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Class 10 NCERT Physics MCQs for UPPSC (UP) Exam
It covers all Important Questions with answers on Class 10 NCERT Physics for the UPPSC (UP) exam. The questions are based on important topics. Details about the questions:- Topic: Class 10 NCERT Physics
- Type of Questions: MCQs with solutions
- Number of Questions: 50
- You can attempt them on EduRev to score high in UPPSC (UP) exam.
To get 2Ω resistance using only 6Ω resistors, the number of them required is- a)2
- b)3
- c)4
- d)6
Correct answer is option 'B'. Can you explain this answer?
To get 2Ω resistance using only 6Ω resistors, the number of them required is
a)
2
b)
3
c)
4
d)
6
 | Avinash Patel answered |
Three resistors of 2Ω is required to get 6Ω because resultant is more than individual so they all must be connected in series.
The effective resistance between A and B is
- a)4Ω
- b)6Ω
- c)May be 10Ω
- d)Must be 10Ω
Correct answer is option 'A'. Can you explain this answer?
The effective resistance between A and B is
a)
4Ω
b)
6Ω
c)
May be 10Ω
d)
Must be 10Ω
 | Gaurav Kumar answered |
6Ω is shorted
as current will pass from wire having no resistance
so effective resistance is 4Ω.
as current will pass from wire having no resistance
so effective resistance is 4Ω.
Speed of light in vacuum is:- a)3 x 108 m/s
- b)3 x 109 m/s
- c)2 x 109 m/s
- d)2 x 1011 m/s
Correct answer is option 'A'. Can you explain this answer?
Speed of light in vacuum is:
a)
3 x 108 m/s
b)
3 x 109 m/s
c)
2 x 109 m/s
d)
2 x 1011 m/s
 | Krishna Iyer answered |
The speed of light in vacuum, commonly denoted c, is a universal physical constant important in many areas of physics. It's exact value is defined as 299 792 458 metres per second ( or approximately, 3*108 m/s)
Calculate the current flows through the 10Ω resistor in the following circuit.
- a)1.2A
- b)0.6A
- c)0.2A
- d)2.0A
Correct answer is option 'B'. Can you explain this answer?
Calculate the current flows through the 10Ω resistor in the following circuit.
a)
1.2A
b)
0.6A
c)
0.2A
d)
2.0A
 | Sun Ray Institute answered |
In parallel, potential difference across each resistor will remain same. So, current through 10Ω resistor
The image formed on the retina of the human eye is- a)virtual and inverted
- b)real and inverted
- c)real and erect
- d)virtual and erect
Correct answer is option 'B'. Can you explain this answer?
The image formed on the retina of the human eye is
a)
virtual and inverted
b)
real and inverted
c)
real and erect
d)
virtual and erect
 | Pooja Shah answered |
Eye lens is convex, in nature. So, image formed by it on the retina is real and inverted.
Stars twinkle due to- a)atmospheric refraction
- b)atmospheric reflection
- c)scattering of light
- d)dispersion of light
Correct answer is option 'A'. Can you explain this answer?
Stars twinkle due to
a)
atmospheric refraction
b)
atmospheric reflection
c)
scattering of light
d)
dispersion of light
 | Deepika Shah answered |
The twinkling of a star is due to atmospheric refraction of starlight. The starlight, on entering the earth’s atmosphere, undergoes refraction continuously before it reaches the earth. The atmospheric refraction occurs in a medium of gradually changing refractive index. Since the atmosphere bends starlight towards the normal, the apparent position of the star is slightly different from its actual position.
If four resistors each of 1Ω are connected in parallel, the effective resistance will be- a)0.5Ω
- b)0.25Ω
- c)4Ω
- d)2Ω
Correct answer is option 'B'. Can you explain this answer?
If four resistors each of 1Ω are connected in parallel, the effective resistance will be
a)
0.5Ω
b)
0.25Ω
c)
4Ω
d)
2Ω
| | Gaurav Kumar answered |
If four resistors each of 1Ω are connected in parallel, the effective resistance will be 0.25Ω..
As, in parralel connection,
1/Reff. = 1/R1 + 1/R2 + ....
The danger signals installed at the top of tall buildings are red in colour. These can be easily seen from a distance because among all other colours, the red light- a)is scattered the most by smoke or fog
- b)is scattered the least by smoke or fog
- c)is absorbed the most by smoke or fog
- d)moves fastest in air
Correct answer is option 'B'. Can you explain this answer?
The danger signals installed at the top of tall buildings are red in colour. These can be easily seen from a distance because among all other colours, the red light
a)
is scattered the most by smoke or fog
b)
is scattered the least by smoke or fog
c)
is absorbed the most by smoke or fog
d)
moves fastest in air
| | Kiran Mehta answered |
Red colour has longer wavelength so least scattered by smoke or fog.
An object 2 cm high is placed at a distance of 15 cm from a concave mirror which produces an inverted image 4 cm high. Find the position of the image.- a)-30 cm
- b)30 cm
- c)40 cm
- d)-40 cm
Correct answer is option 'B'. Can you explain this answer?
An object 2 cm high is placed at a distance of 15 cm from a concave mirror which produces an inverted image 4 cm high. Find the position of the image.
a)
-30 cm
b)
30 cm
c)
40 cm
d)
-40 cm
| | Krishna Iyer answered |
The magnification produced by a concave mirror is given by the formula:
m = -v/u
where, m = magnification v = image distance u = object distance
From the problem, we have: u = -15 cm (since the object is placed in front of the mirror, the distance is negative) m = -4/2 = -2 (since the image is inverted and 4 cm high whereas the object is 2 cm high)
Substituting these values in the magnification formula, we get:
-2 = -v/(-15)
Simplifying, we get:
v = 30 cm
Therefore, the position of the image is 30 cm from the concave mirror.
