Page 1 Page 1 CAT 2002 Actual Paper 1 3 2 4 3 4 4 3 5 3 6 1 7 1 8 3 9 3 10 3 11 2 12 4 13 1 14 4 15 1 16 1 17 1 18 4 19 2 20 3 21 3 22 3 23 4 24 1 25 3 26 3 27 2 28 2 29 2 30 2 31 2 32 4 33 4 34 2 35 2 36 2 37 3 38 2 39 1 40 4 41 2 42 2 43 2 44 4 45 3 46 1 47 3 48 2 49 4 50 3 51 3 52 2 53 1 54 2 55 1 56 4 57 4 58 2 59 4 60 4 61 3 62 2 63 4 64 3 65 3 66 2 67 2 68 4 69 3 70 1 71 3 72 2 73 3 74 4 75 4 76 1 77 1 78 4 79 2 80 4 81 4 82 3 83 4 84 3 85 1 86 3 87 *2 88 3 89 2 90 2 91 4 92 4 93 4 94 3 95 4 96 2 97 2 98 4 99 3 100 3 101 3 102 2 103 4 104 2 105 4 106 3 107 1 108 3 109 4 110 2 111 3 112 1 113 4 114 3 115 1 116 4 117 3 118 2 119 3 120 2 121 1 122 4 123 1 124 3 125 1 126 3 127 2 128 3 129 4 130 1 131 1 132 4 133 4 134 4 135 2 136 4 137 2 138 2 139 4 140 4 141 4 142 1 143 1 144 2 145 1 146 3 147 4 148 3 149 1 150 3 Scoring table Section DI 1 to 50 50 QA 51 to 100 50 EU + RC 101 to 150 50 T otal 150 T otal questions T otal attempted T otal correct T otal incorrect Net score Time taken Question number Page 2 Page 1 CAT 2002 Actual Paper 1 3 2 4 3 4 4 3 5 3 6 1 7 1 8 3 9 3 10 3 11 2 12 4 13 1 14 4 15 1 16 1 17 1 18 4 19 2 20 3 21 3 22 3 23 4 24 1 25 3 26 3 27 2 28 2 29 2 30 2 31 2 32 4 33 4 34 2 35 2 36 2 37 3 38 2 39 1 40 4 41 2 42 2 43 2 44 4 45 3 46 1 47 3 48 2 49 4 50 3 51 3 52 2 53 1 54 2 55 1 56 4 57 4 58 2 59 4 60 4 61 3 62 2 63 4 64 3 65 3 66 2 67 2 68 4 69 3 70 1 71 3 72 2 73 3 74 4 75 4 76 1 77 1 78 4 79 2 80 4 81 4 82 3 83 4 84 3 85 1 86 3 87 *2 88 3 89 2 90 2 91 4 92 4 93 4 94 3 95 4 96 2 97 2 98 4 99 3 100 3 101 3 102 2 103 4 104 2 105 4 106 3 107 1 108 3 109 4 110 2 111 3 112 1 113 4 114 3 115 1 116 4 117 3 118 2 119 3 120 2 121 1 122 4 123 1 124 3 125 1 126 3 127 2 128 3 129 4 130 1 131 1 132 4 133 4 134 4 135 2 136 4 137 2 138 2 139 4 140 4 141 4 142 1 143 1 144 2 145 1 146 3 147 4 148 3 149 1 150 3 Scoring table Section DI 1 to 50 50 QA 51 to 100 50 EU + RC 101 to 150 50 T otal 150 T otal questions T otal attempted T otal correct T otal incorrect Net score Time taken Question number Page 2 CAT 2002 Actual Paper 1. 3 Statement I tells us that (1) Ashish is not an engineer, (2) Ashish got more offers than the engineers. Hence, Ashish did not have 0 offers. After this the following table can be achieved. Profession N ames Offers 3 2 1 0 X P rofession CA Ash ish × × × X E ngineer M D D hanraj × × × X E ngineer E conom ist Sam eer × ×× E ngineer × × × From statement IV, Dhanraj is not at 0 and 1. 2. 4 Option (3) is ruled out by statement VII. Option (1) is ruled out by statements VII and VIII. From statement IV, Sandeep had Rs. 30 to start and Daljeet Rs. 20. From statement II, option (2) is not possible as Sandeep was left with Re 1, he spent Rs. 29. But according to (2) he spent Rs. 1.50 more than Daljeet. But Daljeet had only Rs. 20. Hence option (4) is correct. 3. 4 Data insufficient, please check the question. 4. 3 Statements V and VI rule out options (1) and (2). Since contestants from Bangalore and Pune did not come first, school from Hyderabad can come first. Convent is not in Hyderabad which rules out option (4). 5. 3 The only two possible combinations are: Younger Older 24 39 Cubes of natural numbers are 1, 8, 27, 64, ... . Here, 64 and above are not possible as the age will go above 10 years. If younger boy is 2 years old, then older boy is 4 years old. Then, Fatherâ€™s age is 24 years and Motherâ€™s age is 42 21 years. 2 = Also, 24 â€“ 21 = 3 ?Age of younger boy = 2 years 6. 1 Total seats in the hall 200 Seats vacant 20 Total waiting 180 Ladies 72 Seating capacity of flight 2 180 120 3 ×= Number of people in flight A = 100 For flight B = 180 â€“ 100 = 80 Thus, airhostess for A = 80 4 20 = Empty seats in flight B = 120 â€“ 80 = 40 40 : 4 = 10 : 1 7. 1 N W E S S F M oves @ 20 km ph t = ½ hr = 30 m inutes s = 20 × = 10 km ? 