Function Generator & 555 Timer MCQs for Electronics and Communication Engineering (ECE) Exam

It covers all Important Questions with answers on Function Generator & 555 Timer for the Electronics and Communication Engineering (ECE) exam. The questions are based on important topics. Details about the questions:
  • Topic: Function Generator & 555 Timer
  • Type of Questions: MCQs with solutions
  • Number of Questions: 20
  • You can attempt them on EduRev to score high in Electronics and Communication Engineering (ECE) exam.

In a multivibrator, both the output states are quasi stable. The output varies from state to state and the circuit acts like a free running square wave oscillator. The type of multivibrator is
  • a)
    monostable
  • b)
    single process
  • c)
    bistable
  • d)
    astable
Correct answer is option 'D'. Can you explain this answer?

Sarita Yadav answered
Astable Multivibrator:
  • An Astable multivibrator is such a circuit that it automatically switches between the two states continuously without the application of any external pulse for its operation, i.e. it is unstable in any state.
  • As this produces a continuous square wave output, it is called a free-running multivibrator.
A Monostable multivibrator has a stable state and a quasi-stable state. This has a trigger input to one transistor. So, one transistor changes its state automatically, while the other one needs a trigger input to change its state.
A Bistable multivibrator has both the two states stable. It requires two trigger pulses to be applied to change the states. Until the trigger input is given, this multivibrator cannot change its state.

A tank circuit contains an inductance of 1 mH. What is the range of tuning capacitor value if the resonant frequency ranges from (540-1650) kHz?
  • a)
    3.0 pF ≤ C≤ 75 pF
  • b)
    9.3 pF≤ C≤ 86.86 pF
  • c)
    3.0 pF ≤ C≤ 86.86 pF
  • d)
    9.3 p F ≤ C ≤ 75.0 pF
Correct answer is option 'B'. Can you explain this answer?

Urvi Khanna answered
The resonant frequency of a tank circuit is given by the formula:

f = 1 / (2π√(LC))

Where f is the resonant frequency, L is the inductance, and C is the capacitance.

Given L = 1 mH and the resonant frequency range of (540-1650) kHz, we can calculate the range of tuning capacitor value.

For the lower resonant frequency of 540 kHz:

f = 540 kHz = 540 * 10^3 Hz

1 / (2π√(L * C)) = 540 * 10^3

√(L * C) = 1 / (2π * 540 * 10^3)

L * C = (1 / (2π * 540 * 10^3))^2

C = (1 / (2π * 540 * 10^3))^2 / L

C ≈ 3.0 pF

For the upper resonant frequency of 1650 kHz:

f = 1650 kHz = 1650 * 10^3 Hz

1 / (2π√(L * C)) = 1650 * 10^3

√(L * C) = 1 / (2π * 1650 * 10^3)

L * C = (1 / (2π * 1650 * 10^3))^2

C = (1 / (2π * 1650 * 10^3))^2 / L

C ≈ 0.984 pF

Therefore, the range of tuning capacitor value is approximately 0.984 pF to 3.0 pF.

The most popular IC used in timing circuit is
  • a)
    555
  • b)
    741
  • c)
    LM317
  • d)
    7400
Correct answer is option 'A'. Can you explain this answer?

555 timer:
The 555 timer IC is an integrated circuit used in a variety of timer, pulse generation, and oscillator applications.
It has three operating modes
  • Astable mode: In this mode, the 555 IC can be used as an oscillator, pulse generator, logic clocks, etc.
  • Monostable mode: In this mode, the 555 functions as a ‘one-shot’ pulse generator and finds uses in frequency divider, timers, pulse detection, touch switches.
  • Bistable mode: In this mode, the 555 IC can be operated as a flip-flop, latches.555 timer IC with the
    of pins is shown below:

Consider the following statements regarding 555 timer:
1. It operates on -5 V to +18 V supply voltage in both free running and one-shot modes.
2. It has a high current output and it can source or sink 500 mA.
3. The output can drive TTL and has a temperature stability of 80 parts per million (ppm) per degree celsius change in temperature or equivalently 0.008 %/°C.
Which of the above statements are not correct?
  • a)
    1 and 2 only
  • b)
    1 and 3 only
  • c)
    1, 2 and 3
  • d)
    2 and 3 only
Correct answer is option 'A'. Can you explain this answer?

Ravi Singh answered
555 Timer IC:
  • The 555 timer chip is extremely robust and stable 8-pin device.
  • It can be operated either as a very accurate Monostable, Bistable or Astable Multivibrator to produce a variety of applications such as one-shot or delay timers, pulse generation, LED and lamp flashers, alarms and tone generation, logic clocks, frequency division, power supplies and converters etc.
Pin Diagram:
Characteristics of 555 timer IC:
  • Typical operating voltage is +5V, can withstand a maximum of +18V.
  • The source/sink current of the output pin is 200mA.
  • Consumes up to 3mA when operating at +5V.
  • Trigger Voltage is 1.67 when operating at +5V.
  • Operating Temperature is 70 degree Celsius.
  • Available in 8-pin PDIP, SOIC, and VSSOP packages.

