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Quadrilaterals MCQs for Class 9 Exam

It covers all Important Questions with answers on Quadrilaterals for the Class 9 exam. The questions are based on important topics. Details about the questions:
  • Topic: Quadrilaterals
  • Type of Questions: MCQs with solutions
  • Number of Questions: 25
  • You can attempt them on EduRev to score high in Class 9 exam.

The figure formed by joining the mid-points of consecutive sides of a quadrilateral is a 
  • a)
    Parallelogram
  • b)
    Trapezium 
  • c)
    Rectangle
  • d)
    None of these 
Correct answer is option 'A'. Can you explain this answer?

Namrata Desai answered
The figure formed by joining the mid-points of consecutive sides of a quadrilateral is a Parallelogram.

Explanation:
A quadrilateral is a polygon with four sides. Let's consider a quadrilateral ABCD, where AB, BC, CD, and DA are the four sides.

Now, let's join the mid-points of the consecutive sides of the quadrilateral. Let the midpoints of AB, BC, CD, and DA be E, F, G, and H respectively.

To prove that the figure formed is a parallelogram, we need to show that opposite sides are parallel and equal in length.

1. Opposite sides are parallel:
- Join EF and GH. These diagonals divide the quadrilateral ABCD into four triangles: AEF, BFG, CGH, and DHG.
- By the Midpoint Theorem, EF is parallel to AB and GH is parallel to CD.
- Similarly, EG is parallel to AD and FH is parallel to BC.
- Therefore, opposite sides EF and GH are parallel, and opposite sides EG and FH are parallel.

2. Opposite sides are equal in length:
- By the Midpoint Theorem, EF = 1/2 AB and GH = 1/2 CD.
- Similarly, EG = 1/2 AD and FH = 1/2 BC.
- Therefore, opposite sides EF and GH are equal in length, and opposite sides EG and FH are equal in length.

Since the figure has opposite sides parallel and equal in length, it satisfies the definition of a parallelogram.

Hence, the figure formed by joining the mid-points of consecutive sides of a quadrilateral is a parallelogram.

Note: It is important to note that the converse of this statement is also true. That is, if a quadrilateral is a parallelogram, then the midpoints of its sides will form a parallelogram.

In a quadrilateral, the angles are in the ratio 1 : 2 : 3 : 4. What is the value of largest angle?
  • a)
    108°
  • b)
    144°
  • c)
    136°
  • d)
    124° 
Correct answer is option 'B'. Can you explain this answer?

Nilofer Singh answered
B)144

Let the four angles be 1x, 2x, 3x, and 4x respectively.

Since the sum of angles in a quadrilateral is 360 degrees, we have:

1x + 2x + 3x + 4x = 360
10x = 360
x = 36

Therefore, the largest angle is 4x = 4(36) = 144 degrees.

The angles of a quadrilateral are in the ratio 3 : 5 : 9 : 13. What is the sum of largest and smallest angle of quadrilateral? 
  • a)
    168°
  • b)
    192°
  • c)
    144°
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Swati Verma answered
Let the angles be 3x,5x,9x and 13x
∴ Sum of largest and smallest angle = 3x + 13x = 16x
A/Q,
3x + 5x + 9x + 13x = 360°
⇒ 30x = 360°  ⇒ x = 12
∴ 16x = 16 × 12° = 192°

If the length of each side of rhombus is 15 cm and one of its diagonals is 24 cm what is length of other diagonal?
  • a)
    16 cm
  • b)
    14 cm
  • c)
    18 cm
  • d)
    12 cm
Correct answer is option 'C'. Can you explain this answer?

Prachi Sharma answered
Given information:
- Length of each side of the rhombus = 15 cm
- Length of one diagonal = 24 cm

To find: Length of the other diagonal

Properties of a rhombus:
1. All sides of a rhombus are equal in length.
2. The diagonals of a rhombus bisect each other at right angles.

Using these properties, we can solve the problem.

Solution:
Let's denote the length of the other diagonal as 'd'.

Step 1: Find the length of the other side of the rhombus.
Since all sides of a rhombus are equal in length, the length of each side is 15 cm.

Step 2: Find the length of the diagonals.
The diagonals of a rhombus bisect each other at right angles. This means that they divide the rhombus into four congruent right-angled triangles.

Using the Pythagorean theorem, we can find the length of the diagonals.
In each right-angled triangle, the hypotenuse is the length of the diagonal, and the two legs are the lengths of the sides of the rhombus.

Applying the Pythagorean theorem:
(15/2)^2 + (d/2)^2 = (24/2)^2
225/4 + d^2/4 = 144
225 + d^2 = 576
d^2 = 576 - 225
d^2 = 351

Taking the square root of both sides:
d = √351
d ≈ 18.7 cm (rounded to the nearest tenth)

Step 3: Choose the correct option.
The question asks for the length of the other diagonal, so the answer is approximately 18.7 cm, which is closest to option (c) 18 cm.

Therefore, the correct answer is option (c) 18 cm.

The figure formed by joining the mid-points of the adjacent sides of a square is 
  • a)
    Parallelogram
  • b)
    Rectangle 
  • c)
    Rhombus
  • d)
    Square 
Correct answer is option 'D'. Can you explain this answer?

