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MOSFET Biasing & Amplifiers MCQs for Electronics and Communication Engineering (ECE) Exam
It covers all Important Questions with answers on MOSFET Biasing & Amplifiers for the Electronics and Communication Engineering (ECE) exam. The questions are based on important topics. Details about the questions:- Topic: MOSFET Biasing & Amplifiers
- Type of Questions: MCQs with solutions
- Number of Questions: 49
- You can attempt them on EduRev to score high in Electronics and Communication Engineering (ECE) exam.
(Q.5-Q.7) An NMOS amplifier is to be designed to provide a 0.50-V peak output signal across a 50-kΩ load that can be used as a drain resistor.If a gain of at least 5 V/V is needed, what value of gm is required?- a)0.1 mA/V
- b)0.2 mA/V
- c)0.4 mA/V
- d)0.8 mA/V
Correct answer is option 'A'. Can you explain this answer?
(Q.5-Q.7) An NMOS amplifier is to be designed to provide a 0.50-V peak output signal across a 50-kΩ load that can be used as a drain resistor.
If a gain of at least 5 V/V is needed, what value of gm is required?
a)
0.1 mA/V
b)
0.2 mA/V
c)
0.4 mA/V
d)
0.8 mA/V
 | Saptarshi Nair answered |
gmRd = 5 or gm= 5/50 mA/V.
The MOSFET combines the areas of _______ & _________- a)field effect & MOS technology
- b)semiconductor & TTL
- c)mos technology & CMOS technology
- d)none of the mentioned
Correct answer is option 'A'. Can you explain this answer?
The MOSFET combines the areas of _______ & _________
a)
field effect & MOS technology
b)
semiconductor & TTL
c)
mos technology & CMOS technology
d)
none of the mentioned
 | Om Saini answered |
It is an enhancement of the FET devices (field effect) using MOS technology.
In the output characteristics of a MOSFET with low values of Vds, the value of the on-state resistance is- a)Vds/Ig
- b)Vds/Id
- c)0
- d)∞
Correct answer is option 'B'. Can you explain this answer?
In the output characteristics of a MOSFET with low values of Vds, the value of the on-state resistance is
a)
Vds/Ig
b)
Vds/Id
c)
0
d)
∞
 | Ayush Kumar answered |
The o/p characteristics Is a plot of Id verses Vds, which for low values of Vds is almost constant. Hence, the on-state resistance is constant & the slop is its constant value.
The controlling parameter in MOSFET is- a)Vds
- b)Ig
- c)Vgs
- d)Is
Correct answer is option 'B'. Can you explain this answer?
The controlling parameter in MOSFET is
a)
Vds
b)
Ig
c)
Vgs
d)
Is
 | Anshika Khanna answered |
The gate to source voltage is the controlling parameter in a MOSFET.
In which of the following configuration does a MOSFET works as an amplifier?- a)Common Source (CS)
- b)Common Gate (CG)
- c)Common drain (CD)
- d)All of the mentioned
Correct answer is option 'D'. Can you explain this answer?
In which of the following configuration does a MOSFET works as an amplifier?
a)
Common Source (CS)
b)
Common Gate (CG)
c)
Common drain (CD)
d)
All of the mentioned
 | Mira Mishra answered |
There are three basic configurations for connecting the MOSFET as an amplifier. Each of these configurations is obtained by connecting one of the three MOSFET terminals to ground, thus creating a two-port network with the grounded terminal being common to the input and output ports.
Choose the correct statement(s)
i) The gate circuit impedance of MOSFET is higher than that of a BJT
ii) The gate circuit impedance of MOSFET is lower than that of a BJT
iii) The MOSFET has higher switching losses than that of a BJT
iv) The MOSFET has lower switching losses than that of a BJT- a)Both i & ii
- b)Both ii & iv
- c)Both i & iv
- d)Only ii
Correct answer is option 'C'. Can you explain this answer?
Choose the correct statement(s)
i) The gate circuit impedance of MOSFET is higher than that of a BJT
ii) The gate circuit impedance of MOSFET is lower than that of a BJT
iii) The MOSFET has higher switching losses than that of a BJT
iv) The MOSFET has lower switching losses than that of a BJT
i) The gate circuit impedance of MOSFET is higher than that of a BJT
ii) The gate circuit impedance of MOSFET is lower than that of a BJT
iii) The MOSFET has higher switching losses than that of a BJT
iv) The MOSFET has lower switching losses than that of a BJT
a)
Both i & ii
b)
Both ii & iv
c)
Both i & iv
d)
Only ii
| | Athul Banerjee answered |
MOSFET requires gate signals with lower amplitude as compared to BJTs & has lower switching losses.