What is the most popular IC used in timing circuits?
  • a)
    741
  • b)
    317
  • c)
    340
  • d)
    555
Correct answer is option 'D'. Can you explain this answer?

555 timer is one of the most popular IC used in timing circuits.
It is an integrated circuit used in a variety of timer, pulse generation, and oscillator applications.
The Pin configuration of IC-555 is as shown:
  • Pin 5 of 555 Timer is the control pin. 
  • This makes the oscillator cycle more consistent.
  • This pin can also be used to change the internal voltage reference to allow modifying the oscillator frequency or duty cycle.
It has three operating modes:
  • Astable Mode: In this mode, the 555 IC can be used as an oscillator, pulse generator, logic clocks, etc.
  • Monostable mode: In this mode, the 555 functions as a ‘one-shot’ pulse generator and finds use in frequency divider, timers, pulse detection, touch switches.
  • Bistable mode: In this mode, the 555 IC can be operated as a flip-flop, latches.

For trigger voltage less than 1/3 Vcc, the output of IC 555 is:
  • a)
    -1
  • b)
    infinite
  • c)
    low
  • d)
    high
Correct answer is option 'D'. Can you explain this answer?

  • A low voltage (less than 1/3 the supply voltage) applied for short time to the trigger input that cause output go high.
  • The output will remain high until a high voltage is applied to the threshold input.
  • In output low state the voltage will be close to 0 V. 

Which of the following are the basic elements in a 555 timer IC?
(a) Two comparators
(b) A flip-flop
(c) A discharge transistor
(d) A resistive voltage divider
  • a)
    (a), (b) and (d)
  • b)
    only (a), (b) and (c)
  • c)
    only (b), (c) and (d)
  • d)
    only (a), (b), (c) and (d)
Correct answer is option 'D'. Can you explain this answer?

Sarita Yadav answered
The 555 timer is one of the most popular IC used in timing circuits.
It is an integrated circuit used in a variety of timer, pulse generation, and oscillator applications.
The Pin configuration of IC-555 is as shown:
  • Pin 5 of 555 Timer is the control pin. 
  • This makes the oscillator cycle more consistent.
  • This pin can also be used to change the internal voltage reference to allow modifying the oscillator frequency or duty cycle.
  • The single 555 Timer chip in its basic form is a Bipolar 8-pin mini DIP device.
  • It consists of 25 transistors, 2 diodes, 16 registers to form two comparators, a flip-flop, and high current output.
  • Pin 7 is called a Discharge pin which is connected directly to the collector of an internal NPN transistor which is used to “discharge” the timing capacitor to the ground when the output at pin 3 switches low.
  • The 555 Timer’s name is derived as there are three 5 kΩ resistors connected internally producing a voltage divider network between the supply voltage at pin 8 and ground at pin 1.

The control terminal (pin5) of 555 timer IC is normally connected to ground through a capacitor (∼ 0.01μF). This is to
  • a)
    protect the IC from inadvertent application of high voltage
  • b)
    prevent false triggering by noise coupled onto the pin
  • c)
    convert the trigger input to sharp pulse by differentiation
  • d)
    suppress any negative triggering pulse
Correct answer is option 'B'. Can you explain this answer?

Sarita Yadav answered
Control pin of 555 Timer:
The control pin on the 555 timers is normally connected to the ground through a capacitor (∼ 0.01μF because the noise from the supply line can ride through this simple divider adding small capacitor filters out high-frequency noise that can cause the comparison point to vary slightly
  • Pin 5 of 555 Timer is the control pin. 
  • This makes the oscillator cycle more consistent.
  • This pin can also be used to change the internal voltage reference to allow modifying the oscillator frequency or duty cycle.
IC 555 has three operating modes namely:
  • Bistable mode or Schmitt Trigger
  • Monostable Mode: In this mode, the 555 functions as a pulse generator.
  • Astable(Free running) Mode: In this mode, the 555 operates as an oscillator.

The 555 timer can be used in which of the following configurations?
  • a)
    astable, monostable
  • b)
    monostable, bistable
  • c)
    astable, toggled
  • d)
    bistable, tristable
Correct answer is option 'A'. Can you explain this answer?

Krish Mehta answered
The 555 timer is a versatile integrated circuit that can be used in various configurations to generate and control timing signals. Out of the given options, the correct answer is option 'A', which states that the 555 timer can be used in astable and monostable configurations.

