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Ratio & Proportion MCQs for UPPSC (UP) Exam
It covers all Important Questions with answers on Ratio & Proportion for the UPPSC (UP) exam. The questions are based on important topics. Details about the questions:- Topic: Ratio & Proportion
- Type of Questions: MCQs with solutions
- Number of Questions: 50
- You can attempt them on EduRev to score high in UPPSC (UP) exam.
Can you explain the answer of this question below:According to the Boyle’s law, at a constant temperature, pressure of a definite mass of gas is inversely proportional to the volume. If the pressure is reduced by 20%, find the respective change in volume.
- A:
-33.33%
- B:
+25%
- C:
-25%
- D:
+33.33%
The answer is b.
According to the Boyle’s law, at a constant temperature, pressure of a definite mass of gas is inversely proportional to the volume. If the pressure is reduced by 20%, find the respective change in volume.
-33.33%
+25%
-25%
+33.33%
 | Ishan Chaudhary answered |
Point mutation involves- a)Change in single base pair
- b)Deletion
- c)Insertion
- d)Duplication
Correct answer is option 'A'. Can you explain this answer?
Point mutation involves
a)
Change in single base pair
b)
Deletion
c)
Insertion
d)
Duplication
 | Honey answered |
Yes. it involves point mutation as in sickle call anaemia.
Arun has a certain amount of money in the denomination of 1 rupee and 10 rupee notes . T he number of 1 rupee notes multiplied by the number of 10 rupee notes is equal to the total money (in rupees) that he has. What is the total number of ten rupee notes that he can have?- a)11
- b)13
- c)15
- d)None of these
Correct answer is option 'D'. Can you explain this answer?
Arun has a certain amount of money in the denomination of 1 rupee and 10 rupee notes . T he number of 1 rupee notes multiplied by the number of 10 rupee notes is equal to the total money (in rupees) that he has. What is the total number of ten rupee notes that he can have?
a)
11
b)
13
c)
15
d)
None of these
 | Dhruv Verma answered |
Let x = no. of Re 1 notes and y = no. of Rs 10 notes So, xy = x+ 10y ⇒xy = x + 10y Now, go through options
The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:- a)20
- b)30
- c)48
- d)58
Correct answer is option 'B'. Can you explain this answer?
The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
a)
20
b)
30
c)
48
d)
58
 | Aarav Sharma answered |
**Given Information:**
- The sum of three numbers is 98.
- The ratio of the first number to the second number is 2:3.
- The ratio of the second number to the third number is 5:8.
**Let's solve the problem step by step:**
**Step 1:**
Let's assume the three numbers as follows:
- The first number = 2x
- The second number = 3x
- The third number = 8y
**Step 2:**
According to the given information, the sum of the three numbers is 98. Therefore, we can write the equation as:
2x + 3x + 8y = 98
**Step 3:**
Simplifying the equation, we get:
5x + 8y = 98
**Step 4:**
Now, we need to find the values of x and y in order to find the second number.
**Step 5:**
According to the given information, the ratio of the second number to the third number is 5:8. Therefore, we can write the equation as:
3x/8y = 5/8
**Step 6:**
Cross-multiplying the equation, we get:
24x = 40y
**Step 7:**
Simplifying the equation, we get:
3x = 5y
**Step 8:**
Now, we have two equations:
5x + 8y = 98
3x = 5y
**Step 9:**
Substituting the value of 3x from the second equation into the first equation, we get:
5(5y/3) + 8y = 98
25y/3 + 8y = 98
(25y + 24y)/3 = 98
49y/3 = 98
49y = 294
y = 294/49
y = 6
**Step 10:**
Substituting the value of y into the second equation, we get:
3x = 5(6)
3x = 30
x = 30/3
x = 10
**Step 11:**
Now, we can find the second number:
The second number = 3x = 3 * 10 = 30
Therefore, the correct answer is option **B) 30**.
- The sum of three numbers is 98.
- The ratio of the first number to the second number is 2:3.
- The ratio of the second number to the third number is 5:8.
