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One of the addresses in a block is 135.16.27.116/20, the third octet (in decimal) of the first IP address in the block is _______.
    Correct answer is '16'. Can you explain this answer?
    Verified Answer
    One of the addresses in a block is 135.16.27.116/20, the third octet (...
    Concept:
    Keep the n leftmost bits of given address in the block and set the 32 − n rightmost bits to 0s to find the first address where n is the prefix length. 
    Calculation:
    Here, prefix length is 20.
    135.16.27.116 ⇒⇒ 10000111 00010000 00011011 01110100 
    The first 20 bits of this octal are fixed as 10000111 00010000 0001
    The remaining 32 – 20 = 12 bits can get a maximum value as 0000 00000000.
    So the possible first octal IP address is 10000111 00010000 00010000 00000000 which is 135.16.16.0
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    One of the addresses in a block is 135.16.27.116/20, the third octet (in decimal) of the first IP address in the block is _______.Correct answer is '16'. Can you explain this answer?
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