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Averages MCQs for UPPSC (UP) Exam

It covers all Important Questions with answers on Averages for the UPPSC (UP) exam. The questions are based on important topics. Details about the questions:
  • Topic: Averages
  • Type of Questions: MCQs with solutions
  • Number of Questions: 33
  • You can attempt them on EduRev to score high in UPPSC (UP) exam.

There are 7 members in a family whose average age is 25 years. Ram who is 12 years old is the second youngest in the family. Find the average age of the family in years just before Ram was born?
  • a)
    15.167
  • b)
    18.2
  • c)
    13
  • d)
    Cannot be determined
Correct answer is option 'D'. Can you explain this answer?

Rajeev Kumar answered
In order to find the average age of the family before Ram was born, we need to know the age of the youngest member of the family. 
Since, we do not know the age of the youngest member, we can not calculate the total age of the family before Ram was born.
Hence, we can not calculate the answer with the given conditions.
Thus, D is the right choice.

Can you explain the answer of this question below:
The average of 20 numbers is zero. Of them, How many of them may be greater than zero , at the most?
  • A:1
  • B:20
  • C:0
  • D:19

The answer is D.

Ishita Das answered
Average of 20 numbers = 0.
 Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).

Can you explain the answer of this question below:
 A car owner buys diesel at Rs.7.50, Rs. 8 and Rs. 8.50 per litre for three successive years. What approximately is the average cost per litre of diesel if he spends Rs. 4000 each year?
  • A:Rs. 8
  • B:Rs. 7.98
  • C:Rs. 6.2
  • D:Rs. 8.1

The answer is B.

Ishani Rane answered
Average cost per litre of petrol = Total amount / Total quantity of petrol

Re. 4000 is spent each year, so total amount spent = 3 * Rs. 4000 = Rs. 12,000

Total quantity of petrol consumed in 3 years = (4000/7.50) + (4000/8) + (4000/8.50) litres

= 533.3 + 500 + 470.6 = 1505

Average cost = Total amount / Total quantity

= 12000/1504 = 7.98

To find quickly, you can take cube root of (7.50 * 8 * 8.50), and it will be slightly less than 8.

The correct option is B.

A batsman makes a score of 87 runs in the 17th inning and thus increases his averages by 3. What is his average after 17th inning?
  • a)
    39
  • b)
    35
  • c)
    42
  • d)
    40.5
Correct answer is option 'A'. Can you explain this answer?

Manoj Ghosh answered
Let the average after 17 innings = x
Total runs scored in 17 innings = 17x
then average after 16 innings = (x-3)
Total runs scored in 16 innings = 16(x-3)
We know that Total runs scored in 16 innings + 87 = Total runs scored in 17 innings
=> 16(x-3) + 87 = 17x
=> 16x - 48 + 87 = 17x
=> x = 39

The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is:
  • a)
    3500
  • b)
    4000
  • c)
    4050
  • d)
    5000
Correct answer is 'B'. Can you explain this answer?

Arya Roy answered
Let monthly income of A = a
monthly income of B = b 
monthly income of C = c
a + b = 2 * 5050 .... (Equation 1)
b + c = 2 * 6250 .... (Equation 2)
a + c = 2 * 5200 .... (Equation 3)
(Equation 1) + (Equation 3) - (Equation 2)
= a + b + a + c - (b + c) = (2 * 5050) + (2 * 5200) - (2 * 6250)
= 2a = 2(5050 + 5200 - 6250)
= a = 4000
i.e., Monthly income of A = 4000

If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, what is the average marks of all the students?
  • a)
    53.23
  • b)
    54.68
  • c)
    51.33
  • d)
    50
Correct answer is 'B'. Can you explain this answer?

