A tower stands vertically on the ground. From...

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A tower stands vertically on the ground. From a point on the ground which is 25 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45o. Then the height (in meters) of the tower is​
• a)
25
• b)
25√3
• c)
12.5
• d)
25√2

A point on the ground which is 25 m away from the foot of the tower i. BC= 25 m
Let the height of the tower be x
The angle of elevation of the tower is found to be 45 degree.i.e.∠ACB=45°
In ΔABC
Using trigonometric ratios

Hence the height of the tower is 25 m.

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A tower stands vertically on the ground. From a point on the ground which is 25 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45o. Then the height (in meters) of the tower is​a)25b)25√3c)12.5d)25√2Correct answer is option 'A'. Can you explain this answer?

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•••hey look , we know the distance from the foot of the tower is 25 m which means , B= 25m and the the angle of elevation is 45 degree •••

we need to find the height of the tower means P

then we know that tan theta = P/B

and tan 45 = P/ 25. ...
then 1= P/25 ...( becoz the value of tan 45 degree is 1)

P = 25 m ans••

•• that's it•••

A tower stands vertically on the ground. From a point on the ground which is 25 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45o. Then the height (in meters) of the tower is​a)25b)25√3c)12.5d)25√2Correct answer is option 'A'. Can you explain this answer?
Let us consider the h of the tower to be AB and the point on the ground is C which is 25 m away from the foot of the tower

tan 45 degree=1
AB/BC=1
AB=BC
AB=25m

hence ,,
is ur ans

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