Neglecting Channel Length Modulation, if the transconductance increases, the input impedance of a follower stage ___________- a)Remans the same
- b)Increases
- c)Decreases
- d)Doubles
Correct answer is option 'A'. Can you explain this answer?
Neglecting Channel Length Modulation, if the transconductance increases, the input impedance of a follower stage ___________
a)
Remans the same
b)
Increases
c)
Decreases
d)
Doubles
 | Jai Kapoor answered |
Introduction:
In electronics, a follower stage, also known as a voltage buffer or unity gain amplifier, is a circuit that has a voltage gain of 1. It is commonly used to isolate different parts of a circuit, provide impedance matching, and prevent loading effects. The input impedance of a follower stage is an important parameter that determines how much the circuit loads the previous stage.
Explanation:
The transconductance of a device is a measure of its ability to convert an input voltage to an output current. In the case of a follower stage, the input impedance is determined by the transconductance of the active device used in the circuit, such as a transistor or an operational amplifier.
When the transconductance increases, it means that the active device has a higher ability to convert an input voltage to an output current. However, this does not directly affect the input impedance of the follower stage. The input impedance is primarily determined by the biasing network and the impedance seen by the input terminals of the active device.
Reasoning:
The input impedance of a follower stage is mainly determined by the biasing network and the impedance seen by the input terminals of the active device. It is not affected by the transconductance of the device itself. Therefore, neglecting channel length modulation, the input impedance of a follower stage remains the same when the transconductance increases.
Conclusion:
In conclusion, neglecting channel length modulation, the input impedance of a follower stage remains the same when the transconductance increases. The input impedance is primarily determined by the biasing network and the impedance seen by the input terminals of the active device. It is important to consider these factors when designing and analyzing follower stages in electronic circuits.
In electronics, a follower stage, also known as a voltage buffer or unity gain amplifier, is a circuit that has a voltage gain of 1. It is commonly used to isolate different parts of a circuit, provide impedance matching, and prevent loading effects. The input impedance of a follower stage is an important parameter that determines how much the circuit loads the previous stage.
Explanation:
The transconductance of a device is a measure of its ability to convert an input voltage to an output current. In the case of a follower stage, the input impedance is determined by the transconductance of the active device used in the circuit, such as a transistor or an operational amplifier.
When the transconductance increases, it means that the active device has a higher ability to convert an input voltage to an output current. However, this does not directly affect the input impedance of the follower stage. The input impedance is primarily determined by the biasing network and the impedance seen by the input terminals of the active device.
Reasoning:
The input impedance of a follower stage is mainly determined by the biasing network and the impedance seen by the input terminals of the active device. It is not affected by the transconductance of the device itself. Therefore, neglecting channel length modulation, the input impedance of a follower stage remains the same when the transconductance increases.
Conclusion:
In conclusion, neglecting channel length modulation, the input impedance of a follower stage remains the same when the transconductance increases. The input impedance is primarily determined by the biasing network and the impedance seen by the input terminals of the active device. It is important to consider these factors when designing and analyzing follower stages in electronic circuits.
Assume µnCox = 100 µA/V2 and supply current is 5mA, what should be the aspect ratio so that a 50 Ω load can be used to give a voltage gain of .25 in C.D. configuration?- a)32.6
- b)50
- c)40
- d)41
Correct answer is option 'A'. Can you explain this answer?
Assume µnCox = 100 µA/V2 and supply current is 5mA, what should be the aspect ratio so that a 50 Ω load can be used to give a voltage gain of .25 in C.D. configuration?
a)
32.6
b)
50
c)
40
d)
41
 | Ravi Singh answered |
The voltage gain is given by RL/(1/gm + RL) where RL is the 50 Ω load. Now, we see that if the voltage gain is .25, gm is 1/175. Now, gm is 
where (W/L) is the aspect ratio, Id is the drain current. We have all the values and the aspect ratio becomes 32.6.
where (W/L) is the aspect ratio, Id is the drain current. We have all the values and the aspect ratio becomes 32.6.At turn-on the initial delay or turn on delay is the time required for the- a)input inductance to charge to the threshold value
- b)input capacitance to charge to the threshold value
- c)input inductance to discharge to the threshold value
- d)input capacitance to discharge to the threshold value
Correct answer is option 'B'. Can you explain this answer?