Manoj Ghosh answered
Total marks of first batch(55) is= 55*50=2750
Total marks of second batch (60) is= 60*55=3300
Total marks of third batch(45)= 45*60=2700

Total marks of second batch= 2750+3300+2700 = 8750
Total number of Students= 55+60+45 =160
Avg= 8750/160= 54.68

The average number of runs scored by Virat Kohli in four matches is 48. In the fifth match, Kohli scores some runs such that his average now becomes 60. In the 6th innings he scores 12 runs more than his fifth innings and now the average of his last five innings becomes 78. How many runs did he score in his first innings? (He does not remain not out in any of the innings)
  • a)
    30
  • b)
    50
  • c)
    70
  • d)
    90
Correct answer is option 'A'. Can you explain this answer?

Quantronics answered
Runs scored by Kohli in first 4 innings = 48*4 = 192
Average of 5 innings is 60, so total runs scored after 5 innings = 60*5 = 300
Hence runs scored by Kohli in fifth inning = 300 – 192 = 108
It is given that in 6th innings he scores 12 runs more than this, so he must score 120 in the sixth inning. Hence total runs scored in 6 innings = 300+120 = 420
Now average of last five innings is 78, so runs scored in last innings = 390
Hence runs scored in first inning = 420 – 390 = 30.

A student's marks were wrongly entered as 83 instead of 63. Due to that, the average marks for the class got increased by 1/2. What is the number of students in the class?
  • a)
    45
  • b)
    40
  • c)
    35
  • d)
    30
Correct answer is option 'B'. Can you explain this answer?

When a person aged 26 years, is replaced by a person aged 56 years, the total age of the group goes up by 30 years.
Since this leads to an increase in the average by 6 years, it means that there are 30 / 6 = 5 persons in the group.

The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. Find out the average age of the team.
  • a)
    23 years
  • b)
    20 years
  • c)
    24 years
  • d)
    21 years
Correct answer is option 'A'. Can you explain this answer?

Number of members in the team = 11
Let the average age of of the team = x
=> Sum of the ages of all the 11 members of the team / 11 = x
=> Sum of the ages of all the 11 members of the team = 11 x
Age of the captain = 26
Age of the wicket keeper = 26 + 3 = 29
Sum of the ages of 9 members of the team excluding captain and wicket keeper 
= 11x − 26 − 29 =11x − 55
Average age of 9 members of the team excluding captain and wicket keeper
= 11x−55 / 9
Given that
11x−55 / 9 =(x−1)
⇒11x−55=9(x−1)
⇒11x−55=9x−9
⇒2x=46
⇒x = 46/2 = 23 years

The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. What is the present age of the husband?
  • a)
    40
  • b)
    32
  • c)
    28
  • d)
    30
Correct answer is option 'A'. Can you explain this answer?

Arya Roy answered
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child (20 x 2 + 5 x 2) years  = 50 years.
Husband's present age = (90 - 50) years = 40 years.

The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, what is the weight of B?
  • a)
    31 kg
  • b)
    28 kg
  • c)
    32 kg
  • d)
    30 kg
Correct answer is option 'A'. Can you explain this answer?

Kavya Saxena answered
Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 .... (i)
A + B = (40 x 2) = 80 .... (ii)
B + C = (43 x 2) = 86 ....(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)
Subtracting (i) from (iv), we get : B = 31.
 B's weight = 31 kg.

The average weight of a class of 10 students is increased by 2 kg when one student of 30kg left and another student joined. After a few months, this new student left and another student joined whose weight was 10 less than the student who left now. What is the difference between the final and initial averages?
  • a)
    11
  • b)
    1
  • c)
    111
  • d)
    121
Correct answer is option 'B'. Can you explain this answer?

Rajeev Kumar answered
Change in total weight of 10 students = difference in weight of the student who joined and the student
=> weigth of first student who left = 30 + (10×2) = 50
weight of the student who joined last = 50 – 10 = 40...
Thus change in average weight = (40 – 30)/10 = 1...
 

The average of 20 numbers is zero. Of them, How many of them may be greater than zero , at the most?
  • a)
    1
  • b)
    20
  • c)
    0
  • d)
    19
Correct answer is 'D'. Can you explain this answer?

Priyanka Datta answered
Average of 20 numbers = 0.
 Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).

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