The change in entropy when three moles of argon gas are heated at constant volume from 200 K to 300 K is:
  • a)
    15.16 JK–1mol–1
  • b)
    – 15.16 JK–1mol–1
  • c)
    – 5.05 JK–1mol–1
  • d)
    5.05 JK–1mol–1
Correct answer is option 'D'. Can you explain this answer?

IIT JAM Question

By Ajit Yadav · 4 days ago ·IIT JAM
2 Answers
Nishant Singh answered Dec 01, 2018
You must be thinking that the answer should be A from the formula but options are given in J per Kelvin per mole so divide your answer with 3  i.e. 15.20/3=5.06 J per Kelvin per mole

This discussion on The change in entropy when three moles of argon gas are heated at constant volume from 200 K to 300 K is:a)15.16 JK1mol1b) 15.16 JK1mol1c) 5.05 JK1mol1d)5.05 JK1mol1Correct answer is option 'D'. Can you explain this answer? is done on EduRev Study Group by IIT JAM Students. The Questions and Answers of The change in entropy when three moles of argon gas are heated at constant volume from 200 K to 300 K is:a)15.16 JK1mol1b) 15.16 JK1mol1c) 5.05 JK1mol1d)5.05 JK1mol1Correct answer is option 'D'. Can you explain this answer? are solved by group of students and teacher of IIT JAM, which is also the largest student community of IIT JAM. If the answer is not available please wait for a while and a community member will probably answer this soon. You can study other questions, MCQs, videos and tests for IIT JAM on EduRev and even discuss your questions like The change in entropy when three moles of argon gas are heated at constant volume from 200 K to 300 K is:a)15.16 JK1mol1b) 15.16 JK1mol1c) 5.05 JK1mol1d)5.05 JK1mol1Correct answer is option 'D'. Can you explain this answer? over here on EduRev! Apart from being the largest IIT JAM community, EduRev has the largest solved Question bank for IIT JAM.
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