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Statistics MCQs for Class 9 Exam
It covers all Important Questions with answers on Statistics for the Class 9 exam. The questions are based on important topics. Details about the questions:- Topic: Statistics
- Type of Questions: MCQs with solutions
- Number of Questions: 50
- You can attempt them on EduRev to score high in Class 9 exam.
Class mark of a particular class is 9.5 and the class size is 6, then the class interval is- a)15.5-27.5
- b)12.5-18.5
- c)3.5-15.5
- d)6.5-12.5
Correct answer is option 'D'. Can you explain this answer?
Class mark of a particular class is 9.5 and the class size is 6, then the class interval is
a)
15.5-27.5
b)
12.5-18.5
c)
3.5-15.5
d)
6.5-12.5
 | Anita Menon answered |
Class mark = 9.5
=> Upper limit + Lower limit / 2 = 9.5
=> u + l = 19 -------(1)
Class mark = 6
=> u - l = 6 --------(2)
On adding equation 1 and 2, we get
2u = 25
=> u = 12.5
l = 6.5
Class interval is ( 6.5 - 12.5)
The class mark of class interval 60 – 70 will be- a)75
- b)65
- c)70
- d)60
Correct answer is option 'B'. Can you explain this answer?
The class mark of class interval 60 – 70 will be
a)
75
b)
65
c)
70
d)
60
 | Sarita Reddy answered |
class mark = [lower class interval + upper class interval]/2
= (60+70)/2
= 130/2
= 65
(if the intervals are of uniform width)
- a)2M – 1
- b)2M2+1
- c)2M2−1
- d)2M + 1
Correct answer is option 'C'. Can you explain this answer?
a)
2M – 1
b)
2M2+1
c)
2M2−1
d)
2M + 1
 | Rohini Seth answered |
If the mean of x and 1/2 is M. then the mean of
x² and 1/x² is
Mean of x and 1/x is M. So
( x +1/x)/2=M
Squaring on both sides,
(x +1/x)²/2²=M²
(x² + 1/x²+2*x*1/x)/4=M²
x²+1/x²+2=4 m²
x²+ 1/x²=4m²-2
Dividing by 2 on both sides,
(x²+1/x²)/2=(4m²-2)/2
= (x²+1/x²)/2 =2 *(2m²-1)/2=2m²-1
=Mean of x² and 1/x²=(2m²-1)
x² and 1/x² is
Mean of x and 1/x is M. So
( x +1/x)/2=M
Squaring on both sides,
(x +1/x)²/2²=M²
(x² + 1/x²+2*x*1/x)/4=M²
x²+1/x²+2=4 m²
x²+ 1/x²=4m²-2
Dividing by 2 on both sides,
(x²+1/x²)/2=(4m²-2)/2
= (x²+1/x²)/2 =2 *(2m²-1)/2=2m²-1
=Mean of x² and 1/x²=(2m²-1)
One of the sides of a frequency polygon is- a)either of the coordinate axes
- b)the x-axis
- c)neither of the coordinate axes
- d)the y-axis
Correct answer is option 'B'. Can you explain this answer?
One of the sides of a frequency polygon is
a)
either of the coordinate axes
b)
the x-axis
c)
neither of the coordinate axes
d)
the y-axis
 | Learners World answered |
The x-axis is one of the sides of a frequency polygon. The x-axis represents the values of the variable being measured.
Direction: Ladli Scheme was launched by the Delhi Government in the year 2008. This scheme helps to make women strong and will empower a girl child. This scheme was started in 2008.
Read the above bar graph and answer the following questions :
Q. What was the difference in budget in the year 2008 - 09 and 2009 - 10?- a)100 Million
- b)1000 Million
- c)50 Million
- d)150 Million
Correct answer is option 'A'. Can you explain this answer?
Direction: Ladli Scheme was launched by the Delhi Government in the year 2008. This scheme helps to make women strong and will empower a girl child. This scheme was started in 2008.