A student sitting on last bench in a classroom cannot see clearly words written on the blackboard. He is suffering from- a)long sightedness
- b)short sightedness
- c)astigmatism
- d)long sightedness as well as short sightedness
Correct answer is option 'B'. Can you explain this answer?
A student sitting on last bench in a classroom cannot see clearly words written on the blackboard. He is suffering from
a)
long sightedness
b)
short sightedness
c)
astigmatism
d)
long sightedness as well as short sightedness
| | Amit Sharma answered |
A student, who cannot read words written on blackboard from the last bench of his class room, is suffering from the myopia or short-sightedness defect of vision of eye.
Which of the following phenomena of light are involved in the formation of a rainbow ?- a)Reflection, refraction and dispersion
- b)Refraction, dispersion and scattering
- c)Refraction, dispersion and internal reflection
- d)Dispersion, scattering and refraction
Correct answer is option 'C'. Can you explain this answer?
Which of the following phenomena of light are involved in the formation of a rainbow ?
a)
Reflection, refraction and dispersion
b)
Refraction, dispersion and scattering
c)
Refraction, dispersion and internal reflection
d)
Dispersion, scattering and refraction
| | Aditya Shah answered |
Phenomena of refraction, dispersion and internal reflection are involved in the formation of rainbow.
Overloading is due to- a)Insulation of wire is damaged
- b)fault in the appliances
- c)accidental hike in supply voltage
- d)All of the above
Correct answer is option 'D'. Can you explain this answer?
Overloading is due to
a)
Insulation of wire is damaged
b)
fault in the appliances
c)
accidental hike in supply voltage
d)
All of the above
 | Rohit Sharma answered |
Overloading occurs when there is any fault in the appliances or the insulation of wire got damaged. It also occurs when there is sudden hike in supply voltage.
Can you explain the answer of this question below:The combination of a convex lens of power +2D and a concave lens of power -2D, acts as a
- A:
glass slab
- B:
bi-focal lens of power 0 D
- C:
prism
- D:
convex lens of power 0 D.
The answer is a.
The combination of a convex lens of power +2D and a concave lens of power -2D, acts as a
glass slab
bi-focal lens of power 0 D
prism
convex lens of power 0 D.
| | Gaurav Kumar answered |
Net power =0
F=infinity
The emergent ray in the rectangular glass slab is parallel to the incident ray so the focal length of the glass slab is infinite.
F=infinity
The emergent ray in the rectangular glass slab is parallel to the incident ray so the focal length of the glass slab is infinite.
The unit of linear magnification is- a)Dioptre
- b)Metre
- c)Metre per second
- d)It is unitless
Correct answer is option 'D'. Can you explain this answer?
The unit of linear magnification is
a)
Dioptre
b)
Metre
c)
Metre per second
d)
It is unitless
| | Gaurav Kumar answered |
Magnification is thr ratio of size of image to size of object and since it is a ratio of tel similar quantities hence it is unitless.
A wire of resistance 8Ω is bent in the form of a closed circle. What is the effective resistance between the two points A and B, at the ends of any diameter of the circle ?
- a)8Ω
- b)4Ω
- c)2Ω
- d)1Ω
Correct answer is option 'C'. Can you explain this answer?
A wire of resistance 8Ω is bent in the form of a closed circle. What is the effective resistance between the two points A and B, at the ends of any diameter of the circle ?
a)
8Ω
b)
4Ω
c)
2Ω
d)
1Ω
 | Flembe Academy answered |
When a wire of 8Ω resistance is bent in the form of a closed circle, resistance of each half (semicircular) part is 8/2 Ω = 4Ω.
As these two parts are connected in parallel across points A and B, hence effective resistance will be 2Ω.
As these two parts are connected in parallel across points A and B, hence effective resistance will be 2Ω.
Earth wire carries- a)current
- b)voltage
- c)no current
- d)heat
Correct answer is option 'C'. Can you explain this answer?
Earth wire carries
a)
current
b)
voltage
c)
no current
d)
heat
| | Kiran Mehta answered |
A "grounding" wire on the other hand is a safety wire that has intentionally been connected to earth. The grounding wire does not carry electricity under normal circuit operations. It's purpose is to carry electrical current only under short circuit or other conditions that would be potentially dangerous.
The resistance whose V - I graph is given below is
- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
The resistance whose V - I graph is given below is
a)
b)
c)
d)
 | Prachi shukla answered |
Resistance = slope line of V-I graph
When a beam of white light passes through a glass prism, it splits up into seven colours. This phenomenon is due to- a)refraction of light
- b)dispersion of light
- c)diffraction of light
- d)absorption of light
Correct answer is option 'B'. Can you explain this answer?
When a beam of white light passes through a glass prism, it splits up into seven colours. This phenomenon is due to
a)
refraction of light
b)
dispersion of light
c)
diffraction of light
d)
absorption of light
 | Kajal verma answered |
Splitting of white light into its constituent seven colours, while passing through a prism, is on account of dispersion of fight.
If the magnification has a negative sign, the image formed by the concave mirror must be- a)Real and inverted
- b)Virtual and inverted
- c)Virtual and erect
- d)Real and erect
Correct answer is option 'A'. Can you explain this answer?
If the magnification has a negative sign, the image formed by the concave mirror must be
a)
Real and inverted
b)
Virtual and inverted
c)
Virtual and erect
d)
Real and erect
 | Naina Sharma answered |
We know that, if the magnification value is negative sign in the concave mirror, then the image will be real and inverted. Especially, when you come to concave mirror, the images are formed at the left of the mirror. So, it forms real and inverted.
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