Astable Configuration:
----------------------
In the astable configuration, the 555 timer operates in a free-running mode, continuously producing a square wave output signal without any external trigger. This configuration is commonly used to generate clock signals, frequency generators, and timing signals in various electronic circuits. The timing of the output signal is determined by the values of resistors and capacitors connected to the 555 timer.

Monostable Configuration:
-------------------------
In the monostable configuration, the 555 timer is triggered by an external input and produces a single pulse of a fixed duration. This configuration is commonly used in applications such as timers, pulse generators, and one-shot circuits. The duration of the output pulse is determined by the values of resistors and capacitors connected to the 555 timer.

Explanation:
--------------
The 555 timer is a highly versatile integrated circuit that can be used in multiple configurations to suit various timing requirements in electronic circuits. The two configurations mentioned in option 'A' cover the most commonly used modes of operation for the 555 timer.

The astable configuration allows the 555 timer to continuously produce a square wave output signal without any external trigger. This is achieved by connecting resistors and capacitors to the timer in a specific arrangement. The timing of the output signal, including the frequency and duty cycle, can be controlled by the values of these external components. This makes the astable configuration of the 555 timer useful in applications where a continuous timing signal is required, such as clock generators or frequency generators.

The monostable configuration, on the other hand, triggers the 555 timer with an external input and produces a single pulse of a fixed duration as the output. This configuration is widely used in applications where a precise and controlled timing pulse is required, such as timers, pulse generators, or one-shot circuits. The duration of the output pulse is determined by the values of resistors and capacitors connected to the 555 timer. Once triggered, the output pulse remains active for the specified duration before returning to its stable state.

Conclusion:
--------------
In conclusion, the 555 timer can be used in astable and monostable configurations, allowing it to generate continuous timing signals or precise pulses depending on the application requirements. These configurations make the 555 timer a versatile and commonly used component in various electronic circuits.

A multivibrator is a circuit which generates
  • a)
    Square wave
  • b)
    Sine wave
  • c)
    Triangular wave
  • d)
    Sawtooth wave
Correct answer is option 'A'. Can you explain this answer?

Krish Mehta answered
Introduction:
A multivibrator is a type of electronic circuit that generates a continuous output signal with a specific waveform. It is commonly used in various applications such as timing circuits, frequency generation, and waveform generation. There are different types of multivibrators, including astable, monostable, and bistable multivibrators. In this case, we are discussing the astable multivibrator, which generates a square wave.

Astable Multivibrator:
An astable multivibrator is a free-running oscillator circuit that does not require any external triggering. It continuously switches between two stable states, producing a square wave output. This circuit consists of two cross-coupled amplifiers (usually transistors) with positive feedback.

Working Principle:
The astable multivibrator operates based on the principles of positive feedback and regenerative switching. Let's understand the working principle step by step:

1. Initial State: Assume one transistor is conducting (ON state) while the other is in cutoff (OFF state). The capacitor connected to the collector of the conducting transistor starts charging through the resistor.

2. Charging Period: As the capacitor charges, the voltage across it gradually increases. This causes the conducting transistor to enter the cutoff state, and the other transistor starts conducting. The charging process continues until the voltage across the capacitor reaches a certain threshold.

3. Discharging Period: Once the threshold voltage is reached, the capacitor starts discharging through the resistor connected to the collector of the newly conducting transistor. As the capacitor voltage decreases, the conducting transistor eventually enters cutoff, and the other transistor starts conducting again.

4. Cycle Repeats: The discharging process continues until the voltage across the capacitor reaches a lower threshold. At this point, the capacitor starts charging again, and the cycle repeats.

Output Waveform:
The astable multivibrator produces a square wave output, which has a constant amplitude and alternates between two voltage levels (high and low). During the charging period, the output is high (corresponding to the conducting transistor), and during the discharging period, the output is low (corresponding to the cutoff transistor). This continuous switching between high and low states generates a square wave.

Conclusion:
In conclusion, a multivibrator is a circuit that generates a specific waveform. In the case of an astable multivibrator, it produces a square wave output. The working principle involves the continuous switching between two stable states, resulting in the generation of a square wave with a constant amplitude and alternating voltage levels.

The output of the IC 555 is ______ when the reset pin is connected to low voltage.
  • a)
    zero
  • b)
    high
  • c)
    normal
  • d)
    tri-state
Correct answer is option 'A'. Can you explain this answer?