30 60 10 km 10 km 20 km 40 km 10 km @ 100 kmph t = 24 minutes s = 40 km ? @ 40 km ph t = 30 minutes s = 20 km ? @ 40 km ph t = 15 minutes s = 10 km ? @ 40 km ph t = 15 minutes s = 10 km ? START IInd Signal IIIrd Signal IVTH Signal Vth Signal FINISH I Signal Note: s = Distance covered; v = Velocity (km/hr) t = Time taken; s = v × t The total distance travelled by the motorist from the starting point till last signal = 10 + 10 + 20 + 40 + 10 = 90 km. 8. 3 N W E S 10 km 10 km 20 km 40 km 10 km S II III IV F 40 km 30 km T I By Pythagorasâ€™ Theorem, SF = 22 ST TF + = 22 40 30 2500 += = 50 km Page 3 Page 1 CAT 2002 Actual Paper 1 3 2 4 3 4 4 3 5 3 6 1 7 1 8 3 9 3 10 3 11 2 12 4 13 1 14 4 15 1 16 1 17 1 18 4 19 2 20 3 21 3 22 3 23 4 24 1 25 3 26 3 27 2 28 2 29 2 30 2 31 2 32 4 33 4 34 2 35 2 36 2 37 3 38 2 39 1 40 4 41 2 42 2 43 2 44 4 45 3 46 1 47 3 48 2 49 4 50 3 51 3 52 2 53 1 54 2 55 1 56 4 57 4 58 2 59 4 60 4 61 3 62 2 63 4 64 3 65 3 66 2 67 2 68 4 69 3 70 1 71 3 72 2 73 3 74 4 75 4 76 1 77 1 78 4 79 2 80 4 81 4 82 3 83 4 84 3 85 1 86 3 87 *2 88 3 89 2 90 2 91 4 92 4 93 4 94 3 95 4 96 2 97 2 98 4 99 3 100 3 101 3 102 2 103 4 104 2 105 4 106 3 107 1 108 3 109 4 110 2 111 3 112 1 113 4 114 3 115 1 116 4 117 3 118 2 119 3 120 2 121 1 122 4 123 1 124 3 125 1 126 3 127 2 128 3 129 4 130 1 131 1 132 4 133 4 134 4 135 2 136 4 137 2 138 2 139 4 140 4 141 4 142 1 143 1 144 2 145 1 146 3 147 4 148 3 149 1 150 3 Scoring table Section DI 1 to 50 50 QA 51 to 100 50 EU + RC 101 to 150 50 T otal 150 T otal questions T otal attempted T otal correct T otal incorrect Net score Time taken Question number Page 2 CAT 2002 Actual Paper 1. 3 Statement I tells us that (1) Ashish is not an engineer, (2) Ashish got more offers than the engineers. Hence, Ashish did not have 0 offers. After this the following table can be achieved. Profession N ames Offers 3 2 1 0 X P rofession CA Ash ish × × × X E ngineer M D D hanraj × × × X E ngineer E conom ist Sam eer × ×× E ngineer × × × From statement IV, Dhanraj is not at 0 and 1. 2. 4 Option (3) is ruled out by statement VII. Option (1) is ruled out by statements VII and VIII. From statement IV, Sandeep had Rs. 30 to start and Daljeet Rs. 20. From statement II, option (2) is not possible as Sandeep was left with Re 1, he spent Rs. 29. But according to (2) he spent Rs. 1.50 more than Daljeet. But Daljeet had only Rs. 20. Hence option (4) is correct. 3. 4 Data insufficient, please check the question. 4. 3 Statements V and VI rule out options (1) and (2). Since contestants from Bangalore and Pune did not come first, school from Hyderabad can come first. Convent is not in Hyderabad which rules out option (4). 5. 3 The only two possible combinations are: Younger Older 24 39 Cubes of natural numbers are 1, 8, 27, 64, ... . Here, 64 and above are not possible as the age will go above 10 years. If younger boy is 2 years old, then older boy is 4 years old. Then, Fatherâ€™s age is 24 years and Motherâ€™s age is 42 21 years. 2 = Also, 24 â€“ 21 = 3 ?Age of younger boy = 2 years 6. 1 Total seats in the hall 200 Seats vacant 20 Total waiting 180 Ladies 72 Seating capacity of flight 2 180 120 3 ×= Number of people in flight A = 100 For flight B = 180 â€“ 100 = 80 Thus, airhostess for A = 80 4 20 = Empty seats in flight B = 120 â€“ 80 = 40 40 : 4 = 10 : 1 7. 1 N W E S S F M oves @ 20 km ph t = ½ hr = 30 m inutes s = 20 × = 10 km ? 30 60 10 km 10 km 20 km 40 km 10 km @ 100 kmph t = 24 minutes s = 40 km ? @ 40 km ph t = 30 minutes s = 20 km ? @ 40 km ph t = 15 minutes s = 10 km ? @ 40 km ph t = 15 minutes s = 10 km ? START IInd Signal IIIrd Signal IVTH Signal Vth Signal FINISH I Signal Note: s = Distance covered; v = Velocity (km/hr) t = Time taken; s = v × t The total distance travelled by the motorist from the starting point till last signal = 10 + 10 + 20 + 40 + 10 = 90 km. 8. 3 N W E S 10 km 10 km 20 km 40 km 10 km S II III IV F 40 km 30 km T I By Pythagorasâ€™ Theorem, SF = 22 ST TF + = 22 40 30 2500 += = 50 km Page 3 CAT 2002 Actual Paper 9. 