What quantity of limestone on heating will give 56 kg of CaO? 1)1000 k...
Calculation of Quantity of Limestone:
To find the quantity of limestone on heating that will give 56 kg of CaO, we need to use the stoichiometry of the chemical reaction that occurs when limestone is heated.
The chemical equation for the reaction is:
CaCO3(s) → CaO(s) + CO2(g)
From the equation, we can see that 1 mole of CaCO3 produces 1 mole of CaO. The molar mass of CaCO3 is 100.09 g/mol, and the molar mass of CaO is 56.08 g/mol.
Therefore, we can use the following formula to calculate the quantity of limestone required:
Quantity of limestone (in kg) = (56 kg of CaO) x (1 mole of CaCO3 / 1 mole of CaO) x (100.09 g/mol of CaCO3) x (1 kg / 1000 g)
Quantity of limestone (in kg) = 5.609 kg
Therefore, the correct option is:
3) 44 kg
Explanation:
- Heading: Calculation of Quantity of Limestone
- Heading: Chemical Equation
- The chemical equation for the reaction is: CaCO3(s) → CaO(s) + CO2(g)
- Heading: Stoichiometry
- From the equation, we can see that 1 mole of CaCO3 produces 1 mole of CaO.
- The molar mass of CaCO3 is 100.09 g/mol, and the molar mass of CaO is 56.08 g/mol.
- Heading: Formula
- We can use the following formula to calculate the quantity of limestone required:
- Quantity of limestone (in kg) = (56 kg of CaO) x (1 mole of CaCO3 / 1 mole of CaO) x (100.09 g/mol of CaCO3) x (1 kg / 1000 g)
- Heading: Calculation
- Quantity of limestone (in kg) = 5.609 kg
- Heading: Answer
- Therefore, the correct option is:
- 3) 44 kg
What quantity of limestone on heating will give 56 kg of CaO? 1)1000 k...
CaCO3→ CaO + CO2
1mole 1mole 1mole
100gm. 56gm. 44gm
therefore 100gm (or kg)of CaCO3 will give 56 gm(or kg) of CaO
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