At turn-on the initial delay or turn on delay is the time required for the
a)
input inductance to charge to the threshold value
b)
input capacitance to charge to the threshold value
c)
input inductance to discharge to the threshold value
d)
input capacitance to discharge to the threshold value
| | Meghana Gupta answered |
Explanation:
The initial delay or turn-on delay refers to the time required for a specific component in a circuit to reach a certain threshold value after the circuit is turned on. In this case, the question is specifically asking about the time required for the input capacitance to charge to the threshold value.
Input Capacitance
The input capacitance is a characteristic of electronic components or circuits that indicates the ability to store an electric charge. It is typically present in devices such as transistors, amplifiers, or integrated circuits.
Threshold Value
The threshold value mentioned in the question refers to a specific voltage level that needs to be reached for the circuit to function properly or for certain operations to occur.
Explanation of Answer
The correct answer is option 'B' - the initial delay or turn-on delay is the time required for the input capacitance to charge to the threshold value. This means that after the circuit is turned on, it takes a certain amount of time for the input capacitance to reach the desired voltage level.
When a circuit is turned on, there is usually a flow of current that charges the various components in the circuit. In the case of the input capacitance, it needs to accumulate a certain amount of charge to reach the threshold voltage. This charging process takes some time, and that time is referred to as the initial delay or turn-on delay.
During this initial delay period, the input capacitance gradually accumulates charge until it reaches the threshold voltage. Once the threshold voltage is reached, the circuit can start functioning as intended.
It's important to note that the other options mentioned in the question are not correct. The input inductance (option 'A') is not directly related to the initial delay or turn-on delay. Similarly, the discharge of the input inductance (option 'C') or the discharge of the input capacitance (option 'D') are not relevant to the initial delay.
In conclusion, the initial delay or turn-on delay is the time required for the input capacitance to charge to the threshold value after the circuit is turned on.
Which of the following is the fastest switching device?- a)JEFT
- b)Triode
- c)MOSFET
- d)BJT
Correct answer is option 'C'. Can you explain this answer?
Which of the following is the fastest switching device?
a)
JEFT
b)
Triode
c)
MOSFET
d)
BJT
 | Yash Patel answered |
MOSFET is the fastest switching device among the given four options.
Consider an ideal MOSFET. If Vgs = 0V, then Id = ?- a)Zero
- b)Maximum
- c)Id(on)
- d)Idd
Correct answer is option 'A'. Can you explain this answer?
Consider an ideal MOSFET. If Vgs = 0V, then Id = ?
a)
Zero
b)
Maximum
c)
Id(on)
d)
Idd
| | Shail Nambiar answered |
Gate current = 0 so device is off (ideally).
The overdrive voltage at which each device must be operating is- a)NMOS = 0.83V and PMOS = 0.48V
- b)NMOS = 0.48V and PMOS = 0.83V
- c)NMOS = 0.24V and PMOS = 0.41V
- d)NMOS = 0.41V and PMOS = 0.24V
Correct answer is option 'B'. Can you explain this answer?
The overdrive voltage at which each device must be operating is
a)
NMOS = 0.83V and PMOS = 0.48V
b)
NMOS = 0.48V and PMOS = 0.83V
c)
NMOS = 0.24V and PMOS = 0.41V
d)
NMOS = 0.41V and PMOS = 0.24V
 | Shivam Ghosh answered |
Explanation:
To understand the answer, we need to understand the concept of overdrive voltage and how it affects the operation of NMOS and PMOS devices in a CMOS circuit.
1. Overdrive Voltage:
Overdrive voltage is the voltage difference between the gate and the threshold voltage of a MOSFET transistor. It determines the level of enhancement or depletion in the channel of the transistor, which in turn affects its performance.
2. NMOS and PMOS Transistors:
In a CMOS circuit, NMOS (n-channel MOSFET) and PMOS (p-channel MOSFET) are complementary devices. They are used together to create logic gates and other digital circuits. The NMOS transistor operates with a positive VGS (gate-to-source voltage), while the PMOS transistor operates with a negative VGS.
3. Operation of NMOS and PMOS:
- NMOS: In an NMOS transistor, when the gate voltage (VGS) is greater than the threshold voltage (Vth), the channel between the source and drain becomes conducting, allowing current to flow. This is called the enhancement mode of operation.