3 For the case when 1st signal were 1 red and 2 green lights, the surface diagram will be as given below. N W E S 10 km 10 km 20 km 40 km 10 km S II III IV F 50 km T I 40 km TF = 50 km; ST = 40 km Considering the above figure, option (3) is correct, 50 km to the east and 40 km to the north. 10. 3 If the car was heading towards South from the start point, then the surface diagram will be as given below. N W E S 10 km 20 km 40 km 10 km II III IV S I 40 km 10 km F START FINISH 30 km Hence, we can see that option (3) is correct. 11. 2 Total five lie between 10 E and 40 E. Austria, Bulgaria, Libya, Poland, Zambia N N N N S 1 20% 5 = 12. 4 Number of cities starting with consonant and in the northern hemisphere = 10. Number of countries starting with consonant and in the east of the meridien = 13. Hence, option (4) is the correct choice. The difference is 3. 13. 1 Three countries starting with vowels and in southern hemisphere â€” Argentina. Australia and Ecuador and two countries with capitals beginning with vowels â€” Canada and Ghana. 14. 4 Let us consider two cases: (a) If 5 min remaining the score was 0 â€“ 2. Then final score could have been 3 â€“ 3. [Assuming no other Indian scored] (b) But if the score before 5 min was 1 â€“ 3, then final score could have been 4 â€“ 3. 14. 4 From statement A, we know only the number of goals made by India is the last 5 minutes. But, as we donâ€™t know what the opponent team did in the last 5 minutes, we canâ€™t conclude anything. So statement A alone is not sufficient. Similarly, statement B does not talk about the total number of goals scored by India. So statement B is not sufficient. Using both the statements, we have two possibilities: (I) If Korea had scored 3 goals 5 minutes before the end of the match India would have scored 1 goal. In the last 5 minutes as India made 3 goals and Korea on the whole made 3 goals, we can conclude that India had won the game. (II) If Korea had scored 3 goals 5 minutes before the end of the match, India would have scored zero goals. In the last 5 minutes, as India made 3 goals and Korea on the whole made 3 goals, we can say the match was drawn. Hence, we cannot answer the question even boy using both the statements together. 15. 1 From A, if by adding 12 students, the total number of students is divisible by 8. By adding 4 students, it will be divisible by 8. 16. 1 From (A), (x + y) 11 xy ?? + ?? ?? = 4 or (x + y) yx xy ?? + ?? ?? = 4 ? (x + y) 2 = 4xy ? (x â€“ y) 2 = 0 ? x = y ... (i) From (B), (x â€“ 50) 2 = (y â€“ 50) 2 On solving x(x â€“ 100) = y(y â€“ 100) ... (ii) This suggests that the values of x and y can either be 0 or 100. Page 4 Page 1 CAT 2002 Actual Paper 1 3 2 4 3 4 4 3 5 3 6 1 7 1 8 3 9 3 10 3 11 2 12 4 13 1 14 4 15 1 16 1 17 1 18 4 19 2 20 3 21 3 22 3 23 4 24 1 25 3 26 3 27 2 28 2 29 2 30 2 31 2 32 4 33 4 34 2 35 2 36 2 37 3 38 2 39 1 40 4 41 2 42 2 43 2 44 4 45 3 46 1 47 3 48 2 49 4 50 3 51 3 52 2 53 1 54 2 55 1 56 4 57 4 58 2 59 4 60 4 61 3 62 2 63 4 64 3 65 3 66 2 67 2 68 4 69 3 70 1 71 3 72 2 73 3 74 4 75 4 76 1 77 1 78 4 79 2 80 4 81 4 82 3 83 4 84 3 85 1 86 3 87 *2 88 3 89 2 90 2 91 4 92 4 93 4 94 3 95 4 96 2 97 2 98 4 99 3 100 3 101 3 102 2 103 4 104 2 105 4 106 3 107 1 108 3 109 4 110 2 111 3 112 1 113 4 114 3 115 1 116 4 117 3 118 2 119 3 120 2 121 1 122 4 123 1 124 3 125 1 126 3 127 2 128 3 129 4 130 1 131 1 132 4 133 4 134 4 135 2 136 4 137 2 138 2 139 4 140 4 141 4 142 1 143 1 144 2 145 1 146 3 147 4 148 3 149 1 150 3 Scoring table Section DI 1 to 50 50 QA 51 to 100 50 EU + RC 101 to 150 50 T otal 150 T otal questions T otal attempted T otal correct T otal incorrect Net score Time taken Question number Page 2 CAT 2002 Actual Paper 1. 3 Statement I tells us that (1) Ashish is not an engineer, (2) Ashish got more offers than the engineers. Hence, Ashish did not have 0 offers. After this the following table can be achieved. Profession N ames Offers 3 2 1 0 X P rofession CA Ash ish × × × X E ngineer M D D hanraj × × × X E ngineer E conom ist Sam eer × ×× E ngineer × × × From statement IV, Dhanraj is not at 0 and 1. 