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Interest (Simple & Compound) MCQs for UPPSC (UP) Exam

It covers all Important Questions with answers on Interest (Simple & Compound) for the UPPSC (UP) exam. The questions are based on important topics. Details about the questions:
  • Topic: Interest (Simple & Compound)
  • Type of Questions: MCQs with solutions
  • Number of Questions: 40
  • You can attempt them on EduRev to score high in UPPSC (UP) exam.

Can you explain the answer of this question below:
A sum of money amounts to Rs.9800 after 5 years and Rs.12005 after 8 years at the same rate of simple interest. The rate of interest per annum is
  • A:15%
  • B:12%
  • C:8%
  • D:5%

The answer is B.

Arya Roy answered
We can get SI of 3 years = 12005 - 9800 = 2205

SI for 5 years = (2205/3)*5 = 3675 [so that we can get principal amount after deducting SI]

Principal = 12005 - 3675 = 6125 

So Rate = (100*3675)/(6125*5) = 12%

Arun took a loan of Rs. 1400 with simple interest for as many years as the rate of interest. If he paid Rs.686 as interest at the end of the loan period, what was the rate of interest?
  • a)
    8%
  • b)
    6%
  • c)
    4%
  • d)
    7%
Correct answer is option 'D'. Can you explain this answer?

Meghana Mishra answered
Simple Interest (SI) = P N R / 100
P is the Principal loan amount = Rs.1400
N is the number of years of deposit
R is the rate of interest
It is given that the loan period is as many years as the rate of interest.
So, N = R
Interest at the end of the loan period (SI ) = Rs.686
So,
686 = 1400 * R * R /100
R^2 = 686*100 /1400
R^2 = 49
R = 7%

What will be the compound interest on a sum of Rs. 40,000 after 3 years at the rate of 11 p.c.p.a.? 
  • a)
    Rs. 14705.24
  • b)
    Rs. 14602.25
  • c)
    Rs. 14822.26
  • d)
    Rs. 14322.10
Correct answer is option 'A'. Can you explain this answer?

Rhea Reddy answered
Amount after 3 years = P(1 + R/100)T
=> 40000(1 + 11/100)3
=> 40000(111/100)3
=> 40000[(111*111*111)/(100*100*100)]
=> (4*111*111*111)/100 
=> 54705.24
Compound Interest = 54705.24 - 40000 
= Rs. 14705.24

The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is
  • a)
    5
  • b)
    4
  • c)
    6
  • d)
    2
Correct answer is option 'B'. Can you explain this answer?

Anaya Patel answered
P [1 + (r/100)]n  >  2P
⇒ P [1 + (20/100)]n  >  2P
[1 + (2/10) ]n  > 2
[12 / 10]n  > 2
[6/5]n  > 2
{6/5 * 6/5 * 6/5 * 6/5}  >  2
∴ n = 4
 

The Simple interest on a certain sum for 2 years at 20% per annum is Rs. 80. The corresponding compound interest is 
  • a)
    Rs. 66
  • b)
    Rs. 82
  • c)
    Rs. 86
  • d)
    Rs. 88
Correct answer is option 'D'. Can you explain this answer?

Savitri Verma answered
Time =2. rate =20%. p=? SI =80
p=SI*100/R*T p=80×100/20×2
p=200. A=p(1+R/100)^n
A=200(1+20/100)^2
A=200×12×12/100×100
A=288
( CI=A-P)
CI =288-200 = 88

A man took loan from a bank at the rate of 8% p.a. simple interest. After 4 years he had to pay Rs. 6200 interest only for the period. The principal amount borrowed by him was:
  • a)
    Rs.17322
  • b)
    Rs.20245
  • c)
    Rs.18230
  • d)
    Rs.19375
Correct answer is option 'D'. Can you explain this answer?

Aarav Sharma answered
Given:
Rate of interest = 8% p.a.
Interest paid after 4 years = Rs. 6200

To find: Principal amount borrowed

Formula: Simple Interest = (P * R * T) / 100

Where,
P = Principal amount
R = Rate of interest
T = Time (in years)

Calculation:
Let the principal amount be P.

Simple Interest for 4 years = Rs. 6200
=> (P * 8 * 4) / 100 = Rs. 6200
=> 32P = 620000
=> P = Rs. 19375

Therefore, the principal amount borrowed was Rs. 19375.

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