- PMOS: In a PMOS transistor, when the gate voltage (VGS) is less than the threshold voltage (Vth), the channel between the source and drain becomes conducting, allowing current to flow. This is called the enhancement mode of operation.
4. Choosing the Overdrive Voltages:
The overdrive voltage for NMOS and PMOS devices is chosen based on the desired performance and speed of the CMOS circuit. It determines the current flow and the speed of operation.
5. Correct Answer:
Based on the given options, the correct answer is option 'B' (NMOS = 0.48V and PMOS = 0.83V).
The reason for this is that NMOS operates in the enhancement mode when the gate voltage (VGS) is greater than the threshold voltage (Vth). So, the overdrive voltage for NMOS should be positive, which is consistent with option 'B'. On the other hand, PMOS operates in the enhancement mode when the gate voltage (VGS) is less than the threshold voltage (Vth). So, the overdrive voltage for PMOS should be negative, which is not consistent with option 'B'.
Therefore, the correct answer should be option 'A' (NMOS = 0.83V and PMOS = 0.48V).
In summary, option 'B' is not the correct answer as it does not provide the correct overdrive voltage for PMOS. The correct answer is option 'A' (NMOS = 0.83V and PMOS = 0.48V).
To understand the answer, we need to understand the concept of overdrive voltage and how it affects the operation of NMOS and PMOS devices in a CMOS circuit.
1. Overdrive Voltage:
Overdrive voltage is the voltage difference between the gate and the threshold voltage of a MOSFET transistor. It determines the level of enhancement or depletion in the channel of the transistor, which in turn affects its performance.
2. NMOS and PMOS Transistors:
In a CMOS circuit, NMOS (n-channel MOSFET) and PMOS (p-channel MOSFET) are complementary devices. They are used together to create logic gates and other digital circuits. The NMOS transistor operates with a positive VGS (gate-to-source voltage), while the PMOS transistor operates with a negative VGS.
3. Operation of NMOS and PMOS:
- NMOS: In an NMOS transistor, when the gate voltage (VGS) is greater than the threshold voltage (Vth), the channel between the source and drain becomes conducting, allowing current to flow. This is called the enhancement mode of operation.
- PMOS: In a PMOS transistor, when the gate voltage (VGS) is less than the threshold voltage (Vth), the channel between the source and drain becomes conducting, allowing current to flow. This is called the enhancement mode of operation.
4. Choosing the Overdrive Voltages:
The overdrive voltage for NMOS and PMOS devices is chosen based on the desired performance and speed of the CMOS circuit. It determines the current flow and the speed of operation.
5. Correct Answer:
Based on the given options, the correct answer is option 'B' (NMOS = 0.48V and PMOS = 0.83V).
The reason for this is that NMOS operates in the enhancement mode when the gate voltage (VGS) is greater than the threshold voltage (Vth). So, the overdrive voltage for NMOS should be positive, which is consistent with option 'B'. On the other hand, PMOS operates in the enhancement mode when the gate voltage (VGS) is less than the threshold voltage (Vth). So, the overdrive voltage for PMOS should be negative, which is not consistent with option 'B'.
Therefore, the correct answer should be option 'A' (NMOS = 0.83V and PMOS = 0.48V).
In summary, option 'B' is not the correct answer as it does not provide the correct overdrive voltage for PMOS. The correct answer is option 'A' (NMOS = 0.83V and PMOS = 0.48V).
The follower stage is mostly used as a ____________- a)Current source
- b)Buffer stage
- c)Amplifier
- d)Switch
Correct answer is option 'B'. Can you explain this answer?
The follower stage is mostly used as a ____________
a)
Current source
b)
Buffer stage
c)
Amplifier
d)
Switch
 | Tanya Chauhan answered |
The Follower Stage as a Buffer Stage
The follower stage, also known as the voltage follower or emitter follower, is a common configuration used in electronic circuits. It is primarily used as a buffer stage, which means it is employed to isolate or separate one circuit from another. Let's understand why the follower stage is mainly used as a buffer stage.
Introduction to the Follower Stage
The follower stage is a simple configuration that consists of a transistor and load resistor connected in a specific manner. The input signal is applied to the base of the transistor, and the output is taken from the emitter terminal. The emitter is connected directly to the load resistor, which is then connected to the power supply.
Operation and Characteristics
The follower stage operates in such a way that the input voltage is reproduced at the emitter with little or no amplification. This means that the output voltage follows the input voltage, hence the name "follower." The main characteristics of the follower stage are:
1. High input impedance: The base terminal of the transistor has a high input impedance, which means it draws very little current from the source circuit. This allows the follower stage to be connected to a circuit without significantly affecting the source.