2. 4 Option (3) is ruled out by statement VII. Option (1) is ruled out by statements VII and VIII. From statement IV, Sandeep had Rs. 30 to start and Daljeet Rs. 20. From statement II, option (2) is not possible as Sandeep was left with Re 1, he spent Rs. 29. But according to (2) he spent Rs. 1.50 more than Daljeet. But Daljeet had only Rs. 20. Hence option (4) is correct. 3. 4 Data insufficient, please check the question. 4. 3 Statements V and VI rule out options (1) and (2). Since contestants from Bangalore and Pune did not come first, school from Hyderabad can come first. Convent is not in Hyderabad which rules out option (4). 5. 3 The only two possible combinations are: Younger Older 24 39 Cubes of natural numbers are 1, 8, 27, 64, ... . Here, 64 and above are not possible as the age will go above 10 years. If younger boy is 2 years old, then older boy is 4 years old. Then, Fatherâ€™s age is 24 years and Motherâ€™s age is 42 21 years. 2 = Also, 24 â€“ 21 = 3 ?Age of younger boy = 2 years 6. 1 Total seats in the hall 200 Seats vacant 20 Total waiting 180 Ladies 72 Seating capacity of flight 2 180 120 3 ×= Number of people in flight A = 100 For flight B = 180 â€“ 100 = 80 Thus, airhostess for A = 80 4 20 = Empty seats in flight B = 120 â€“ 80 = 40 40 : 4 = 10 : 1 7. 1 N W E S S F M oves @ 20 km ph t = ½ hr = 30 m inutes s = 20 × = 10 km ? 30 60 10 km 10 km 20 km 40 km 10 km @ 100 kmph t = 24 minutes s = 40 km ? @ 40 km ph t = 30 minutes s = 20 km ? @ 40 km ph t = 15 minutes s = 10 km ? @ 40 km ph t = 15 minutes s = 10 km ? START IInd Signal IIIrd Signal IVTH Signal Vth Signal FINISH I Signal Note: s = Distance covered; v = Velocity (km/hr) t = Time taken; s = v × t The total distance travelled by the motorist from the starting point till last signal = 10 + 10 + 20 + 40 + 10 = 90 km. 8. 3 N W E S 10 km 10 km 20 km 40 km 10 km S II III IV F 40 km 30 km T I By Pythagorasâ€™ Theorem, SF = 22 ST TF + = 22 40 30 2500 += = 50 km Page 3 CAT 2002 Actual Paper 9. 3 For the case when 1st signal were 1 red and 2 green lights, the surface diagram will be as given below. N W E S 10 km 10 km 20 km 40 km 10 km S II III IV F 50 km T I 40 km TF = 50 km; ST = 40 km Considering the above figure, option (3) is correct, 50 km to the east and 40 km to the north. 10. 3 If the car was heading towards South from the start point, then the surface diagram will be as given below. N W E S 10 km 20 km 40 km 10 km II III IV S I 40 km 10 km F START FINISH 30 km Hence, we can see that option (3) is correct. 11. 2 Total five lie between 10 E and 40 E. Austria, Bulgaria, Libya, Poland, Zambia N N N N S 1 20% 5 = 12. 4 Number of cities starting with consonant and in the northern hemisphere = 10. Number of countries starting with consonant and in the east of the meridien = 13. Hence, option (4) is the correct choice. The difference is 3. 13. 1 Three countries starting with vowels and in southern hemisphere â€” Argentina. Australia and Ecuador and two countries with capitals beginning with vowels â€” Canada and Ghana. 14. 4 Let us consider two cases: (a) If 5 min remaining the score was 0 â€“ 2. Then final score could have been 3 â€“ 3. [Assuming no other Indian scored] (b) But if the score before 5 min was 1 â€“ 3, then final score could have been 4 â€“ 3. 14. 4 From statement A, we know only the number of goals made by India is the last 5 minutes. But, as we donâ€™t know what the opponent team did in the last 5 minutes, we canâ€™t conclude anything. So statement A alone is not sufficient. Similarly, statement B does not talk about the total number of goals scored by India. So statement B is not sufficient. Using both the statements, we have two possibilities: (I) If Korea had scored 3 goals 5 minutes before the end of the match India would have scored 1 goal. In the last 5 minutes as India made 3 goals and Korea on the whole made 3 goals, we can conclude that India had won the game. (II) If Korea had scored 3 goals 5 minutes before the end of the match, India would have scored zero goals. In the last 5 minutes, as India made 3 goals and Korea on the whole made 3 goals, we can say the match was drawn. Hence, we cannot answer the question even boy using both the statements together. 