Read the above bar graph and answer the following questions :
Q. What was the difference in budget in the year 2008 - 09 and 2009 - 10?
a)
100 Million
b)
1000 Million
c)
50 Million
d)
150 Million
| | Swati Verma answered |
2008 - 09 = 9060
2009 - 10 = 9160
= 9160 - 9060 = 100.
Direction: India's national animal Tiger (which has also been under the radar of the government as its population declined in the country) has witnessed an increase in its population.A survey was done by the Ministry of Environment, Forests and Climate change, according to which tiger population is on rise at the rate of 6 per cent every year from 2006 and 2018.
Pranav has found a report on status of tigers in India in last 100 years. He has some queries as follow :Q. In which year, number of tigers were maximum?- a)1960
- b)2002
- c)2007
- d)1900
Correct answer is option 'D'. Can you explain this answer?
Direction: India's national animal Tiger (which has also been under the radar of the government as its population declined in the country) has witnessed an increase in its population.
A survey was done by the Ministry of Environment, Forests and Climate change, according to which tiger population is on rise at the rate of 6 per cent every year from 2006 and 2018.
Pranav has found a report on status of tigers in India in last 100 years. He has some queries as follow :
Q. In which year, number of tigers were maximum?
a)
1960
b)
2002
c)
2007
d)
1900
| | Swati Verma answered |
In 1900, number of tigers were maximum.
Class mark of a particular class is 9.5 and the class size is 6, then the class interval is- a)3.5-15.5
- b)12.5-18.5
- c)15.5-27.5
- d)6.5-12.5
Correct answer is option 'D'. Can you explain this answer?
Class mark of a particular class is 9.5 and the class size is 6, then the class interval is
a)
3.5-15.5
b)
12.5-18.5
c)
15.5-27.5
d)
6.5-12.5
| | Gayatri Choudhary answered |
To determine the class interval, we need to know the range of the data and the number of class intervals.
In this case, the class mark is given as 9.5 and the class size is 6. The class mark represents the midpoint of the class interval, which means that the lower limit of the class interval is 9.5 - 0.5 = 9 and the upper limit is 9.5 + 0.5 = 10.
Let's calculate the range of the data:
Range = Upper Limit - Lower Limit
Range = 10 - 9
Range = 1
Since the range is 1 and there are 6 class intervals, we can divide the range by the number of class intervals to determine the class interval size:
Class Interval Size = Range / Number of Class Intervals
Class Interval Size = 1 / 6
Class Interval Size = 0.1667
Now, we can determine the class intervals:
First Class Interval: 9 - 9.1667
Second Class Interval: 9.1667 - 9.3333
Third Class Interval: 9.3333 - 9.5
Fourth Class Interval: 9.5 - 9.6667
Fifth Class Interval: 9.6667 - 9.8333
Sixth Class Interval: 9.8333 - 10
As we can see, the class interval that includes the class mark of 9.5 is 9.5 - 9.6667. Therefore, the correct answer is option D) 6.5-12.5.
It is important to note that the other options given are incorrect because they do not include the class mark of 9.5 within the range of the class intervals.
In this case, the class mark is given as 9.5 and the class size is 6. The class mark represents the midpoint of the class interval, which means that the lower limit of the class interval is 9.5 - 0.5 = 9 and the upper limit is 9.5 + 0.5 = 10.
Let's calculate the range of the data:
Range = Upper Limit - Lower Limit
Range = 10 - 9
Range = 1
Since the range is 1 and there are 6 class intervals, we can divide the range by the number of class intervals to determine the class interval size:
Class Interval Size = Range / Number of Class Intervals
Class Interval Size = 1 / 6
Class Interval Size = 0.1667
Now, we can determine the class intervals:
First Class Interval: 9 - 9.1667
Second Class Interval: 9.1667 - 9.3333
Third Class Interval: 9.3333 - 9.5
Fourth Class Interval: 9.5 - 9.6667
Fifth Class Interval: 9.6667 - 9.8333
Sixth Class Interval: 9.8333 - 10
As we can see, the class interval that includes the class mark of 9.5 is 9.5 - 9.6667. Therefore, the correct answer is option D) 6.5-12.5.