2. Low output impedance: The emitter terminal of the transistor has a low output impedance, which means it can drive a load with ease. The follower stage can provide a low impedance output to the next stage of the circuit without introducing significant signal loss.
Buffer Stage Function
A buffer stage is used to overcome impedance mismatching between two circuits. It ensures that the output impedance of the source circuit does not affect the input impedance of the load circuit. In other words, a buffer stage isolates the two circuits and allows them to operate independently without affecting each other.
Application of the Follower Stage as a Buffer Stage
The follower stage's high input impedance and low output impedance make it an ideal choice for a buffer stage. It can be used to connect different circuits that have different impedance levels. The follower stage ensures that the source circuit does not load the preceding circuit and that the load circuit does not affect the preceding stage.
Additionally, the follower stage also provides other advantages as a buffer stage:
- Voltage gain: Although the follower stage does not amplify the signal, it provides voltage gain by maintaining the same voltage level at the input and output. This can be useful when the load circuit requires a higher voltage than the source circuit can provide.
- Signal isolation: The follower stage acts as a barrier between the source and load circuits, preventing any interference or distortion from one circuit affecting the other.
In summary, the follower stage is primarily used as a buffer stage due to its high input impedance, low output impedance, voltage gain, and signal isolation capabilities. It allows for impedance matching between different circuits, ensuring efficient and reliable signal transfer without introducing significant losses or distortions.
The follower stage, also known as the voltage follower or emitter follower, is a common configuration used in electronic circuits. It is primarily used as a buffer stage, which means it is employed to isolate or separate one circuit from another. Let's understand why the follower stage is mainly used as a buffer stage.
Introduction to the Follower Stage
The follower stage is a simple configuration that consists of a transistor and load resistor connected in a specific manner. The input signal is applied to the base of the transistor, and the output is taken from the emitter terminal. The emitter is connected directly to the load resistor, which is then connected to the power supply.
Operation and Characteristics
The follower stage operates in such a way that the input voltage is reproduced at the emitter with little or no amplification. This means that the output voltage follows the input voltage, hence the name "follower." The main characteristics of the follower stage are:
1. High input impedance: The base terminal of the transistor has a high input impedance, which means it draws very little current from the source circuit. This allows the follower stage to be connected to a circuit without significantly affecting the source.
2. Low output impedance: The emitter terminal of the transistor has a low output impedance, which means it can drive a load with ease. The follower stage can provide a low impedance output to the next stage of the circuit without introducing significant signal loss.
Buffer Stage Function
A buffer stage is used to overcome impedance mismatching between two circuits. It ensures that the output impedance of the source circuit does not affect the input impedance of the load circuit. In other words, a buffer stage isolates the two circuits and allows them to operate independently without affecting each other.
Application of the Follower Stage as a Buffer Stage
The follower stage's high input impedance and low output impedance make it an ideal choice for a buffer stage. It can be used to connect different circuits that have different impedance levels. The follower stage ensures that the source circuit does not load the preceding circuit and that the load circuit does not affect the preceding stage.
Additionally, the follower stage also provides other advantages as a buffer stage:
- Voltage gain: Although the follower stage does not amplify the signal, it provides voltage gain by maintaining the same voltage level at the input and output. This can be useful when the load circuit requires a higher voltage than the source circuit can provide.
- Signal isolation: The follower stage acts as a barrier between the source and load circuits, preventing any interference or distortion from one circuit affecting the other.
In summary, the follower stage is primarily used as a buffer stage due to its high input impedance, low output impedance, voltage gain, and signal isolation capabilities. It allows for impedance matching between different circuits, ensuring efficient and reliable signal transfer without introducing significant losses or distortions.
The current gain of a simple CG stage is approximate _______- a)Infinity
- b)unity
- c)twice
- d)0
Correct answer is option 'B'. Can you explain this answer?
The current gain of a simple CG stage is approximate _______
a)
Infinity
b)
unity
c)
twice
d)
0
 | Vihaan Gupta answered |
Simple Common Gate (CG) Stage Current Gain
The current gain of a simple CG stage is approximately unity.
Explanation:
Common Gate (CG) Amplifier Stage:
- In a common gate (CG) amplifier stage, the input signal is applied to the source terminal, and the output is taken from the drain terminal.
- The gate terminal is connected to the ground through a biasing resistor.
