A man can row three-quarters of a kilometer against the stream in 11 1...
Given information:
- The man can row three-quarters of a kilometer against the stream in 11 1/4 minutes.
- The man can row three-quarters of a kilometer down the stream in 7 1/2 minutes.
Let's assume the speed of the stream is x kmph and the speed of the man in still water is y kmph.
Calculating the speed of the man against the stream:
- Speed of the man against the stream = y - x kmph
- Distance covered in 11 1/4 minutes = 3/4 km
- Time taken = 11 1/4 minutes = 45/4 minutes
- Speed = Distance / Time
- (y - x) = (3/4) / (45/4)
- (y - x) = 3/45
- (y - x) = 1/15 ----(1)
Calculating the speed of the man down the stream:
- Speed of the man down the stream = y + x kmph
- Distance covered in 7 1/2 minutes = 3/4 km
- Time taken = 7 1/2 minutes = 15/2 minutes
- Speed = Distance / Time
- (y + x) = (3/4) / (15/2)
- (y + x) = 3/30
- (y + x) = 1/10 ----(2)
Adding equations (1) and (2):
- (y - x) + (y + x) = 1/15 + 1/10
- 2y = 1/15 + 1/10
- 2y = 2/30 + 3/30
- 2y = 5/30
- 2y = 1/6
- y = 1/12
Therefore, the speed of the man in still water is 1/12 kmph.
Converting to kmph:
- 1/12 kmph = (1/12) * (60/1) = 5 kmph.
Hence, the correct answer is option B) 5 kmph.