15. 1 From A, if by adding 12 students, the total number of students is divisible by 8. By adding 4 students, it will be divisible by 8. 16. 1 From (A), (x + y) 11 xy ?? + ?? ?? = 4 or (x + y) yx xy ?? + ?? ?? = 4 ? (x + y) 2 = 4xy ? (x â€“ y) 2 = 0 ? x = y ... (i) From (B), (x â€“ 50) 2 = (y â€“ 50) 2 On solving x(x â€“ 100) = y(y â€“ 100) ... (ii) This suggests that the values of x and y can either be 0 or 100. Page 4 CAT 2002 Actual Paper 17. 1 Statement: A. Let the wholesale price is x. Thus, listed prices = 1.2x After a discount of 10%, new price = 0.9 × 1.2x = 1.08x ? 1.08 â€“ x = 10$. Thus, we know x can be found. B. We do not know at what percentage profit, or at what amount of profit the dress was actually sold. 18. 4 A gives 500 as median and B gives 600 as range. A and B together do not give average. Therefore, it cannot be answered from the given statements. 19. 2 From statement A, we know that for all â€“1 < x < 1, we can determine |x â€“ 2| < 1 is not true. Therefore, statement A alone is sufficient. From statement B, â€“1 < x < 3, we cannot determine whether |x â€“ 2| < 1 or not. Therefore, statement B alone is sufficient. 20. 3 From statement A, we cannot find anything. From B alone we cannot find. From A and B, 300 F R X 58 196 x + 196 + 58 = 300. Thus, x can be found. 21. 3 Jagdish (J), Punit (P), Girish (G) (A) J = 2 9 [P + G] P + G + J = 38500 Thus, only J can be found. (B) Similarly, from this only P can be found. Combining we know J, P and G can be found. 22. 3 Emp. numbers 51, 58, 64, 72, 73 earn more than 50 per day in complex operations. Total = 5 23. 4 80% attendance = 80% of 25 = 20 days Emp. numbers 47, 51, 72, 73, 74, 79, 80. Thus, total = 7 24. 1 Emp. No. Earnings No. of daysE/D ED (medium) (medium) 2001151 159.64 13.33 11.97 2001158 109.72 9.61 11.41 2001164 735.22 12.07 60.91 2001171 6.10 4.25 - 2001172 117.46 8.50 13.81 2001179 776.19 19.00 40.85 2001180 1262.79 19.00 66.46 Hence, Emp. number 2001180 earns the maximum earnings per day. 25. 3 Emp. numbers 51, 58, 64, 71, 72 satisfy the condition. [For emp. 64, you see 12 is not the double of 5. And 735 is not even double of 402. Hence, 402 735 . 512 > Note: Emp. numbers 48, 49, 50 are not eligible for earnings. Hence, they are not counted. 26. 3 Total revenue of 1999 = 3374 5% of 3374 = 3374 × 5 100 = 168.7 For 1999, revenue for Spain is 55, Rest of Latin America is 115, North Sea is 140, Rest of the world is 91. So total four operations of the company accounted for less than 5% of the total revenue earned in the year 1999. 27. 2 The language in the question is ambiguous. Taking the question to be more than 200% growth in revenue, the revenue in 2000 will be more than 3 times that in 1999. Hence, (2) is the answer. Taking the revenue in 2000 to be more than 200% of that in 1999, the revenue in 2000 should be more than twice of that in 1999. Then there will be 4 operations. 28. 2 Four operations, as given below: (1) North Africa and Middle-East (2) Argentina (3) Rest of Latin America (4) Far East have registered yearly increase in income before taxes and charges from 1998 to 2000. 29. 