Ravi Singh answered
Concept:
Pin diagram of 555 timer IC
Pin 1 - Ground 
This pin is connected to the ground of the circuit 
Pin 2 - Trigger
The trigger pin is used to feed the trigger input to the 555 IC is set up as a monostable multivibrator. This pin is an inverting input of a comparator and is responsible for the transition of flip-flops from set to reset. The output of the timer depends on the amplitude of the external trigger pulse applied to this pin.
Pin 3 - Output
The output of the timer is present at pin 3. load can be connected at the output. 
​Pin 4 - Reset pin
Whenever the timer IC is to be reset, a negative pulse (low voltage) is applied to reset the pin, the output is reset (Zero) irrespective of the input condition. (Option 1 is correct).
Pin 5 - Control voltage 
This pin provides access to the internal voltage divider (2/3 Vcc by default) By applying a voltage to this pin the timing characteristics can be changed.
Pin 6 - Threshold
when the voltage at this pin is greater than the voltage at CONTROL (2⁄3 VCC except when CONTROL is driven by an external signal), then the OUTPUT high state timing interval ends, causing the OUTPUT to go to the low state.
Pin 7 - Discharge
This pin can be used to discharge the capacitor between intervals, in phase with the output.
Pin 8 - Vcc
The positive supply voltage is usually between 3 and 15 depending on the variation.

Assertion (A): All oscillators require positive feedback for their operation.
Reason (R): Any circuit which is used to generate a periodic voltage without an a.c. input signal is called an oscillator.
  • a)
    Both A and R are true and R is the correct explanation of A.
  • b)
    Both A and R are true but R is not the correct explanation of A.
  • c)
    A is true but R is false.
  • d)
    A is false but R is true.
Correct answer is option 'D'. Can you explain this answer?

Aniket Ghoshal answered
Ail oscillators do not require positive feedback for their operation because if the positive resistance of the LC tank circuit is cancelled by introducing the right amount of negative resistance across the tank circuit, then the steady oscillation can be maintained. Some of the devices which possess negative resistance as mentioned above are dynatron, transitron, UJT and tunnel diode. Hence, assertion is not correct.

Each stage of a three stage amplifier without feedback has identical pole frequencies and its open loop transfer function is expressed as:
What is the maximum value of feedback factor βmax  for which the amplifier remains stable?
  • a)
  • b)
  • c)
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?

Partho Singh answered
The phase change may change Aβ to negative. This can happen only when the total change in the phase angle of  becomes 1800 . The  required phase change in one stage i.e   should be 600  or,  
 ∴ Here, ωc is the frequency at which the phase angle changes the sign. The value of Aβ at this frequency is

A 555 time basically operates in
  • a)
    monostable multivibrator mode
  • b)
    astable multivibrator mode
  • c)
    either as monostable or as an astable l + i i y“ J rs iiiuiuviuiaiui niuuc
  • d)
    none of the above
Correct answer is option 'C'. Can you explain this answer?

Inaya Reddy answered
Understanding the 555 Timer's Modes
The 555 timer is a versatile integrated circuit that can operate in two primary modes: monostable and astable multivibrator modes.
Monostable Multivibrator Mode
- In this mode, the 555 timer acts as a single-pulse generator.
- It produces a single output pulse when triggered by an external signal.
- The duration of the pulse can be adjusted using external resistors and capacitors.
- This mode is useful for applications like timers and pulse-width modulation.
Astable Multivibrator Mode
- In astable mode, the 555 timer continuously oscillates between high and low states, generating a square wave.
- It does not require an external trigger to operate and produces a continuous output.
- The frequency and duty cycle of the output waveform can be controlled by adjusting the external resistor and capacitor values.
- This mode is commonly used in clock pulses and waveform generation applications.
Operation in Both Modes
- The flexibility of the 555 timer allows it to be configured easily for either mode, making it a staple in electronics.
- Depending on the circuit configuration, it can perform various tasks, from simple timing applications to complex pulse modulation.
- This dual functionality is what makes the 555 timer so widely used in various electronic projects.
In summary, the correct answer is option 'C' because the 555 timer can operate effectively as either a monostable or astable multivibrator, catering to different circuit requirements in electronics and communication engineering.

Assertion (A): If the magnitude of loop gain of the amplifier is unity then the amplifier gives an a.c. output without any a.c. input signal.
Reason (R): The property of the regenerative feedback is utilised in oscillators.
  • a)
    Both A and R are true and R is the correct explanation of A.
  • b)
    Both A and R are true but R is not the correct explanation of A.'
  • c)
    A is true but R is false.
  • d)
    A is false but R is true.
Correct answer is option 'B'. Can you explain this answer?

The closed-iooD aain with positive feedback is
If the magnitude of loop gain i.e. |βA| - 1, then Af = ∞. Hence, the gain of the amplifier with positive feedback is infinite and the amplifier gives an a.c. output without any a.c. input signal. Thus, the amplifier acts as an oscillator. Regenerative or positive feedback is utilized in oscillators.
Hence, both assertion and reason are correct but reason is not the correct explanation of assertion.

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