How many numbers arc there between 99 and 1000 such that the digit 8 o...
Numbers are: 108, 118, 128, 138, .............,998
Total = 10 x 9 =90
View all questions of this testHow many numbers arc there between 99 and 1000 such that the digit 8 o...
To find the number of numbers between 99 and 1000 such that the digit 8 occupies the units place, we can break down the problem into smaller cases and then add up the results.
Numbers in the form of XY8:
- For the hundreds place (X), we have 9 options (1-9).
- For the tens place (Y), we have 10 options (0-9).
- For the units place (8), we have only 1 option.
So, for numbers in the form of XY8, we have a total of 9 * 10 * 1 = 90 options.
Numbers in the form of X88:
- For the hundreds place (X), we have 9 options (1-9).
- For the tens place (8), we have only 1 option.
- For the units place (8), we have only 1 option.
So, for numbers in the form of X88, we have a total of 9 * 1 * 1 = 9 options.
Numbers in the form of 88Y:
- For the hundreds place (8), we have only 1 option.
- For the tens place (8), we have only 1 option.
- For the units place (Y), we have 10 options (0-9).
So, for numbers in the form of 88Y, we have a total of 1 * 1 * 10 = 10 options.
Adding up the results from all three cases, we have:
90 + 9 + 10 = 109
However, we need to exclude the number 888 as it falls outside the range between 99 and 1000. Therefore, we subtract 1 from the total.
109 - 1 = 108
Therefore, the correct answer is option C) 108.