2 Percentage increase in net income before tax and charges for total world (1998-99) = 1375 248 100 248 - × = 454.4% Spain is making loss. Page 5 Page 1 CAT 2002 Actual Paper 1 3 2 4 3 4 4 3 5 3 6 1 7 1 8 3 9 3 10 3 11 2 12 4 13 1 14 4 15 1 16 1 17 1 18 4 19 2 20 3 21 3 22 3 23 4 24 1 25 3 26 3 27 2 28 2 29 2 30 2 31 2 32 4 33 4 34 2 35 2 36 2 37 3 38 2 39 1 40 4 41 2 42 2 43 2 44 4 45 3 46 1 47 3 48 2 49 4 50 3 51 3 52 2 53 1 54 2 55 1 56 4 57 4 58 2 59 4 60 4 61 3 62 2 63 4 64 3 65 3 66 2 67 2 68 4 69 3 70 1 71 3 72 2 73 3 74 4 75 4 76 1 77 1 78 4 79 2 80 4 81 4 82 3 83 4 84 3 85 1 86 3 87 *2 88 3 89 2 90 2 91 4 92 4 93 4 94 3 95 4 96 2 97 2 98 4 99 3 100 3 101 3 102 2 103 4 104 2 105 4 106 3 107 1 108 3 109 4 110 2 111 3 112 1 113 4 114 3 115 1 116 4 117 3 118 2 119 3 120 2 121 1 122 4 123 1 124 3 125 1 126 3 127 2 128 3 129 4 130 1 131 1 132 4 133 4 134 4 135 2 136 4 137 2 138 2 139 4 140 4 141 4 142 1 143 1 144 2 145 1 146 3 147 4 148 3 149 1 150 3 Scoring table Section DI 1 to 50 50 QA 51 to 100 50 EU + RC 101 to 150 50 T otal 150 T otal questions T otal attempted T otal correct T otal incorrect Net score Time taken Question number Page 2 CAT 2002 Actual Paper 1. 3 Statement I tells us that (1) Ashish is not an engineer, (2) Ashish got more offers than the engineers. Hence, Ashish did not have 0 offers. After this the following table can be achieved. Profession N ames Offers 3 2 1 0 X P rofession CA Ash ish × × × X E ngineer M D D hanraj × × × X E ngineer E conom ist Sam eer × ×× E ngineer × × × From statement IV, Dhanraj is not at 0 and 1. 2. 4 Option (3) is ruled out by statement VII. Option (1) is ruled out by statements VII and VIII. From statement IV, Sandeep had Rs. 30 to start and Daljeet Rs. 20. From statement II, option (2) is not possible as Sandeep was left with Re 1, he spent Rs. 29. But according to (2) he spent Rs. 1.50 more than Daljeet. But Daljeet had only Rs. 20. Hence option (4) is correct. 3. 4 Data insufficient, please check the question. 4. 3 Statements V and VI rule out options (1) and (2). Since contestants from Bangalore and Pune did not come first, school from Hyderabad can come first. Convent is not in Hyderabad which rules out option (4). 5. 3 The only two possible combinations are: Younger Older 24 39 Cubes of natural numbers are 1, 8, 27, 64, ... . Here, 64 and above are not possible as the age will go above 10 years. If younger boy is 2 years old, then older boy is 4 years old. Then, Fatherâ€™s age is 24 years and Motherâ€™s age is 42 21 years. 2 = Also, 24 â€“ 21 = 3 ?Age of younger boy = 2 years 6. 1 Total seats in the hall 200 Seats vacant 20 Total waiting 180 Ladies 72 Seating capacity of flight 2 180 120 3 ×= Number of people in flight A = 100 For flight B = 180 â€“ 100 = 80 Thus, airhostess for A = 80 4 20 = Empty seats in flight B = 120 â€“ 80 = 40 40 : 4 = 10 : 1 7. 1 N W E S S F M oves @ 20 km ph t = ½ hr = 30 m inutes s = 20 × = 10 km ? 30 60 10 km 10 km 20 km 40 km 10 km @ 100 kmph t = 24 minutes s = 40 km ? @ 40 km ph t = 30 minutes s = 20 km ? @ 40 km ph t = 15 minutes s = 10 km ? @ 40 km ph t = 15 minutes s = 10 km ? START IInd Signal IIIrd Signal IVTH Signal Vth Signal FINISH I Signal Note: s = Distance covered; v = Velocity (km/hr) t = Time taken; s = v × t The total distance travelled by the motorist from the starting point till last signal = 10 + 10 + 20 + 40 + 10 = 90 km. 8. 3 N W E S 10 km 10 km 20 km 40 km 10 km S II III IV F 40 km 30 km T I By Pythagorasâ€™ Theorem, SF = 22 ST TF + = 22 40 30 2500 += = 50 km Page 3 CAT 2002 Actual Paper 9. 3 For the case when 1st signal were 1 red and 2 green lights, the surface diagram will be as given below. N W E S 10 km 10 km 20 km 40 km 10 km S II III IV F 50 km T I 40 km TF = 50 km; ST = 40 km Considering the above figure, option (3) is correct, 50 km to the east and 40 km to the north. 10. 3 If the car was heading towards South from the start point, then the surface diagram will be as given below. N W E S 10 km 20 km 40 km 10 km II III IV S I 40 km 10 km F START FINISH 30 km Hence, we can see that option (3) is correct. 11. 2 Total five lie between 10 E and 40 E. Austria, Bulgaria, Libya, Poland, Zambia N N N N S 1 20% 5 = 12. 4 Number of cities starting with consonant and in the northern hemisphere = 10. Number of countries starting with consonant and in the east of the meridien = 13. Hence, option (4) is the correct choice. The difference is 3. 