It is important to note that the other options given are incorrect because they do not include the class mark of 9.5 within the range of the class intervals.
The mean of five observations is 15. If the mean of first three observations is 14 and that of last three is 17, then the third observation is- a)29
- b)31
- c)32
- d)18
Correct answer is option 'D'. Can you explain this answer?
The mean of five observations is 15. If the mean of first three observations is 14 and that of last three is 17, then the third observation is
a)
29
b)
31
c)
32
d)
18
 | Naina Sharma answered |
⇒ It is given that Mean of 5 observations is 15.
∴ The sum of observations =15×5=75.
∴ It is given that mean of the first 3 observations is 14.
∴ The sum of first three observations =14×3=42.
⇒ Given that mean of the last 3 observations is 17.
∴ The sum of the last three observations =17×3=51
∴ The third observation =(42+51)−75
=93−75
=93−75
=18
The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is- a)15
- b)40
- c)25
- d)35
Correct answer is option 'D'. Can you explain this answer?
The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is
a)
15
b)
40
c)
25
d)
35
 | Vikas Kapoor answered |
Let x and y be the upper and lower class limit of frequency distribution.
Given, width of the class = 5
⇒ x-y= 5 …(i)
Also, given lower class (y) = 10 On putting y = 10 in Eq. (i), we get
x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15.
Hence, the upper class limit of the highest class
=(Number of continuous classes x Class width + Lower class limit of the lowest class)
= 5 x 5+10 = 25+10=35
Hence,’the upper class limit of the highest class is 35.
Alternate Method
After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.
Thus, the highest class is 30-35,
Hence, the upper limit of this class is 35.
Given, width of the class = 5
⇒ x-y= 5 …(i)
Also, given lower class (y) = 10 On putting y = 10 in Eq. (i), we get
x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15.
Hence, the upper class limit of the highest class
=(Number of continuous classes x Class width + Lower class limit of the lowest class)
= 5 x 5+10 = 25+10=35
Hence,’the upper class limit of the highest class is 35.
Alternate Method
After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.
Thus, the highest class is 30-35,
Hence, the upper limit of this class is 35.
Direction: Child labour refers to any work or activity that deprives children of their childhood. It is a violation of children's rights. This can harm them mentally or physically. It also exposes them to hazardous situations or stop them from going to school. Naman got data on number of child labours (in million) in different country that is given below.
Q. Name the country which has 1 million child labour.- a)Mexico
- b)Kenya
- c)Peru
- d)India
Correct answer is option 'B'. Can you explain this answer?
Direction: Child labour refers to any work or activity that deprives children of their childhood. It is a violation of children's rights. This can harm them mentally or physically. It also exposes them to hazardous situations or stop them from going to school. Naman got data on number of child labours (in million) in different country that is given below.
Q. Name the country which has 1 million child labour.
a)
Mexico
b)
Kenya
c)
Peru
d)
India
| | Swati Verma answered |
Kenya has 1 million child labour.
A student collects information about the number of school going children in a locality consisting of a hundred households. The data collected by him is- a)Arrayed data
- b)Grouped data
- c)Primary data
- d)Secondary data
Correct answer is option 'C'. Can you explain this answer?
A student collects information about the number of school going children in a locality consisting of a hundred households. The data collected by him is
a)
Arrayed data
b)
Grouped data
c)
Primary data
d)
Secondary data
 | Rajdeep Majumdar answered |
Primary Data in Statistics
Primary data is the data that is collected firsthand by the researcher himself for a specific research purpose. It is original data that has not been processed or analyzed by anyone else. The researcher collects primary data by conducting surveys, experiments, observations, or interviews.
