time.
• The velocity equation is given by v = u - gt, where v is the velocity at time t.
• Setting v to zero and solving for t gives us the time taken to reach the maximum height.
Solving for time
• Setting v = u - gt to zero, we get u - gt = 0
• Solving for t, we get t = u/g
• Therefore, the time taken to reach the maximum height is t = u/g.
Conclusion
• The time taken to reach the maximum height by a particle thrown upward with a speed u is t = u/g, where g = 9.8m/s^2.
• Understanding the motion of the particle and the relationship between velocity and time helps us determine the time taken to reach the maximum height accurately.
• To find the time taken to reach the maximum height, we need to consider the particle's motion when it reaches its highest point.
• At the maximum height, the particle's velocity becomes zero, as it momentarily stops moving upward before starting to descend.
• Therefore, we can set the velocity equation to zero and solve for time to find the time taken to reach the maximum height.
Velocity equation
• The velocity of the particle at any time t can be found by taking the derivative of the height equation with respect to time.
• The velocity equation is given by v = u - gt, where v is the velocity at time t.
• Setting v to zero and solving for t gives us the time taken to reach the maximum height.
Solving for time
• Setting v = u - gt to zero, we get u - gt = 0
• Solving for t, we get t = u/g
• Therefore, the time taken to reach the maximum height is t = u/g.
Conclusion
• The time taken to reach the maximum height by a particle thrown upward with a speed u is t = u/g, where g = 9.8m/s^2.
• Understanding the motion of the particle and the relationship between velocity and time helps us determine the time taken to reach the maximum height accurately.
Community Answer
The height in time t by a particle thrown upward with a speed u is giv...
Hmax=Uy^2/2g
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The height in time t by a particle thrown upward with a speed u is given by h = ut - 1/2gt^2 where g = 9.8m/s^2 is a constant . find the time taken in reaching the maximum height.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The height in time t by a particle thrown upward with a speed u is given by h = ut - 1/2gt^2 where g = 9.8m/s^2 is a constant . find the time taken in reaching the maximum height.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The height in time t by a particle thrown upward with a speed u is given by h = ut - 1/2gt^2 where g = 9.8m/s^2 is a constant . find the time taken in reaching the maximum height.?.
The height in time t by a particle thrown upward with a speed u is given by h = ut - 1/2gt^2 where g = 9.8m/s^2 is a constant . find the time taken in reaching the maximum height.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The height in time t by a particle thrown upward with a speed u is given by h = ut - 1/2gt^2 where g = 9.8m/s^2 is a constant . find the time taken in reaching the maximum height.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The height in time t by a particle thrown upward with a speed u is given by h = ut - 1/2gt^2 where g = 9.8m/s^2 is a constant . find the time taken in reaching the maximum height.?.
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