13. 1 Three countries starting with vowels and in southern hemisphere â€” Argentina. Australia and Ecuador and two countries with capitals beginning with vowels â€” Canada and Ghana. 14. 4 Let us consider two cases: (a) If 5 min remaining the score was 0 â€“ 2. Then final score could have been 3 â€“ 3. [Assuming no other Indian scored] (b) But if the score before 5 min was 1 â€“ 3, then final score could have been 4 â€“ 3. 14. 4 From statement A, we know only the number of goals made by India is the last 5 minutes. But, as we donâ€™t know what the opponent team did in the last 5 minutes, we canâ€™t conclude anything. So statement A alone is not sufficient. Similarly, statement B does not talk about the total number of goals scored by India. So statement B is not sufficient. Using both the statements, we have two possibilities: (I) If Korea had scored 3 goals 5 minutes before the end of the match India would have scored 1 goal. In the last 5 minutes as India made 3 goals and Korea on the whole made 3 goals, we can conclude that India had won the game. (II) If Korea had scored 3 goals 5 minutes before the end of the match, India would have scored zero goals. In the last 5 minutes, as India made 3 goals and Korea on the whole made 3 goals, we can say the match was drawn. Hence, we cannot answer the question even boy using both the statements together. 15. 1 From A, if by adding 12 students, the total number of students is divisible by 8. By adding 4 students, it will be divisible by 8. 16. 1 From (A), (x + y) 11 xy ?? + ?? ?? = 4 or (x + y) yx xy ?? + ?? ?? = 4 ? (x + y) 2 = 4xy ? (x â€“ y) 2 = 0 ? x = y ... (i) From (B), (x â€“ 50) 2 = (y â€“ 50) 2 On solving x(x â€“ 100) = y(y â€“ 100) ... (ii) This suggests that the values of x and y can either be 0 or 100. Page 4 CAT 2002 Actual Paper 17. 1 Statement: A. Let the wholesale price is x. Thus, listed prices = 1.2x After a discount of 10%, new price = 0.9 × 1.2x = 1.08x ? 1.08 â€“ x = 10$. Thus, we know x can be found. B. We do not know at what percentage profit, or at what amount of profit the dress was actually sold. 18. 4 A gives 500 as median and B gives 600 as range. A and B together do not give average. Therefore, it cannot be answered from the given statements. 19. 2 From statement A, we know that for all â€“1 < x < 1, we can determine |x â€“ 2| < 1 is not true. Therefore, statement A alone is sufficient. From statement B, â€“1 < x < 3, we cannot determine whether |x â€“ 2| < 1 or not. Therefore, statement B alone is sufficient. 20. 3 From statement A, we cannot find anything. From B alone we cannot find. From A and B, 300 F R X 58 196 x + 196 + 58 = 300. Thus, x can be found. 21. 3 Jagdish (J), Punit (P), Girish (G) (A) J = 2 9 [P + G] P + G + J = 38500 Thus, only J can be found. (B) Similarly, from this only P can be found. Combining we know J, P and G can be found. 22. 3 Emp. numbers 51, 58, 64, 72, 73 earn more than 50 per day in complex operations. Total = 5 23. 4 80% attendance = 80% of 25 = 20 days Emp. numbers 47, 51, 72, 73, 74, 79, 80. Thus, total = 7 24. 1 Emp. No. Earnings No. of daysE/D ED (medium) (medium) 2001151 159.64 13.33 11.97 2001158 109.72 9.61 11.41 2001164 735.22 12.07 60.91 2001171 6.10 4.25 - 2001172 117.46 8.50 13.81 2001179 776.19 19.00 40.85 2001180 1262.79 19.00 66.46 Hence, Emp. number 2001180 earns the maximum earnings per day. 25. 3 Emp. numbers 51, 58, 64, 71, 72 satisfy the condition. [For emp. 64, you see 12 is not the double of 5. And 735 is not even double of 402. Hence, 402 735 . 512 > Note: Emp. numbers 48, 49, 50 are not eligible for earnings. Hence, they are not counted. 26. 3 Total revenue of 1999 = 3374 5% of 3374 = 3374 × 5 100 = 168.7 For 1999, revenue for Spain is 55, Rest of Latin America is 115, North Sea is 140, Rest of the world is 91. So total four operations of the company accounted for less than 5% of the total revenue earned in the year 1999. 