P, Q, R and S are the mid-points of BA, BC, CD and DA respectively.

∴ AP = AS = PB = BQ = QC

∴ In ΔAPS
AP = AS

Similarly
Similarly ∠ASP = ∠APS =∠BPQ = ∠BQP = ∠CQR
= ∠CRQ = ∠DSR = ∠DRS = 45°
Now ∠P + ∠ASP + ∠APS = 180°
⇒ ∠P = 90°
Similarly,
∠P = ∠Q = ∠R = ∠S = 90°
∴ PQRS is a parallelogram having each of its angles = 90°
Now
using midpoint theorem in DABC and DACD
SR = PQ = 1/2 AC, and in DS ABD and BDC

∴ SP = PQ = QR = RS
∴ PQRS is a square

The resulting figure obtained from joining the consecutive mid points of side of a square is
  • a)
    Rectangle
  • b)
    Square 
  • c)
    Trapezium
  • d)
    Rhombus 
Correct answer is option 'B'. Can you explain this answer?

Prerna Chavan answered
There are several ways to approach this problem, but one of the most straightforward methods is to draw a square and label its sides and midpoints. Let's go through the solution step by step.

Step 1: Draw a square
Start by drawing a square with all sides of equal length. Label the four corners as A, B, C, and D.

Step 2: Label the midpoints
Next, label the midpoints of each side of the square. Let's call the midpoint on AB as E, BC as F, CD as G, and DA as H.

Step 3: Join the midpoints
Now, join the midpoints consecutively. That is, join E and F, F and G, G and H, and finally, H and E.

Step 4: Observe the resulting figure
Take a moment to observe the resulting figure formed by joining the consecutive midpoints. You will notice that it is a smaller square inside the original square.

Step 5: Identify the shape
Based on our observation, we can conclude that the resulting figure obtained from joining the consecutive midpoints of the sides of a square is another square. Therefore, the correct answer is option 'B' - Square.

Explanation:
When we join the consecutive midpoints of the sides of a square, we are essentially connecting the midpoints of each side. This creates a smaller square inside the original square. This smaller square shares the same center and orientation as the original square, but its sides are shorter in length. Therefore, the resulting figure is another square. This can be proven mathematically as well using properties of similar triangles and the fact that the diagonals of a square bisect each other at right angles.

In conclusion, the correct answer is option 'B' - Square.

Two opposite angles of a parallelogram are (3x - 2)° and (50 - x)°. Find the smallest angle.
  • a)
    37°
  • b)
    43° 
  • c)
    47°
  • d)
    57°
Correct answer is option 'A'. Can you explain this answer?

∵ The opposite angles of a parallelogram are equal.
∴ (3x-2)° = (50 -x)°
⇒  4x = 52°
⇒ x = 13°
∴ (3x - 2)° = 37°
∴ (50 - x)° = 37°

In ΔABC, AD is the median through A and E is the mid-point of AD. BE produced meets AC in F. then which of the following is correct? 

  • a)
  • b)
  • c)
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Rohit Sharma answered
∵ AD is the median of ΔABC
∴ BD = DC
Through D, draw DR || BF

Now, in ΔBFC,
DR || BF and D is the mid-point of BC
∴ R should be the mid-point of FC (according to converse of mid-point theorem)
∴ FR = RC ...(i)
Similarly, in ΔADR
E is the mid-point of AD and EF || DR
∴ F should be the mid-point of AR
∴ FR = AF ...(ii)
Using (i) and (ii)
FR = RC = AF
⇒ AC = 3AF
⇒ 

P is the mid-point of side AB of parallelogram ABCD. A line drawn from B parallel to PD meets CD at Q and AD produce at R, then which of the following is correct?
  • a)
    AR = 1/2BC
  • b)
    BR = 2BQ
  • c)
    BR = 1/3 BQ
  • d)
    AR = 1/3 BC
Correct answer is option 'B'. Can you explain this answer?

In △ARB, P is the mid-point of AB and PD is a parallel to BR.
∴ D will be the mid-point of AR.
i.e.   AR = 2AD
But ABCD is a parallelogram.
∴   AD = BC
Therefore,   AR = 2BC
∴ ABCD is a parallelogram.
⟹   DC ∥ AB
⟹   DQ ∥ AB
In △RAB
D is the mid-point of RA.
and DQ ∥ AB
∴ Q is the mid-point of RB.
⟹   BR = 2BQ

The angles of a quadrilateral are in the ratio 2:4:5:7. What is the difference between largest and smallest angle? 
  • a)
    80°
  • b)
    100°
  • c)
    60°
  • d)
    90°
Correct answer is option 'B'. Can you explain this answer?

Let the angles be 2x, 4x,5x and 7x respectively.
∴ Difference between largest and smallest angle = lx - 2x = 5x
∵ Sum of all angles of a quadrilateral = 360°
⇒ 2x + 4x + 5x + lx = 360°
⇒ 18x=360°
⇒ x = 20°
∴ Required difference
= 7x - 2x = 5x
= 5 x 20° = 100°

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