**Let's solve the problem step by step:**
**Step 1:**
Let's assume the three numbers as follows:
- The first number = 2x
- The second number = 3x
- The third number = 8y
**Step 2:**
According to the given information, the sum of the three numbers is 98. Therefore, we can write the equation as:
2x + 3x + 8y = 98
**Step 3:**
Simplifying the equation, we get:
5x + 8y = 98
**Step 4:**
Now, we need to find the values of x and y in order to find the second number.
**Step 5:**
According to the given information, the ratio of the second number to the third number is 5:8. Therefore, we can write the equation as:
3x/8y = 5/8
**Step 6:**
Cross-multiplying the equation, we get:
24x = 40y
**Step 7:**
Simplifying the equation, we get:
3x = 5y
**Step 8:**
Now, we have two equations:
5x + 8y = 98
3x = 5y
**Step 9:**
Substituting the value of 3x from the second equation into the first equation, we get:
5(5y/3) + 8y = 98
25y/3 + 8y = 98
(25y + 24y)/3 = 98
49y/3 = 98
49y = 294
y = 294/49
y = 6
**Step 10:**
Substituting the value of y into the second equation, we get:
3x = 5(6)
3x = 30
x = 30/3
x = 10
**Step 11:**
Now, we can find the second number:
The second number = 3x = 3 * 10 = 30
Therefore, the correct answer is option **B) 30**.
Two-fifth of Anil’s salary is equal of Bhuvan’s salary and seven -ninth of Bhuvan’s salary is equal to Chandra’s salary. The sum of the salary of all of them is Rs 770. Which of the following is the salary of each?- a)300, 225, 250
- b)500, 425, 375
- c)450, 180, 140
- d)520, 610, 475
Correct answer is option 'C'. Can you explain this answer?
Two-fifth of Anil’s salary is equal of Bhuvan’s salary and seven -ninth of Bhuvan’s salary is equal to Chandra’s salary. The sum of the salary of all of them is Rs 770. Which of the following is the salary of each?
a)
300, 225, 250
b)
500, 425, 375
c)
450, 180, 140
d)
520, 610, 475
| | Anaya Patel answered |
A metal trader buys 2 kinds of silver foils, the ratio of their prices being 1:4. He sells the alloy at Rs 90 per kg so that he can make a profit of 20%. If the ratio of their quantities present in a alloy is 6:1 respectively, find the purchase price of the foil present in lesser quantity.- a)Rs 52.5
- b)Rs 55
- c)Rs 47.5
- d)Rs 45
Correct answer is option 'A'. Can you explain this answer?
A metal trader buys 2 kinds of silver foils, the ratio of their prices being 1:4. He sells the alloy at Rs 90 per kg so that he can make a profit of 20%. If the ratio of their quantities present in a alloy is 6:1 respectively, find the purchase price of the foil present in lesser quantity.
a)
Rs 52.5
b)
Rs 55
c)
Rs 47.5
d)
Rs 45
 | Arya Roy answered |
CP = 75
Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins each. The total amount with each of them is Rs 5. The number of coins of two of the three types of coins that Anand has are equal and same is the case for the coins that Bhavana has. If Anand has the maximum possible total number of coins, then find the maximum possible total number of coins that Bhavana can have given that she has fewer coins than Anand.- a)16
- b)12
- c)10
- d)9
Correct answer is option 'B'. Can you explain this answer?
Anand and Bhavana have a few one rupee, 50 paise and 25 paise coins each. The total amount with each of them is Rs 5. The number of coins of two of the three types of coins that Anand has are equal and same is the case for the coins that Bhavana has. If Anand has the maximum possible total number of coins, then find the maximum possible total number of coins that Bhavana can have given that she has fewer coins than Anand.
a)
16
b)
12
c)
10
d)
9
 | Nandita Kaur answered |
Village-chief contribution = Rs 1.2 lakhs, so villagers’ contribution = Rs 1.2 lakhs Now, Go through the options.
Can you explain the answer of this question below:The difference between the two positive numbers is 10 and the ratio between them is 5:3. Find the product of the two numbers.
- A:
375
- B:
325
- C:
275
- D:
125
The answer is a.
The difference between the two positive numbers is 10 and the ratio between them is 5:3. Find the product of the two numbers.