27. 2 The language in the question is ambiguous. Taking the question to be more than 200% growth in revenue, the revenue in 2000 will be more than 3 times that in 1999. Hence, (2) is the answer. Taking the revenue in 2000 to be more than 200% of that in 1999, the revenue in 2000 should be more than twice of that in 1999. Then there will be 4 operations. 28. 2 Four operations, as given below: (1) North Africa and Middle-East (2) Argentina (3) Rest of Latin America (4) Far East have registered yearly increase in income before taxes and charges from 1998 to 2000. 29. 2 Percentage increase in net income before tax and charges for total world (1998-99) = 1375 248 100 248 - × = 454.4% Spain is making loss. Page 5 CAT 2002 Actual Paper Percentage increase for North Africa and Middle-East 341 111 111 - × 100 = 207.2% Percentage increase for Argentina 838 94 100 94 - =× = 791.5% From the table one can directly say that there is no operation other than Argentina, whose percentage increase in net income before taxes and charges is higher than the average (world). 30. 2 Statement 1 is obviously wrong. (2) 54 20 65 52 > . Hence, (2) is correct. (3) 500 61 1168 187 > . Hence (3) is wrong. 31. 2 Profitability of North Africa and Middle-East in 2000 = 356 530 = 0.67 Profitability of Spain in 2000 = 225 43 = 5.23 Profitability of Rest of Latin America in 2000 = 169 252 , i.e. < 1. Profitability of Far East in 2000 = 189 311 = < 1 32. 4 Except Rest of Latin America and Rest of the World all the operations are greater than 2. 33. 4 Options (1), (2) and (3), are ruled out. So the correct option is (4). 34. 2 It can be easily observed from the two charts that Switzerlandâ€™s ratio of chart 1 to chart 2 is 20 11 has the highest price per unit kilogram for its supply. Finding the ratio of the value and quantity is enough to reach the solution. 35. 2 Total value of distribution to Turkey is 16% of 5760 million Euro. Total quantity of distribution to Turkey is 15% of 1.055 million tonnes. So the average price in Euro per kilogram for Turkey is 16 5760 100 5.6 15 1055 100 ?? × ?? ?? ?? × ?? ?? 36. 2 BC ? AC ? AAC = 0 37. 3 095.2 BD AE AAB ?????? ? ?Least cost of sending one unit from any refinery to AAB = 0 + 95.2 = 95.2. 38. 2 BB ? AB ? AAG = 311.1 Same as above. 39. 1 First we will have to check the minimum cost for receiving at AAA. This is 0 for AE. But, BB to AE is very high. Next is AC [314.5]. BB to AC is 451.1. After AC, the others are high. Hence, 314.5 + 451.1 = 765.6 is the least cost. 40. 4 Number of refineries = 6 Number of depots = 7 Number of districts = 9 Therefore, number of possible ways to send petrol from any refinery to any district is 6 × 7 × 9 = 378. 41. 2 The highest cost is for the route BE ? AE ? AAH = 2193.0 For questions 42 to 47: Position of States (Rank) 96-97 97-98 98-99 99-00 00-01 1 MAMA MAMA MA 2TN TN TN TN TN 3GU AP AP AP AP 4AP GU GUGU UP changed 5 KAUP UP UPGU tw ice 6 UPKA KAKA KA 7WB WB WBWB WB } Year 42. 2 From above table, we can conclude that option (2) is correct. 43. 2 On referring to the table, we can see that UP is the state which changed its relative ranking most number of times. 44. 4 We can say directly on observing the graph that the sales tax revenue collections for AP has more than doubled from 1997 to 2001. 45. 3 Growth rate of tax revenue can be calculated as: (Sales tax revenue of correct year â€“ Sales tax revenue of previous year) For year 1997-98 7826 7290 7826 - = 0.068 For year 1998-99 8067 7826 7826 - = 0.030Read More

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### CAT Past Year Question Paper - 2001

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### CAT Past Year Question Paper Solution - 1999.

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- CAT Past Year Question Paper - 2002
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