Explanation:
In the given scenario, a student collects information about the number of school going children in a locality consisting of a hundred households. This information is collected by the student himself for a specific research purpose, making it primary data. The data is collected through surveys or interviews conducted by the student.
Option C is the correct answer as it refers to primary data. Option A, arrayed data, refers to data that is arranged in a specific sequence or order. Option B, grouped data, refers to data that is organized into groups or categories for analysis. Option D, secondary data, refers to data that has already been collected and processed by someone else for a different research purpose.
Primary data is the data that is collected firsthand by the researcher himself for a specific research purpose. It is original data that has not been processed or analyzed by anyone else. The researcher collects primary data by conducting surveys, experiments, observations, or interviews.
Explanation:
In the given scenario, a student collects information about the number of school going children in a locality consisting of a hundred households. This information is collected by the student himself for a specific research purpose, making it primary data. The data is collected through surveys or interviews conducted by the student.
Option C is the correct answer as it refers to primary data. Option A, arrayed data, refers to data that is arranged in a specific sequence or order. Option B, grouped data, refers to data that is organized into groups or categories for analysis. Option D, secondary data, refers to data that has already been collected and processed by someone else for a different research purpose.
A set of data consists of six numbers: 7, 8, 8, 9, 9 and x. The difference between the modes when x = 9 and x = 8 is- a)1
- b)4
- c)3
- d)2
Correct answer is option 'A'. Can you explain this answer?
A set of data consists of six numbers: 7, 8, 8, 9, 9 and x. The difference between the modes when x = 9 and x = 8 is
a)
1
b)
4
c)
3
d)
2
| | Dhwani Shah answered |
**Solution:**
To find the difference between the modes when x = 9 and x = 8, we need to determine the modes for both scenarios and then calculate the difference between them.
Given data set: 7, 8, 8, 9, 9, x
**When x = 9:**
In this case, the data set becomes: 7, 8, 8, 9, 9, 9
The modes are the numbers that appear most frequently in the data set. In this case, the modes are 8 and 9, as they both appear twice.
**When x = 8:**
In this case, the data set becomes: 7, 8, 8, 9, 9, 8
The modes are the numbers that appear most frequently in the data set. In this case, the modes are 8 and 9, as they both appear twice.
Therefore, the modes are the same for both scenarios: 8 and 9.
**Calculating the difference between the modes:**
To calculate the difference between the modes, we subtract the smaller mode from the larger mode.
In this case, the smaller mode is 8 and the larger mode is 9.
Difference = 9 - 8 = 1
Therefore, the difference between the modes when x = 9 and x = 8 is 1.
Hence, the correct answer is option A.
To find the difference between the modes when x = 9 and x = 8, we need to determine the modes for both scenarios and then calculate the difference between them.
Given data set: 7, 8, 8, 9, 9, x
**When x = 9:**
In this case, the data set becomes: 7, 8, 8, 9, 9, 9
The modes are the numbers that appear most frequently in the data set. In this case, the modes are 8 and 9, as they both appear twice.
**When x = 8:**
In this case, the data set becomes: 7, 8, 8, 9, 9, 8
The modes are the numbers that appear most frequently in the data set. In this case, the modes are 8 and 9, as they both appear twice.
Therefore, the modes are the same for both scenarios: 8 and 9.
**Calculating the difference between the modes:**
To calculate the difference between the modes, we subtract the smaller mode from the larger mode.
In this case, the smaller mode is 8 and the larger mode is 9.
Difference = 9 - 8 = 1
Therefore, the difference between the modes when x = 9 and x = 8 is 1.
Hence, the correct answer is option A.
In a bar graph, 0.25 cm length of a bar represents 100 people. Then, the length of bar which represents 2000 people is- a)5 cm
- b)4 cm
- c)4.5 cm
- d)3.5 cm
Correct answer is option 'A'. Can you explain this answer?
