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3 mole of a mixture of FeSO4 and Fe2(SO4)3 required 100 ml of 2M KMnO4 solution in acidic medium. Hence mole fraction of FeSO4 in the mixture is
- a)3/5
- b)2/3
- c)2/5
- d)1/3
Correct answer is option 'D'. Can you explain this answer?
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3 mole of a mixture of FeSO4 and Fe2(SO4)3 required 100 ml of 2M KMnO4...
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3 mole of a mixture of FeSO4 and Fe2(SO4)3 required 100 ml of 2M KMnO4...
Given:
- 3 moles of a mixture of FeSO4 and Fe2(SO4)3
- 100 ml of 2M KMnO4 solution in acidic medium
To find:
- Mole fraction of FeSO4 in the mixture
Solution:
1. Write the balanced chemical equation for the reaction between FeSO4 and KMnO4 in acidic medium:
5FeSO4 + 2KMnO4 + 8H2SO4 → 5Fe2(SO4)3 + K2SO4 + 2MnSO4 + 8H2O
2. From the equation, we can see that each mole of FeSO4 reacts with 2/5 moles of KMnO4.
So, 3 moles of the mixture will react with (2/5) x 3 = 6/5 moles of KMnO4.
3. We know that 100 ml of 2M KMnO4 solution contains 2 x (100/1000) = 0.2 moles of KMnO4.
Therefore, 6/5 moles of KMnO4 will be present in (6/5) / 0.2 = 3 moles of the mixture.
4. Let x be the mole fraction of FeSO4 in the mixture.
Then, the mole fraction of Fe2(SO4)3 will be (1-x).
5. Using the reaction stoichiometry, we can write:
3x moles of FeSO4 will react with 2(1-x) moles of Fe2(SO4)3.
Therefore, 3x + 2(1-x) = 3 moles (total moles of mixture)
6. Solving for x, we get:
x = 1/3
Therefore, the mole fraction of FeSO4 in the mixture is 1/3, which is option (d).
- 3 moles of a mixture of FeSO4 and Fe2(SO4)3
- 100 ml of 2M KMnO4 solution in acidic medium
To find:
- Mole fraction of FeSO4 in the mixture
Solution:
1. Write the balanced chemical equation for the reaction between FeSO4 and KMnO4 in acidic medium:
5FeSO4 + 2KMnO4 + 8H2SO4 → 5Fe2(SO4)3 + K2SO4 + 2MnSO4 + 8H2O
2. From the equation, we can see that each mole of FeSO4 reacts with 2/5 moles of KMnO4.
So, 3 moles of the mixture will react with (2/5) x 3 = 6/5 moles of KMnO4.
3. We know that 100 ml of 2M KMnO4 solution contains 2 x (100/1000) = 0.2 moles of KMnO4.
Therefore, 6/5 moles of KMnO4 will be present in (6/5) / 0.2 = 3 moles of the mixture.
4. Let x be the mole fraction of FeSO4 in the mixture.
Then, the mole fraction of Fe2(SO4)3 will be (1-x).
5. Using the reaction stoichiometry, we can write:
3x moles of FeSO4 will react with 2(1-x) moles of Fe2(SO4)3.
Therefore, 3x + 2(1-x) = 3 moles (total moles of mixture)
6. Solving for x, we get:
x = 1/3
Therefore, the mole fraction of FeSO4 in the mixture is 1/3, which is option (d).
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3 mole of a mixture of FeSO4 and Fe2(SO4)3 required 100 ml of 2M KMnO4...
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3 mole of a mixture of FeSO4 and Fe2(SO4)3 required 100 ml of 2M KMnO4 solution in acidic medium. Hence mole fraction of FeSO4 in the mixture isa)3/5b)2/3c)2/5d)1/3Correct answer is option 'D'. Can you explain this answer?
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3 mole of a mixture of FeSO4 and Fe2(SO4)3 required 100 ml of 2M KMnO4 solution in acidic medium. Hence mole fraction of FeSO4 in the mixture isa)3/5b)2/3c)2/5d)1/3Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 3 mole of a mixture of FeSO4 and Fe2(SO4)3 required 100 ml of 2M KMnO4 solution in acidic medium. Hence mole fraction of FeSO4 in the mixture isa)3/5b)2/3c)2/5d)1/3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3 mole of a mixture of FeSO4 and Fe2(SO4)3 required 100 ml of 2M KMnO4 solution in acidic medium. Hence mole fraction of FeSO4 in the mixture isa)3/5b)2/3c)2/5d)1/3Correct answer is option 'D'. Can you explain this answer?.
3 mole of a mixture of FeSO4 and Fe2(SO4)3 required 100 ml of 2M KMnO4 solution in acidic medium. Hence mole fraction of FeSO4 in the mixture isa)3/5b)2/3c)2/5d)1/3Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 3 mole of a mixture of FeSO4 and Fe2(SO4)3 required 100 ml of 2M KMnO4 solution in acidic medium. Hence mole fraction of FeSO4 in the mixture isa)3/5b)2/3c)2/5d)1/3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3 mole of a mixture of FeSO4 and Fe2(SO4)3 required 100 ml of 2M KMnO4 solution in acidic medium. Hence mole fraction of FeSO4 in the mixture isa)3/5b)2/3c)2/5d)1/3Correct answer is option 'D'. Can you explain this answer?.
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