Current Gain of a CG Stage:
- The current gain of a CG stage is defined as the ratio of the change in output current to the change in input current.
- In a simple CG stage, the current gain is approximately unity, meaning the output current is almost equal to the input current.
- This is because the input signal is applied to the source terminal, and the output current flows through the drain terminal without much attenuation.
Importance of Unity Current Gain:
- A current gain close to unity is desirable in many amplifier applications as it helps in maintaining the integrity of the input signal without significant loss.
- It also simplifies the analysis and design of the amplifier circuit.
Therefore, the current gain of a simple CG stage is approximately unity, making it an essential characteristic of this amplifier configuration in electronic circuits.
The current gain of a simple CG stage is approximately unity.
Explanation:
Common Gate (CG) Amplifier Stage:
- In a common gate (CG) amplifier stage, the input signal is applied to the source terminal, and the output is taken from the drain terminal.
- The gate terminal is connected to the ground through a biasing resistor.
Current Gain of a CG Stage:
- The current gain of a CG stage is defined as the ratio of the change in output current to the change in input current.
- In a simple CG stage, the current gain is approximately unity, meaning the output current is almost equal to the input current.
- This is because the input signal is applied to the source terminal, and the output current flows through the drain terminal without much attenuation.
Importance of Unity Current Gain:
- A current gain close to unity is desirable in many amplifier applications as it helps in maintaining the integrity of the input signal without significant loss.
- It also simplifies the analysis and design of the amplifier circuit.
Therefore, the current gain of a simple CG stage is approximately unity, making it an essential characteristic of this amplifier configuration in electronic circuits.
If the internal resistance of the current source is finite, what will happen to the voltage gain. for the following C.S. stage, if K is doubled?
- a)The voltage gain reduces by 1/2
- b)The voltage gain remains the same
- c)The voltage gain increases
- d)The voltage gain decreases
Correct answer is option 'B'. Can you explain this answer?
If the internal resistance of the current source is finite, what will happen to the voltage gain. for the following C.S. stage, if K is doubled?
a)
The voltage gain reduces by 1/2
b)
The voltage gain remains the same
c)
The voltage gain increases
d)
The voltage gain decreases
| | Yash Patel answered |
The dependent current source has a variable resistance. If K doubles, the magnitude of current provided by the current source doubles, and thus, the total resistance connected to the source of M1 reduces by 2. By using the expression of voltage gain, 
, we find that a decrease in Rs leads to an increase in the voltage gain.
, we find that a decrease in Rs leads to an increase in the voltage gain. Choose the correct statement- a)MOSFET suffers from secondary breakdown problems
- b)MOSFET has lower switching losses as compared to other devices
- c)MOSFET has high value of on-state resistance as compared to other devices
- d)All of the mentioned
Correct answer is option 'B'. Can you explain this answer?
Choose the correct statement
a)
MOSFET suffers from secondary breakdown problems
b)
MOSFET has lower switching losses as compared to other devices
c)
MOSFET has high value of on-state resistance as compared to other devices
d)
All of the mentioned
| | Prasenjit Yadav answered |
MOSFET has lower switching losses due to its unipolar nature & less turn off time. All of the other statements are false.
In the transfer characteristics of a MOSFET, the threshold voltage is the measure of the- a)minimum voltage to induce a n-channel/p-channel for conduction
- b)minimum voltage till which temperature is constant
- c)minimum voltage to turn off the device
- d)none of the above mentioned is true
Correct answer is option 'A'. Can you explain this answer?
In the transfer characteristics of a MOSFET, the threshold voltage is the measure of the
a)
minimum voltage to induce a n-channel/p-channel for conduction
b)
minimum voltage till which temperature is constant
c)
minimum voltage to turn off the device
d)
none of the above mentioned is true
| | Om Saini answered |
It is the minimum voltage to induce a n-channel/p-channel which will allow the device to conduct electrically through its length.
The arrow on the symbol of MOSFET indicates- a)that it is a N-channel MOSFET
- b)the direction of electrons
- c)the direction of conventional current flow
- d)that it is a P-channel MOSFET
Correct answer is option 'B'. Can you explain this answer?
The arrow on the symbol of MOSFET indicates
a)
that it is a N-channel MOSFET
b)
the direction of electrons
c)
the direction of conventional current flow
d)
that it is a P-channel MOSFET
| | Ayush Kumar answered |
The arrow is to indicate the direction of electrons (opposite to the direction of conventional current flow).
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