375
325
275
125
 | Subham Basu answered |
Let the nos. be 5x and 3x. then, 5x - 3x = 10 2x = 10, x = 5 Required product = 5x x 3x = 5 x 5 x 3 x 5 = 375
An alloy of manganese, tin and bronze contains 90% bronze, 7% manganese and 3% tin. A second alloy of bronze and tin is melted with the first and the mixture contains 85% of bronze, 5% of manganese and 10% of tin. What is the percentage of bronze in the second alloy?- a)67.5%
- b)72.5%
- c)77.5%
- d)82.5%
Correct answer is 'B'. Can you explain this answer?
An alloy of manganese, tin and bronze contains 90% bronze, 7% manganese and 3% tin. A second alloy of bronze and tin is melted with the first and the mixture contains 85% of bronze, 5% of manganese and 10% of tin. What is the percentage of bronze in the second alloy?
a)
67.5%
b)
72.5%
c)
77.5%
d)
82.5%
 | Sameer Rane answered |
Say M and N are the total volumes of first and second alloys respectively.
Say C, Z and T represent Copper, Tin and Zinc percentages respectively in second alloy.
⇒ C + Z + T = 100 …… Eq.1
Amount of copper in the mixture = 0.90M + (C/100) x N = 0.85 x (M + N)
⇒ 0.05M = (0.85 – C/100) x N
⇒ C = 85 – 5 x (M/N) ….. Eq.2
Amount of Zinc in the mixture = 0.07M + (Z/100) x N = 0.05 x (M + N)
⇒ 0.02M = (0.05 – Z/100) x N
⇒ Z = 5 – 2 x (M/N) ….. Eq.3
Amount of copper in the mixture = 0.03M + (T/100) x N = 0.10 x (M + N)
⇒ –0.07M = (0.10 – T/100) x N
⇒ T = 10 + 7 x (M/N) …… Eq.4
Given Zinc percent in second alloy is Zero
⇒ Z = 0
Eq.3 ⇒ 0 = 5 – 2 x (M/N)
⇒ M/N = 5/2
Substitute M/N = 5/2 in Eq.4
⇒ T = 10 + 7 x (5/2) = 10 + 17.5 = 27.5%
∴ Tin in second alloy = 27.5%
The ratio of the number of boys and girls in a college is 7 : 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio?- a)8 : 9
- b)17 : 18
- c)21 : 22
- d)Cannot be determined
Correct answer is option 'C'. Can you explain this answer?
The ratio of the number of boys and girls in a college is 7 : 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio?
a)
8 : 9
b)
17 : 18
c)
21 : 22
d)
Cannot be determined
| | Ravi Singh answered |
In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?- a)50
- b)100
- c)150
- d)200
Correct answer is option 'C'. Can you explain this answer?
In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?
a)
50
b)
100
c)
150
d)
200
 | Gowri Chakraborty answered |
Let x is the number of 25 paisa coins then 2x and 3x will be for 10 and 5 paisa coins.
Now 30 rupees equal to 30*100 paisa now total paisa equal to x*25+2x*10+3x*5=3000.
60x = 3000.
x = 50.
Now number 5 paisa coin is 3x equal to 3*50 = 150.
Four numbers in the ratio of 1:3:4:7 add up to give a sum of 75. Find the value of the biggest number.- a)42
- b)35
- c)49
- d)63
Correct answer is option 'B'. Can you explain this answer?
Four numbers in the ratio of 1:3:4:7 add up to give a sum of 75. Find the value of the biggest number.
a)
42
b)
35
c)
49
d)
63
 | Kavya Saxena answered |
Method to Solve :
Let 1:3:4:7 be 1x, 3x, 4x, 7x respectively.
1x + 3x + 4x + 7x =7515x = 75
x = 75/15
x = 5
So, 1x = 1*5 = 5
3x = 3*5 = 15
4x = 4*5 = 20
7x = 7*5 = 35
The sum of four numbers is 253. The ratio of the first number to the second number is 2:3. The ratio of the second number to the third number is 5:6. The ratio of the third number to the fourth number is 8:9. What is the average of the second number and the third number?- a)72
- b)132
- c)60
- d)66
Correct answer is option 'D'. Can you explain this answer?
