A tap can fill a tank in 4 hours. After half the tank is filled, two m...
Explanation :
A tap can fill a tank in 4 hours
= The tap can fill half the tank in 2 hours
Remaining part = 1/2
After half the tank is filled, three more similar taps are opened.
Hence, total number of taps becomes 4.
Part filled by one tap in 1 hour = 1/4
Part filled by four taps in 1 hour =
4*1/4=1
i.e., 4 taps can fill remaining half in 40 minutes
total time taken = 2 hour + 40 minute = 2 hour 40 minutes
View all questions of this testA tap can fill a tank in 4 hours. After half the tank is filled, two m...
Solution:
Let the capacity of the tank be 'C'.
Given, a tap can fill the tank in 4 hours.
So, the rate of the tap = 1/4 tank/hour.
When half of the tank is filled, then the remaining capacity = C/2.
Now, two more similar taps are opened. So, the total number of taps becomes three.
Hence, the rate of three taps = 3 × (1/4) = 3/4 tank/hour.
Using the formula,
Time = (Volume of work) / (Rate of work)
Time taken to fill the remaining half of the tank = (C/2) / (3/4) = (C/2) × (4/3) = 2C/3
Therefore, the total time taken to fill the tank completely = Time taken to fill the first half of the tank + Time taken to fill the remaining half of the tank
= C / (1/4) + 2C/3
= 4C + 8C/12
= 32C/12
= 8C/3
Hence, the total time taken to fill the tank completely is 8C/3 hours.
As we do not have the value of C, we cannot calculate the exact time taken to fill the tank. So, option D, 2 hours 40 minutes, cannot be confirmed as the answer.
A tap can fill a tank in 4 hours. After half the tank is filled, two m...
Since
4hr is full time.
so to first fill it half 2 hours will be required
anything greater than 2 and less than 3 will be the answer.
By looking into the option only option 4 is valid