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At temperature T, the compound AB2 (g) dissociates according to the reaction, 2AB2 (g)   2 AB(g) + B2(g).With a degree of dissociation x, which is small compared with unity. Deduce the expression for x in terms of the equilibrium constant, Kp and the total pressure, P.
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'D'. Can you explain this answer?
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At temperature T, the compound AB2 (g) dissociates according to the re...
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At temperature T, the compound AB2 (g) dissociates according to the reaction, 2AB2 (g) 2 AB(g) + B2(g).With a degree of dissociation x, which is small compared with unity. Deduce the expression for x in terms of the equilibrium constant, Kp and the total pressure, P.a)b)c)d)Correct answer is option 'D'. Can you explain this answer?
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At temperature T, the compound AB2 (g) dissociates according to the reaction, 2AB2 (g) 2 AB(g) + B2(g).With a degree of dissociation x, which is small compared with unity. Deduce the expression for x in terms of the equilibrium constant, Kp and the total pressure, P.a)b)c)d)Correct answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about At temperature T, the compound AB2 (g) dissociates according to the reaction, 2AB2 (g) 2 AB(g) + B2(g).With a degree of dissociation x, which is small compared with unity. Deduce the expression for x in terms of the equilibrium constant, Kp and the total pressure, P.a)b)c)d)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At temperature T, the compound AB2 (g) dissociates according to the reaction, 2AB2 (g) 2 AB(g) + B2(g).With a degree of dissociation x, which is small compared with unity. Deduce the expression for x in terms of the equilibrium constant, Kp and the total pressure, P.a)b)c)d)Correct answer is option 'D'. Can you explain this answer?.
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