In a bar graph, 0.25 cm length of a bar represents 100 people. Then, the length of bar which represents 2000 people is
a)
5 cm
b)
4 cm
c)
4.5 cm
d)
3.5 cm
 | Charvi Tiwari answered |
Given, 0.25 cm represents 100 people.
To find the length of the bar that represents 2000 people, we need to use the concept of proportionality.
Let x be the length of the bar that represents 2000 people.
We know that,
0.25 cm represents 100 people
So,
x cm represents 2000 people
Using the concept of proportionality, we can write:
0.25/100 = x/2000
Simplifying the above equation, we get:
x = (0.25 x 2000)/100
x = 5 cm
Therefore, the length of the bar that represents 2000 people is 5 cm.
Hence, the correct option is (a) 5 cm.
To find the length of the bar that represents 2000 people, we need to use the concept of proportionality.
Let x be the length of the bar that represents 2000 people.
We know that,
0.25 cm represents 100 people
So,
x cm represents 2000 people
Using the concept of proportionality, we can write:
0.25/100 = x/2000
Simplifying the above equation, we get:
x = (0.25 x 2000)/100
x = 5 cm
Therefore, the length of the bar that represents 2000 people is 5 cm.
Hence, the correct option is (a) 5 cm.
A data is such that its maximum value is 75 and range is 20, then the minimum value is- a)20
- b)55
- c)75
- d)95
Correct answer is option 'B'. Can you explain this answer?
A data is such that its maximum value is 75 and range is 20, then the minimum value is
a)
20
b)
55
c)
75
d)
95
| | Aditya Shah answered |
Let minimum value be x ,
So,
75 - x = 20
x = 75 - 20
x = 55
So,
75 - x = 20
x = 75 - 20
x = 55
In a bar graph, 0.25 cm length of a bar represents 100 people. Then, the length of bar which represents 2000 people is- a)4 cm
- b)4.5 cm
- c)5 cm
- d)3.5 cm
Correct answer is option 'C'. Can you explain this answer?
In a bar graph, 0.25 cm length of a bar represents 100 people. Then, the length of bar which represents 2000 people is
a)
4 cm
b)
4.5 cm
c)
5 cm
d)
3.5 cm
| | Vikram Khanna answered |
To find the length of a bar that represents 2000 people in a bar graph, you can use the following steps:
Identify the scale of the bar graph: In this case, the scale of the bar graph is 0.25 cm per 100 people.
Calculate the number of units on the scale: To find the number of units on the scale, you can divide the number of people by the number of people per unit. In this case, you would divide 2000 people by 100 people/unit = 20 units.
Multiply the number of units by the length of each unit: To find the length of the bar, you can multiply the number of units by the length of each unit. In this case, the length of the bar would be 20 units * 0.25 cm/unit = 5 cm.
Therefore, the length of a bar that represents 2000 people in this bar graph is 5 cm. The correct answer is option (c).
If the class marks in a frequency distribution are 19.5, 26.5, 33.5, 40.5 then the class corresponding to the class mark 33.5 is:- a)37 – 41
- b)30 – 37
- c)23 – 30
- d)16 – 23
Correct answer is option 'B'. Can you explain this answer?
If the class marks in a frequency distribution are 19.5, 26.5, 33.5, 40.5 then the class corresponding to the class mark 33.5 is:
a)
37 – 41
b)
30 – 37
c)
23 – 30
d)
16 – 23
 | Saanvi Sen answered |
B)The class corresponding to the class mark 33.5 is 31-36.
This is because the class marks represent the midpoint of each class interval, and we can see that the class interval containing 33.5 as its midpoint is 31-36. Therefore, the class corresponding to the class mark 33.5 is 31-36.
This is because the class marks represent the midpoint of each class interval, and we can see that the class interval containing 33.5 as its midpoint is 31-36. Therefore, the class corresponding to the class mark 33.5 is 31-36.
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