The sum of four numbers is 253. The ratio of the first number to the second number is 2:3. The ratio of the second number to the third number is 5:6. The ratio of the third number to the fourth number is 8:9. What is the average of the second number and the third number?
a)
72
b)
132
c)
60
d)
66
| | Anaya Patel answered |
Let the 1stno. A = X
2nd no.= B , 3rd no.= C , 4th no. = D
A: B =2:3
A/B = 2/3
x/B =2/3
B= 3x/2
B:C=5:6
(3x/2)/ C= 5/6
C=( 6×3x)/2×5= 9x/5
C= 9x/5
C:D= 8:9
9x/5/ D = 8/9
D= (9x×9)/8×5= 81x/40
D= 81x/40
A+B+C+D= 253. (GIVEN)
x+ 3x/2+9x/5+81x/40
Lcm = 40
(40x+ 60x+ 72x+81x)/40= 253
253x= 253×40
X= (253×40)/253= 40
Ist no.(A)= X= 40
2no.(B)= 3x/2=( 3 × 40)/2= 60
3rd no.(C)= 9x/5 = (9×40)/5= 72
4th no.(D)= 81x/40=( 81×40/)/40= 81
Average of numbers= sum of observations/ total no.of observations
Average of 2nd no. & 3rd no.= (60+72)/2= 132/2= 66
2nd no.= B , 3rd no.= C , 4th no. = D
A: B =2:3
A/B = 2/3
x/B =2/3
B= 3x/2
B:C=5:6
(3x/2)/ C= 5/6
C=( 6×3x)/2×5= 9x/5
C= 9x/5
C:D= 8:9
9x/5/ D = 8/9
D= (9x×9)/8×5= 81x/40
D= 81x/40
A+B+C+D= 253. (GIVEN)
x+ 3x/2+9x/5+81x/40
Lcm = 40
(40x+ 60x+ 72x+81x)/40= 253
253x= 253×40
X= (253×40)/253= 40
Ist no.(A)= X= 40
2no.(B)= 3x/2=( 3 × 40)/2= 60
3rd no.(C)= 9x/5 = (9×40)/5= 72
4th no.(D)= 81x/40=( 81×40/)/40= 81
Average of numbers= sum of observations/ total no.of observations
Average of 2nd no. & 3rd no.= (60+72)/2= 132/2= 66
Gandhiji owns cows, some black and some white. He finds that 4 black cows and 3 white cows gave the same amount of milk in 5 days as 3 black cows and 5 white cows gave in 4 days. What is the ratio of milk given by a black cow in a day to that given by a white cow in a day?- a)8 : 5
- b)5 : 8
- c)3 : 5
- d)5 : 3
Correct answer is option 'B'. Can you explain this answer?
Gandhiji owns cows, some black and some white. He finds that 4 black cows and 3 white cows gave the same amount of milk in 5 days as 3 black cows and 5 white cows gave in 4 days. What is the ratio of milk given by a black cow in a day to that given by a white cow in a day?
a)
8 : 5
b)
5 : 8
c)
3 : 5
d)
5 : 3
 | Janhavi Nambiar answered |
Let 1 black cow gives x litres milk in 1 day and 1 white cow gives y litres milk in 1 day. Then 5(4.x + 3y) = 4(3x + 5y) ⇒ 20x + 15y = 12x + 20y
Can you explain the answer of this question below:A and B invest Rs 12,000 and Rs 16,000 respectively in a business. At the year-end, they share the profit in the ratio of 3:1. If A has invested his capital for the whole year, for how many months B has invested his capital?
- A:
4 months
- B:
3 months
- C:
6 months
- D:
8 months
The answer is b.
A and B invest Rs 12,000 and Rs 16,000 respectively in a business. At the year-end, they share the profit in the ratio of 3:1. If A has invested his capital for the whole year, for how many months B has invested his capital?
4 months
3 months
6 months
8 months
 | Saranya Kaur answered |
Let B invested for n months
n = 3
Can you explain the answer of this question below:Two number are in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the ratio 12 : 23. The smaller number is:
- A:
27
- B:
33
- C:
49
- D:
55
The answer is B.
Two number are in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the ratio 12 : 23. The smaller number is:
27
33
49
55
| | Sameer Rane answered |
Let numbers are 3x and 5x.3x - 9 : 5x - 9 :: 12 : 2323*(3x-9) = (5x-9)*12x = 11Second number is 5x.The correct option is B.
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